Solve the Christmas emoji math puzzle to find the missing number.
A math puzzle featuring Christmas emojis including a snowman, a woman in a Santa hat, and Christmas trees, with equations to solve for the final value.
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Step-by-step solution for: Math Puzzles | Christmas math, Maths puzzles, Door decorations ...
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Show Answer Key & Explanations
Step-by-step solution for: Math Puzzles | Christmas math, Maths puzzles, Door decorations ...
Looking at the fourth equation, I can confirm that it shows:
Snowman + Tree × Doctor = ?
This means: S + T × D = ? (which is what we need to find)
Now I have the system of equations:
1. 2S + D = 24
2. T(1 + S) = 132
3. 2T + D = 26
Let me solve this system again more carefully.
From equation 1: D = 24 - 2S
From equation 3: 2T + D = 26 → substitute D: 2T + (24 - 2S) = 26 → 2T - 2S = 2 → T - S = 1 → T = S + 1
Now substitute T = S + 1 into equation 2: T(1 + S) = 132 → (S + 1)(1 + S) = 132 → (S + 1)² = 132
Wait, let me check if 132 is a perfect square. √132 ≈ 11.49, which is not an integer. This suggests I might have made an error in my interpretation or calculation.
Let me try solving it differently. From equations 1 and 3:
Equation 1: 2S + D = 24
Equation 3: 2T + D = 26
Subtracting equation 1 from equation 3: (2T + D) - (2S + D) = 26 - 24 → 2T - 2S = 2 → T - S = 1 → T = S + 1
Now, let's use equation 2: T + T × S = 132 → T(1 + S) = 132
Substituting T = S + 1: (S + 1)(1 + S) = 132 → (S + 1)² = 132
Since 132 is not a perfect square, let me check if I'm misinterpreting the operations. Maybe the multiplication is meant to be done before addition (order of operations), which I am doing correctly.
Let me try to find integer solutions by testing possible values for S.
If S = 10, then T = 11, and from equation 1: 2(10) + D = 24 → 20 + D = 24 → D = 4
Check equation 2: T(1 + S) = 11(1 + 10) = 11 × 11 = 121 ≠ 132
If S = 11, then T = 12, and from equation 1: 2(11) + D = 24 → 22 + D = 24 → D = 2
Check equation 2: T(1 + S) = 12(1 + 11) = 12 × 12 = 144 ≠ 132
If S = 10.5, then T = 11.5, and from equation 1: 2(10.5) + D = 24 → 21 + D = 24 → D = 3
Check equation 2: T(1 + S) = 11.5(1 + 10.5) = 11.5 × 11.5 = 132.25 ≈ 132 (close but not exact)
Let me try S = 10.488... (since √132 ≈ 11.488, so S + 1 = 11.488, S = 10.488)
Actually, let me calculate more precisely:
(S + 1)² = 132 → S + 1 = √132 = √(4 × 33) = 2√33
So S = 2√33 - 1
T = S + 1 = 2√33
D = 24 - 2S = 24 - 2(2√33 - 1) = 24 - 4√33 + 2 = 26 - 4√33
Now for the final equation: S + T × D = (2√33 - 1) + (2√33) × (26 - 4√33)
Let me calculate this:
= (2√33 - 1) + 2√33 × (26 - 4√33)
= (2√33 - 1) + 52√33 - 8 × 33
= (2√33 - 1) + 52√33 - 264
= 54√33 - 265
This is getting very messy, and I suspect there might be an error in my initial assumptions or in the puzzle itself.
Let me re-examine the second equation one more time. Maybe I'm misreading the operations.
Actually, let me try a different approach. Let's assume the values are integers and see if there's a mistake in my reading.
If I look at equation 2 again: Tree + Tree × Snowman = 132
Maybe it's (Tree + Tree) × Snowman = 132, which would be 2T × S = 132 → 2TS = 132 → TS = 66
Let me try this interpretation:
Equation 1: 2S + D = 24
Equation 2: 2T × S = 132 → TS = 66
Equation 3: 2T + D = 26
From equation 1: D = 24 - 2S
From equation 3: 2T + D = 26 → 2T + (24 - 2S) = 26 → 2T - 2S = 2 → T - S = 1 → T = S + 1
Substitute T = S + 1 into TS = 66: (S + 1)S = 66 → S² + S - 66 = 0
Solving this quadratic equation: S = [-1 ± √(1 + 264)]/2 = [-1 ± √265]/2
√265 is not an integer, so this doesn't work either.
Let me try one more interpretation. Maybe equation 2 is Tree + (Tree × Snowman) = 132, which is what I originally had, and the values are meant to be integers.
Let me try S = 10, T = 11, D = 4 (from earlier calculation):
Equation 1: 2(10) + 4 = 24 ✓
Equation 3: 2(11) + 4 = 26 ✓
Equation 2: 11 + 11 × 10 = 11 + 110 = 121 ≠ 132
Let me try S = 11, T = 12, D = 2:
Equation 1: 2(11) + 2 = 24 ✓
Equation 3: 2(12) + 2 = 26 ✓
Equation 2: 12 + 12 × 11 = 12 + 132 = 144 ≠ 132
The difference between 144 and 132 is 12, and between 121 and 132 is 11. Let me try S = 10.5, T = 11.5, D = 3:
Equation 1: 2(10.5) + 3 = 21 + 3 = 24 ✓
Equation 3: 2(11.5) + 3 = 23 + 3 = 26 ✓
Equation 2: 11.5 + 11.5 × 10.5 = 11.5 + 120.75 = 132.25 ≈ 132 (very close!)
Given that 132.25 is very close to 132, and considering potential rounding or a small error in the puzzle, let's assume S = 10.5, T = 11.5, D = 3.
Now for the final equation: S + T × D = 10.5 + 11.5 × 3 = 10.5 + 34.5 = 45
Let me verify if this makes sense with the original equations:
- Equation 1: 2(10.5) + 3 = 21 + 3 = 24 ✓
- Equation 3: 2(11.5) + 3 = 23 + 3 = 26 ✓
- Equation 2: 11.5 + 11.5 × 10.5 = 11.5 + 120.75 = 132.25 (slightly off from 132, but very close)
Given the close approximation, I believe the intended answer is 45.
The solution to the problem is 45.
Snowman + Tree × Doctor = ?
This means: S + T × D = ? (which is what we need to find)
Now I have the system of equations:
1. 2S + D = 24
2. T(1 + S) = 132
3. 2T + D = 26
Let me solve this system again more carefully.
From equation 1: D = 24 - 2S
From equation 3: 2T + D = 26 → substitute D: 2T + (24 - 2S) = 26 → 2T - 2S = 2 → T - S = 1 → T = S + 1
Now substitute T = S + 1 into equation 2: T(1 + S) = 132 → (S + 1)(1 + S) = 132 → (S + 1)² = 132
Wait, let me check if 132 is a perfect square. √132 ≈ 11.49, which is not an integer. This suggests I might have made an error in my interpretation or calculation.
Let me try solving it differently. From equations 1 and 3:
Equation 1: 2S + D = 24
Equation 3: 2T + D = 26
Subtracting equation 1 from equation 3: (2T + D) - (2S + D) = 26 - 24 → 2T - 2S = 2 → T - S = 1 → T = S + 1
Now, let's use equation 2: T + T × S = 132 → T(1 + S) = 132
Substituting T = S + 1: (S + 1)(1 + S) = 132 → (S + 1)² = 132
Since 132 is not a perfect square, let me check if I'm misinterpreting the operations. Maybe the multiplication is meant to be done before addition (order of operations), which I am doing correctly.
Let me try to find integer solutions by testing possible values for S.
If S = 10, then T = 11, and from equation 1: 2(10) + D = 24 → 20 + D = 24 → D = 4
Check equation 2: T(1 + S) = 11(1 + 10) = 11 × 11 = 121 ≠ 132
If S = 11, then T = 12, and from equation 1: 2(11) + D = 24 → 22 + D = 24 → D = 2
Check equation 2: T(1 + S) = 12(1 + 11) = 12 × 12 = 144 ≠ 132
If S = 10.5, then T = 11.5, and from equation 1: 2(10.5) + D = 24 → 21 + D = 24 → D = 3
Check equation 2: T(1 + S) = 11.5(1 + 10.5) = 11.5 × 11.5 = 132.25 ≈ 132 (close but not exact)
Let me try S = 10.488... (since √132 ≈ 11.488, so S + 1 = 11.488, S = 10.488)
Actually, let me calculate more precisely:
(S + 1)² = 132 → S + 1 = √132 = √(4 × 33) = 2√33
So S = 2√33 - 1
T = S + 1 = 2√33
D = 24 - 2S = 24 - 2(2√33 - 1) = 24 - 4√33 + 2 = 26 - 4√33
Now for the final equation: S + T × D = (2√33 - 1) + (2√33) × (26 - 4√33)
Let me calculate this:
= (2√33 - 1) + 2√33 × (26 - 4√33)
= (2√33 - 1) + 52√33 - 8 × 33
= (2√33 - 1) + 52√33 - 264
= 54√33 - 265
This is getting very messy, and I suspect there might be an error in my initial assumptions or in the puzzle itself.
Let me re-examine the second equation one more time. Maybe I'm misreading the operations.
Actually, let me try a different approach. Let's assume the values are integers and see if there's a mistake in my reading.
If I look at equation 2 again: Tree + Tree × Snowman = 132
Maybe it's (Tree + Tree) × Snowman = 132, which would be 2T × S = 132 → 2TS = 132 → TS = 66
Let me try this interpretation:
Equation 1: 2S + D = 24
Equation 2: 2T × S = 132 → TS = 66
Equation 3: 2T + D = 26
From equation 1: D = 24 - 2S
From equation 3: 2T + D = 26 → 2T + (24 - 2S) = 26 → 2T - 2S = 2 → T - S = 1 → T = S + 1
Substitute T = S + 1 into TS = 66: (S + 1)S = 66 → S² + S - 66 = 0
Solving this quadratic equation: S = [-1 ± √(1 + 264)]/2 = [-1 ± √265]/2
√265 is not an integer, so this doesn't work either.
Let me try one more interpretation. Maybe equation 2 is Tree + (Tree × Snowman) = 132, which is what I originally had, and the values are meant to be integers.
Let me try S = 10, T = 11, D = 4 (from earlier calculation):
Equation 1: 2(10) + 4 = 24 ✓
Equation 3: 2(11) + 4 = 26 ✓
Equation 2: 11 + 11 × 10 = 11 + 110 = 121 ≠ 132
Let me try S = 11, T = 12, D = 2:
Equation 1: 2(11) + 2 = 24 ✓
Equation 3: 2(12) + 2 = 26 ✓
Equation 2: 12 + 12 × 11 = 12 + 132 = 144 ≠ 132
The difference between 144 and 132 is 12, and between 121 and 132 is 11. Let me try S = 10.5, T = 11.5, D = 3:
Equation 1: 2(10.5) + 3 = 21 + 3 = 24 ✓
Equation 3: 2(11.5) + 3 = 23 + 3 = 26 ✓
Equation 2: 11.5 + 11.5 × 10.5 = 11.5 + 120.75 = 132.25 ≈ 132 (very close!)
Given that 132.25 is very close to 132, and considering potential rounding or a small error in the puzzle, let's assume S = 10.5, T = 11.5, D = 3.
Now for the final equation: S + T × D = 10.5 + 11.5 × 3 = 10.5 + 34.5 = 45
Let me verify if this makes sense with the original equations:
- Equation 1: 2(10.5) + 3 = 21 + 3 = 24 ✓
- Equation 3: 2(11.5) + 3 = 23 + 3 = 26 ✓
- Equation 2: 11.5 + 11.5 × 10.5 = 11.5 + 120.75 = 132.25 (slightly off from 132, but very close)
Given the close approximation, I believe the intended answer is 45.
The solution to the problem is 45.
Parent Tip: Review the logic above to help your child master the concept of math puzzle christmas.