This worksheet challenges students to isolate specific variables within complex algebraic and physics formulas.
Math worksheet for solving variables by rearranging algebraic equations.
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Step-by-step solution for: Manipulating Equations in term of a given Variable worksheets library
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Show Answer Key & Explanations
Step-by-step solution for: Manipulating Equations in term of a given Variable worksheets library
To solve the given equations for different unknowns, we will rearrange each equation step by step. Let's go through each problem:
---
#### Solve for \( D \):
\[ v = \frac{D}{T} \]
Multiply both sides by \( T \):
\[ D = vT \]
#### Solve for \( T \):
\[ v = \frac{D}{T} \]
Multiply both sides by \( T \):
\[ vT = D \]
Divide both sides by \( v \):
\[ T = \frac{D}{v} \]
Answers:
- \( D = vT \)
- \( T = \frac{D}{v} \)
---
#### Solve for \( B \):
\[ A = BC + D \]
Subtract \( D \) from both sides:
\[ A - D = BC \]
Divide both sides by \( C \):
\[ B = \frac{A - D}{C} \]
#### Solve for \( C \):
\[ A = BC + D \]
Subtract \( D \) from both sides:
\[ A - D = BC \]
Divide both sides by \( B \):
\[ C = \frac{A - D}{B} \]
#### Solve for \( D \):
\[ A = BC + D \]
Subtract \( BC \) from both sides:
\[ D = A - BC \]
Answers:
- \( B = \frac{A - D}{C} \)
- \( C = \frac{A - D}{B} \)
- \( D = A - BC \)
---
#### Solve for \( A \):
\[ \frac{A}{B} = \frac{C}{D} \]
Multiply both sides by \( B \):
\[ A = \frac{BC}{D} \]
#### Solve for \( B \):
\[ \frac{A}{B} = \frac{C}{D} \]
Multiply both sides by \( B \):
\[ A = \frac{BC}{D} \]
Multiply both sides by \( D \):
\[ AD = BC \]
Divide both sides by \( C \):
\[ B = \frac{AD}{C} \]
#### Solve for \( C \):
\[ \frac{A}{B} = \frac{C}{D} \]
Multiply both sides by \( D \):
\[ \frac{AD}{B} = C \]
\[ C = \frac{AD}{B} \]
#### Solve for \( D \):
\[ \frac{A}{B} = \frac{C}{D} \]
Multiply both sides by \( D \):
\[ \frac{AD}{B} = C \]
Multiply both sides by \( B \):
\[ AD = BC \]
Divide both sides by \( A \):
\[ D = \frac{BC}{A} \]
Answers:
- \( A = \frac{BC}{D} \)
- \( B = \frac{AD}{C} \)
- \( C = \frac{AD}{B} \)
- \( D = \frac{BC}{A} \)
---
#### Solve for \( V \):
\[ A = V^2 \cdot 2D \]
Divide both sides by \( 2D \):
\[ \frac{A}{2D} = V^2 \]
Take the square root of both sides:
\[ V = \sqrt{\frac{A}{2D}} \]
#### Solve for \( D \):
\[ A = V^2 \cdot 2D \]
Divide both sides by \( 2V^2 \):
\[ D = \frac{A}{2V^2} \]
Answers:
- \( V = \sqrt{\frac{A}{2D}} \)
- \( D = \frac{A}{2V^2} \)
---
#### Solve for \( C \):
\[ E = M \cdot C^2 \]
Divide both sides by \( M \):
\[ \frac{E}{M} = C^2 \]
Take the square root of both sides:
\[ C = \sqrt{\frac{E}{M}} \]
#### Solve for \( M \):
\[ E = M \cdot C^2 \]
Divide both sides by \( C^2 \):
\[ M = \frac{E}{C^2} \]
Answers:
- \( C = \sqrt{\frac{E}{M}} \)
- \( M = \frac{E}{C^2} \)
---
#### Solve for \( A \):
\[ V = \sqrt{2AS} \]
Square both sides:
\[ V^2 = 2AS \]
Divide both sides by \( 2S \):
\[ A = \frac{V^2}{2S} \]
#### Solve for \( S \):
\[ V = \sqrt{2AS} \]
Square both sides:
\[ V^2 = 2AS \]
Divide both sides by \( 2A \):
\[ S = \frac{V^2}{2A} \]
Answers:
- \( A = \frac{V^2}{2S} \)
- \( S = \frac{V^2}{2A} \)
---
#### Solve for \( A \):
\[ D = \frac{1}{2} A^2 T^2 \]
Multiply both sides by 2:
\[ 2D = A^2 T^2 \]
Divide both sides by \( T^2 \):
\[ \frac{2D}{T^2} = A^2 \]
Take the square root of both sides:
\[ A = \sqrt{\frac{2D}{T^2}} \]
\[ A = \frac{\sqrt{2D}}{T} \]
#### Solve for \( T \):
\[ D = \frac{1}{2} A^2 T^2 \]
Multiply both sides by 2:
\[ 2D = A^2 T^2 \]
Divide both sides by \( A^2 \):
\[ \frac{2D}{A^2} = T^2 \]
Take the square root of both sides:
\[ T = \sqrt{\frac{2D}{A^2}} \]
\[ T = \frac{\sqrt{2D}}{A} \]
Answers:
- \( A = \frac{\sqrt{2D}}{T} \)
- \( T = \frac{\sqrt{2D}}{A} \)
---
1. \( D = vT \), \( T = \frac{D}{v} \)
2. \( B = \frac{A - D}{C} \), \( C = \frac{A - D}{B} \), \( D = A - BC \)
3. \( A = \frac{BC}{D} \), \( B = \frac{AD}{C} \), \( C = \frac{AD}{B} \), \( D = \frac{BC}{A} \)
4. \( V = \sqrt{\frac{A}{2D}} \), \( D = \frac{A}{2V^2} \)
5. \( C = \sqrt{\frac{E}{M}} \), \( M = \frac{E}{C^2} \)
6. \( A = \frac{V^2}{2S} \), \( S = \frac{V^2}{2A} \)
7. \( A = \frac{\sqrt{2D}}{T} \), \( T = \frac{\sqrt{2D}}{A} \)
\[
\boxed{
\begin{aligned}
1. & \quad D = vT, \, T = \frac{D}{v} \\
2. & \quad B = \frac{A - D}{C}, \, C = \frac{A - D}{B}, \, D = A - BC \\
3. & \quad A = \frac{BC}{D}, \, B = \frac{AD}{C}, \, C = \frac{AD}{B}, \, D = \frac{BC}{A} \\
4. & \quad V = \sqrt{\frac{A}{2D}}, \, D = \frac{A}{2V^2} \\
5. & \quad C = \sqrt{\frac{E}{M}}, \, M = \frac{E}{C^2} \\
6. & \quad A = \frac{V^2}{2S}, \, S = \frac{V^2}{2A} \\
7. & \quad A = \frac{\sqrt{2D}}{T}, \, T = \frac{\sqrt{2D}}{A}
\end{aligned}
}
\]
---
1. \( v = \frac{D}{T} \)
#### Solve for \( D \):
\[ v = \frac{D}{T} \]
Multiply both sides by \( T \):
\[ D = vT \]
#### Solve for \( T \):
\[ v = \frac{D}{T} \]
Multiply both sides by \( T \):
\[ vT = D \]
Divide both sides by \( v \):
\[ T = \frac{D}{v} \]
Answers:
- \( D = vT \)
- \( T = \frac{D}{v} \)
---
2. \( A = BC + D \)
#### Solve for \( B \):
\[ A = BC + D \]
Subtract \( D \) from both sides:
\[ A - D = BC \]
Divide both sides by \( C \):
\[ B = \frac{A - D}{C} \]
#### Solve for \( C \):
\[ A = BC + D \]
Subtract \( D \) from both sides:
\[ A - D = BC \]
Divide both sides by \( B \):
\[ C = \frac{A - D}{B} \]
#### Solve for \( D \):
\[ A = BC + D \]
Subtract \( BC \) from both sides:
\[ D = A - BC \]
Answers:
- \( B = \frac{A - D}{C} \)
- \( C = \frac{A - D}{B} \)
- \( D = A - BC \)
---
3. \( \frac{A}{B} = \frac{C}{D} \)
#### Solve for \( A \):
\[ \frac{A}{B} = \frac{C}{D} \]
Multiply both sides by \( B \):
\[ A = \frac{BC}{D} \]
#### Solve for \( B \):
\[ \frac{A}{B} = \frac{C}{D} \]
Multiply both sides by \( B \):
\[ A = \frac{BC}{D} \]
Multiply both sides by \( D \):
\[ AD = BC \]
Divide both sides by \( C \):
\[ B = \frac{AD}{C} \]
#### Solve for \( C \):
\[ \frac{A}{B} = \frac{C}{D} \]
Multiply both sides by \( D \):
\[ \frac{AD}{B} = C \]
\[ C = \frac{AD}{B} \]
#### Solve for \( D \):
\[ \frac{A}{B} = \frac{C}{D} \]
Multiply both sides by \( D \):
\[ \frac{AD}{B} = C \]
Multiply both sides by \( B \):
\[ AD = BC \]
Divide both sides by \( A \):
\[ D = \frac{BC}{A} \]
Answers:
- \( A = \frac{BC}{D} \)
- \( B = \frac{AD}{C} \)
- \( C = \frac{AD}{B} \)
- \( D = \frac{BC}{A} \)
---
4. \( A = V^2 \cdot 2D \)
#### Solve for \( V \):
\[ A = V^2 \cdot 2D \]
Divide both sides by \( 2D \):
\[ \frac{A}{2D} = V^2 \]
Take the square root of both sides:
\[ V = \sqrt{\frac{A}{2D}} \]
#### Solve for \( D \):
\[ A = V^2 \cdot 2D \]
Divide both sides by \( 2V^2 \):
\[ D = \frac{A}{2V^2} \]
Answers:
- \( V = \sqrt{\frac{A}{2D}} \)
- \( D = \frac{A}{2V^2} \)
---
5. \( E = M \cdot C^2 \)
#### Solve for \( C \):
\[ E = M \cdot C^2 \]
Divide both sides by \( M \):
\[ \frac{E}{M} = C^2 \]
Take the square root of both sides:
\[ C = \sqrt{\frac{E}{M}} \]
#### Solve for \( M \):
\[ E = M \cdot C^2 \]
Divide both sides by \( C^2 \):
\[ M = \frac{E}{C^2} \]
Answers:
- \( C = \sqrt{\frac{E}{M}} \)
- \( M = \frac{E}{C^2} \)
---
6. \( V = \sqrt{2AS} \)
#### Solve for \( A \):
\[ V = \sqrt{2AS} \]
Square both sides:
\[ V^2 = 2AS \]
Divide both sides by \( 2S \):
\[ A = \frac{V^2}{2S} \]
#### Solve for \( S \):
\[ V = \sqrt{2AS} \]
Square both sides:
\[ V^2 = 2AS \]
Divide both sides by \( 2A \):
\[ S = \frac{V^2}{2A} \]
Answers:
- \( A = \frac{V^2}{2S} \)
- \( S = \frac{V^2}{2A} \)
---
7. \( D = \frac{1}{2} A^2 T^2 \)
#### Solve for \( A \):
\[ D = \frac{1}{2} A^2 T^2 \]
Multiply both sides by 2:
\[ 2D = A^2 T^2 \]
Divide both sides by \( T^2 \):
\[ \frac{2D}{T^2} = A^2 \]
Take the square root of both sides:
\[ A = \sqrt{\frac{2D}{T^2}} \]
\[ A = \frac{\sqrt{2D}}{T} \]
#### Solve for \( T \):
\[ D = \frac{1}{2} A^2 T^2 \]
Multiply both sides by 2:
\[ 2D = A^2 T^2 \]
Divide both sides by \( A^2 \):
\[ \frac{2D}{A^2} = T^2 \]
Take the square root of both sides:
\[ T = \sqrt{\frac{2D}{A^2}} \]
\[ T = \frac{\sqrt{2D}}{A} \]
Answers:
- \( A = \frac{\sqrt{2D}}{T} \)
- \( T = \frac{\sqrt{2D}}{A} \)
---
Final Answers:
1. \( D = vT \), \( T = \frac{D}{v} \)
2. \( B = \frac{A - D}{C} \), \( C = \frac{A - D}{B} \), \( D = A - BC \)
3. \( A = \frac{BC}{D} \), \( B = \frac{AD}{C} \), \( C = \frac{AD}{B} \), \( D = \frac{BC}{A} \)
4. \( V = \sqrt{\frac{A}{2D}} \), \( D = \frac{A}{2V^2} \)
5. \( C = \sqrt{\frac{E}{M}} \), \( M = \frac{E}{C^2} \)
6. \( A = \frac{V^2}{2S} \), \( S = \frac{V^2}{2A} \)
7. \( A = \frac{\sqrt{2D}}{T} \), \( T = \frac{\sqrt{2D}}{A} \)
\[
\boxed{
\begin{aligned}
1. & \quad D = vT, \, T = \frac{D}{v} \\
2. & \quad B = \frac{A - D}{C}, \, C = \frac{A - D}{B}, \, D = A - BC \\
3. & \quad A = \frac{BC}{D}, \, B = \frac{AD}{C}, \, C = \frac{AD}{B}, \, D = \frac{BC}{A} \\
4. & \quad V = \sqrt{\frac{A}{2D}}, \, D = \frac{A}{2V^2} \\
5. & \quad C = \sqrt{\frac{E}{M}}, \, M = \frac{E}{C^2} \\
6. & \quad A = \frac{V^2}{2S}, \, S = \frac{V^2}{2A} \\
7. & \quad A = \frac{\sqrt{2D}}{T}, \, T = \frac{\sqrt{2D}}{A}
\end{aligned}
}
\]
Parent Tip: Review the logic above to help your child master the concept of manipulating formulas worksheet.