Long Division practice worksheet with 3-digit dividends and no remainders.

Let’s solve each long division problem step by step. All problems are 3-digit dividends divided by single-digit divisors, and the worksheet says “No Remainder” — so every answer should be a whole number.

We’ll go one by one:

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Problem 1: 297 ÷ 3

- 3 goes into 2? No → look at 29.
- 3 × 9 = 27 → write 9 above the 9 in 297.
- Subtract: 29 - 27 = 2.
- Bring down the 7 → makes 27.
- 3 × 9 = 27 → write 9 above the 7.
- Subtract: 27 - 27 = 0.
✔ Answer: 99

*(Already filled in correctly on the sheet.)*

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Problem 2: 800 ÷ 5

- 5 into 8 → 1 time (5×1=5), remainder 3.
- Write 1 above the 8.
- Bring down 0 → 30.
- 5 into 30 → 6 times (5×6=30).
- Write 6 above the first 0.
- Bring down last 0 → 0.
- 5 into 0 → 0.
✔ Answer: 160

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Problem 3: 841 ÷ ? Wait — divisor is missing! Looking at the image, it shows “)841” with no number before the parenthesis. But since this is a standard worksheet, and looking at pattern, likely it’s ÷ 7? Let me check: 841 ÷ 7?

Wait — actually, let’s double-check the image description. The user said “Long Division Type I (No Remainder)” and all others have divisors shown. Problem 3 has “)841” — but in the original image, perhaps the divisor is written to the left? Since we can’t see it clearly from text, but based on common worksheets and that 841 is 29², maybe it’s ÷ 29? But that’s not single digit.

Wait — re-examining: In the image transcription, problem 3 is written as “)841” — but in the actual image (which I’m simulating solving), the divisor is probably 7, because 841 ÷ 7 = 120.14… not whole. Hmm.

Actually — let’s think differently. Maybe it’s ÷ 1? No, too easy. Or perhaps it’s a typo? Wait — another idea: 841 ÷ 29 = 29 — but again, not single digit.

Hold on — let’s look at problem 4: 984 ÷ ? — same issue? No, in the image, problem 4 is “)984” — wait, no — looking back at the user’s text representation:

In the user’s message, they wrote:

> ③ )841
> ④ )984
> etc.

But in the actual image (as implied by the structure), the divisor is written *before* the parenthesis. For example, problem 1 is “3)297”, problem 2 is “5)800”.

So for problem 3, if it’s written as “)841”, that might mean the divisor is missing in transcription — but in reality, in the image, it’s likely 7) or 9)? Let’s test:

Try 841 ÷ 7 = 120.14… no
841 ÷ 9 = 93.44… no
841 ÷ 1 = 841 — possible, but unlikely
Wait — 841 ÷ 29 = 29 — but 29 is two digits.

This is confusing. Perhaps there’s a mistake in my assumption.

Wait — let’s look at problem 6: “)592” — again, no divisor? That can’t be right.

I think the issue is that in the user’s text representation, the divisors are omitted for some problems due to formatting. But in the actual image, they are present.

Since this is a standard 3rd/4th grade worksheet titled “3 Digit Dividends Type I (No Remainder)”, and given the patterns, let’s assume the divisors are as follows (based on common problems and ensuring no remainder):

Let me list them properly by checking what divides evenly:

Problem 3: 841 — factors? 841 = 29 × 29 → only divisible by 1, 29, 841. So unless divisor is 29 (not single digit), this doesn’t fit. Maybe it’s 840? But it says 841.

Wait — perhaps it’s ÷ 1? Then answer is 841. But that seems odd.

Alternatively, maybe it’s a misprint, and it’s supposed to be 840 ÷ 7 = 120? But the problem says 841.

Let’s skip and come back.

Problem 4: 984 ÷ ? — let’s try ÷ 6: 984 ÷ 6 = 164 → yes! 6×164=984. Good.

Problem 5: 545 ÷ ? — try ÷ 5: 545 ÷ 5 = 109 → yes.

Problem 6: 592 ÷ ? — try ÷ 8: 592 ÷ 8 = 74 → yes.

Problem 7: 696 ÷ ? — try ÷ 6: 696 ÷ 6 = 116 → yes.

Problem 8: 254 ÷ ? — try ÷ 2: 254 ÷ 2 = 127 → yes.

Problem 9: 986 ÷ ? — try ÷ 2: 986 ÷ 2 = 493 → yes.

Now back to problem 3: 841 — if we must have no remainder and single-digit divisor, none work except 1. But 1 is trivial. Alternatively, perhaps it’s 846? 846 ÷ 9 = 94. But it says 841.

Wait — another thought: maybe problem 3 is ÷ 29 but that’s not single digit. Or perhaps the dividend is 840? Let’s assume for now that it’s a typo and it’s 840 ÷ 7 = 120. But the problem says 841.

Perhaps in the image, the divisor is 1? Let’s go with that for now.

But let’s verify with problem 3 being 841 ÷ 1 = 841.

Similarly, problem 4: 984 ÷ 6 = 164 (as above)

Problem 5: 545 ÷ 5 = 109

Problem 6: 592 ÷ 8 = 74

Problem 7: 696 ÷ 6 = 116

Problem 8: 254 ÷ 2 = 127

Problem 9: 986 ÷ 2 = 493

Now for problem 3: if we take 841 ÷ 1 = 841, it works, but let’s see if there’s another possibility. What if it’s 841 ÷ 29? But 29 is not single digit. The worksheet says “3 Digit Dividends” but doesn’t specify divisor size, though typically in such sheets, divisors are single-digit.

Looking at problem 1: divisor 3, problem 2: divisor 5, so likely single-digit.

Another idea: perhaps problem 3 is 841 ÷ 7? 7*120=840, so 841-840=1 — remainder 1, but worksheet says "No Remainder". So not valid.

Unless... wait, 841 is 29^2, so only divisors are 1,29,841. So only single-digit divisor is 1.

So I'll go with 841 ÷ 1 = 841.

But let's confirm the others:

Problem 4: 984 ÷ 6 = 164 → 6*164=984 ✓

Problem 5: 545 ÷ 5 = 109 → 5*109=545 ✓

Problem 6: 592 ÷ 8 = 74 → 8*74=592 ✓

Problem 7: 696 ÷ 6 = 116 → 6*116=696 ✓

Problem 8: 254 ÷ 2 = 127 → 2*127=254 ✓

Problem 9: 986 ÷ 2 = 493 → 2*493=986 ✓

All good.

For problem 3, since 841 ÷ 1 = 841, and 1 is a single-digit divisor, it fits, even if trivial.

Perhaps in the image, the divisor is written as "1)" but was missed in transcription.

So final answers:

1. 99 (given)
2. 160
3. 841
4. 164
5. 109
6. 74
7. 116
8. 127
9. 493

But let's double-check problem 3: is there any single-digit divisor other than 1 that divides 841? 841 ÷ 3 = 280.333... no; ÷7=120.142... no; ÷9=93.444... no. So only 1.

Perhaps the problem is 846? 846 ÷ 9 = 94, which is nice. But the problem says 841.

Given the constraints, I'll proceed with 841 ÷ 1 = 841.

Final Answer:

1. 99
2. 160
3. 841
4. 164
5. 109
6. 74
7. 116
8. 127
9. 493