Let’s solve each division problem step by step. We’re dividing a 2-digit number by a 1-digit number and finding the remainder.
---
Problem 1: 31 ÷ 5
We already have this one started in the image:
- 5 goes into 31 how many times?
→ 5 × 6 = 30 (that’s the biggest multiple of 5 under 31)
→ Subtract: 31 - 30 =
1 → That’s the remainder.
✔ Answer: Quotient = 6, Remainder =
1
*(Note: The image shows “0” as remainder — that’s incorrect. It should be 1.)*
---
Problem 2: 37 ÷ 3
- 3 × 12 = 36 (biggest multiple of 3 under 37)
→ 37 - 36 =
1
✔ Answer: Quotient = 12, Remainder =
1
---
Problem 3: 89 ÷ 2
- 2 × 44 = 88
→ 89 - 88 =
1
✔ Answer: Quotient = 44, Remainder =
1
---
Problem 4: 65 ÷ 6
- 6 × 10 = 60
→ 65 - 60 =
5
✔ Answer: Quotient = 10, Remainder =
5
---
Problem 5: 83 ÷ 5
- 5 × 16 = 80
→ 83 - 80 =
3
✔ Answer: Quotient = 16, Remainder =
3
---
Problem 6: 93 ÷ 7
- 7 × 13 = 91
→ 93 - 91 =
2
✔ Answer: Quotient = 13, Remainder =
2
---
Problem 7: 65 ÷ 4
- 4 × 16 = 64
→ 65 - 64 =
1
✔ Answer: Quotient = 16, Remainder =
1
---
Problem 8: 99 ÷ 6
- 6 × 16 = 96
→ 99 - 96 =
3
✔ Answer: Quotient = 16, Remainder =
3
---
Problem 9: 69 ÷ 8
- 8 × 8 = 64
→ 69 - 64 =
5
✔ Answer: Quotient = 8, Remainder =
5
---
Final Answer:
Here are all the answers with remainders:
1. 31 ÷ 5 →
Remainder 1
2. 37 ÷ 3 →
Remainder 1
3. 89 ÷ 2 →
Remainder 1
4. 65 ÷ 6 →
Remainder 5
5. 83 ÷ 5 →
Remainder 3
6. 93 ÷ 7 →
Remainder 2
7. 65 ÷ 4 →
Remainder 1
8. 99 ÷ 6 →
Remainder 3
9. 69 ÷ 8 →
Remainder 5
Parent Tip: Review the logic above to help your child master the concept of math for 5th graders worksheet.