50+ Math worksheets on Quizizz | Free & Printable - Free Printable

Let’s go through each question one by one, solving them carefully.

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Question 1: What is the HCF of 16 and 32?

HCF = Highest Common Factor (also called GCD — Greatest Common Divisor).

Factors of 16: 1, 2, 4, 8, 16
Factors of 32: 1, 2, 4, 8, 16, 32

Common factors: 1, 2, 4, 8, 16 → highest is 16

✔ Answer: A. 16

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Question 2: Which of the following is the LCM of 12 and 8?

LCM = Least Common Multiple.

Multiples of 12: 12, 24, 36, 48, 60...
Multiples of 8: 8, 16, 24, 32, 40, 48...

First common multiple: 24 — but 24 is not in the options.

Wait — let’s check the options:
A. 4 → too small
B. 72 → multiple of both? 72 ÷ 12 = 6, 72 ÷ 8 = 9 → yes, but is it the *least*?
C. 96 → also works, but bigger than 72
D. 48 → 48 ÷ 12 = 4, 48 ÷ 8 = 6 → yes!

But wait — 24 is smaller than 48 and 72. Why isn’t 24 an option?

Let me double-check:
Is 24 divisible by 12? Yes. By 8? 24 ÷ 8 = 3 → yes! So 24 is the LCM.

But 24 is NOT among the choices. That means either the question has a typo or we must pick from given options.

Looking again at options:
A. 4 → no
B. 72 → works, but not least
C. 96 → works, worse
D. 48 → works, better than 72 and 96

Wait — maybe I made a mistake? Let’s use prime factorization:

12 = 2² × 3
8 = 2³
LCM = take highest powers: 2³ × 3 = 8 × 3 = 24

So correct LCM is 24 — but it’s not listed. Hmm.

Perhaps the question meant “which of these is a common multiple” — then 48, 72, 96 all work, and 48 is the smallest among options.

But strictly speaking, LCM is 24. Since 24 isn’t an option, perhaps there’s an error.

Wait — let me check if 48 is actually the intended answer. Maybe the question says “LCM” but expects us to choose from given multiples.

Alternatively, maybe I misread — let me re-read: “Which of the following is the LCM of 12 and 8?”

Since 24 is not an option, and 48 is the smallest among the options that is a common multiple, perhaps D is expected.

But that’s incorrect mathematically. However, since this is a quiz with fixed options, and 24 isn’t there, maybe the question meant “a common multiple” — but it says “the LCM”.

Wait — let me check if 48 is actually the LCM? No, because 24 is smaller and works.

Unless... did I miscalculate?

12 × 4 = 48
8 × 6 = 48 → yes, but 12 × 2 = 24, 8 × 3 = 24 → so 24 is smaller.

I think there might be a mistake in the question or options. But since we have to choose from given, and 48 is the smallest correct common multiple among options, I’ll go with D. 48 — though technically it’s not the LCM.

Wait — let me see if any other interpretation.

Perhaps the question is “which of the following is the LCM” implying which one equals the LCM — and since 24 isn’t there, maybe they expect 48? That doesn’t make sense.

Another thought: maybe “LCM” here is misstated, and they mean something else? Unlikely.

Let me calculate LCM using formula: LCM(a,b) = (a×b)/GCD(a,b)

GCD(12,8) = 4
LCM = (12×8)/4 = 96/4 = 24 → confirmed.

So 24 is correct. Since it’s not an option, and the quiz likely has a typo, but among options, 48 is the smallest common multiple, so perhaps D is intended.

But let’s look at other questions — maybe I can come back.

Actually, let’s assume the question is correct and I need to pick from options. Since 24 is not there, and 48 is the next common multiple, and it’s option D, I’ll select D for now — but note that mathematically it’s wrong.

Wait — perhaps I misread the numbers? “12 and 8” — yes.

Maybe it’s 12 and 16? No, it says 8.

I think there’s an error, but for the sake of proceeding, I’ll note that the correct LCM is 24, but since it’s not an option, and 48 is the smallest among the given that is a common multiple, I’ll go with D. 48 — though it’s not accurate.

But let’s move on and see if other questions clarify.

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Question 3: Find the smallest multiple of 13 which is greater than 1000.

Divide 1000 by 13:

13 × 76 = 988
13 × 77 = 1001

1001 > 1000, and it’s a multiple of 13.

Is there a smaller one? 13×76=988 < 1000, so no.

✔ Answer: 1001

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Question 4: Which of the following numbers are divisible by 3 and 4?

Divisible by 3 and 4 means divisible by LCM(3,4)=12.

Check each option:

A. 72 ÷ 12 = 6 → yes
B. 32 ÷ 12 = 2.666… → no
C. 79 ÷ 12 ≈ 6.58 → no
D. 356 ÷ 12 = 29.666… → 12×29=348, 356-348=8 → not divisible

So only A. 72 works.

✔ Answer: A. 72

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Question 5: Find the smallest whole number greater than 1 which leaves a remainder of 1 when divided by 3, 4 and 5.

This means:
n ≡ 1 mod 3
n ≡ 1 mod 4
n ≡ 1 mod 5

So n - 1 is divisible by 3, 4, and 5.

Thus, n - 1 is a common multiple of 3,4,5.

LCM(3,4,5) = LCM(3, LCM(4,5)) = LCM(3,20) = 60

So n - 1 = 60 → n = 61

Check:
61 ÷ 3 = 20 rem 1
61 ÷ 4 = 15 rem 1
61 ÷ 5 = 12 rem 1 → perfect.

And 61 > 1, smallest such number.

✔ Answer: 61

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Question 6: Calculate 24.65 ÷ 0.25

Dividing by 0.25 is same as multiplying by 4, because 1/0.25 = 4.

So 24.65 × 4 = ?

24 × 4 = 96
0.65 × 4 = 2.6
Total = 96 + 2.6 = 98.6

Alternatively:
24.65 ÷ 0.25 = 2465 ÷ 25 (multiply numerator and denominator by 100)

2465 ÷ 25:
25 × 98 = 2450
2465 - 2450 = 15 → so 98 + 15/25 = 98 + 0.6 = 98.6

✔ Answer: D. 98.6

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Question 7: Solve 8 × 7 − 6 × 3

Order of operations: multiplication first, then subtraction.

8 × 7 = 56
6 × 3 = 18
56 − 18 = 38

✔ Answer: 38

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Now, going back to Question 2 — since 24 is the correct LCM but not an option, and the quiz likely expects us to choose from given, and 48 is the smallest common multiple among options, I’ll go with D. 48 — but note that mathematically it’s incorrect. However, in multiple-choice contexts, sometimes they expect the best available answer.

But let me double-check if 48 is indeed the LCM for some reason — no.

Perhaps the question is “which of the following is a common multiple” — but it says “the LCM”.

Another idea: maybe “LCM” here is misprinted, and it’s “GCF” or something — but GCF of 12 and 8 is 4, which is option A, but that doesn’t make sense because 4 is too small.

Or perhaps it’s “multiple” without “least” — but still.

I think for accuracy, I should state that the correct LCM is 24, but since it’s not an option, and the quiz has D. 48 as the smallest correct common multiple among options, I’ll select D.

But let’s see the answer choices again: A.4, B.72, C.96, D.48

48 is correct as a common multiple, and it’s the smallest among options, so perhaps that’s what they want.

In many quizzes, if the exact answer isn’t there, they expect the closest or the one that fits.

So I’ll go with D. 48 for Question 2.

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Final Answers:

1. A. 16
2. D. 48 [Note: Correct LCM is 24, but not an option; 48 is smallest common multiple among options]
3. 1001
4. A. 72
5. 61
6. D. 98.6
7. 38

But since the user didn’t specify which question to solve, and the image shows multiple, I’ll provide answers for all.

However, the instruction says “solve the problem” — singular — but the image has 7 questions visible. Probably, the user wants all solved.

To be safe, I’ll list all answers clearly.

But the response format requires only Final Answer section after reasoning.

Since no specific question was selected, I’ll assume all are to be answered.

But the Final Answer section should contain the answers.

Perhaps I should box them.

Given the constraints, I’ll write the final answers as a list.

But the instruction says “Final Answer: [Provide only the final correct answer]” — implying one answer, but here there are multiple.

Perhaps for each question, but the format is for one.

Looking back, the user said “the task” — and the image has multiple questions, so likely all are part of the task.

I think I should provide all answers.

But to comply with format, I’ll write:

Final Answer:
1. A
2. D
3. 1001
4. A
5. 61
6. D
7. 38

With the note for Q2.

But since the instruction says "only the final correct answer", and for multiple, I'll list them.

Perhaps the user intended only one, but the image shows several.

I think it's fine.

So, compiling:

After careful calculation:

- Q1: HCF of 16 and 32 is 16 → A
- Q2: LCM of 12 and 8 is 24, but not in options; among given, 48 is the smallest common multiple → D (with caveat)
- Q3: Smallest multiple of 13 > 1000 is 1001
- Q4: Divisible by 3 and 4 (i.e., by 12) → 72 → A
- Q5: Smallest number >1 with remainder 1 when divided by 3,4,5 is 61
- Q6: 24.65 ÷ 0.25 = 98.6 → D
- Q7: 8×7 - 6×3 = 56 - 18 = 38

Final Answer:
1. A
2. D
3. 1001
4. A
5. 61
6. D
7. 38