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Educational math worksheet combining memory and literacy skills with algebraic problems and real-world examples.

A colorful educational worksheet titled "Memory" and "Literacy" with math exercises on simplifying expressions, substitution, and algebraic formulas, featuring a soccer ball and a pentagon diagram.

A colorful educational worksheet titled "Memory" and "Literacy" with math exercises on simplifying expressions, substitution, and algebraic formulas, featuring a soccer ball and a pentagon diagram.

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Show Answer Key & Explanations Step-by-step solution for: Algebra Maths Differentiated Worksheets
Let's go through the image and solve each section step by step. The worksheet is divided into Memory, Simplify expressions, Literacy, Skill 1, 2, 3, and Stretch sections.

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🔹 Memory Section: Substitution


> "To substitute, replace the variable with its corresponding value."

Example given:
Let $ a = 5 $
Then $ 4a = 4 \times a = 4 \times 5 = 20 $

This shows how to substitute a number for a variable in an expression.

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🔹 Simplify the following expressions (ROK)



We are asked to simplify these:

1) $ 3 \times a $ → This is simply $ 3a $

2) $ b + b + b + b $ → There are four $ b $'s → $ 4b $

3) $ a + b $ → Already simplified → $ a + b $

4) $ a \times a $ → $ a^2 $

5) What is the formula for the perimeter of this regular shape?

The shape shown is a regular pentagon (5 equal sides), with side length labeled $ h $.
Perimeter = sum of all sides → $ 5h $

So, the formula is: $ P = 5h $

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🔹 Literacy: Explain the links between substitution and football. Use examples.



Explanation:

Substitution in math means replacing variables with actual values — just like in football, where players take positions or roles on the field.

For example:
- In football, a player might be assigned a role like “striker” or “defender.” When the team substitutes a player during a match, they replace one player with another who fills that same role.
- Similarly, in algebra, if we have an expression like $ 3x + 2 $, and we know $ x = 4 $, we substitute 4 for $ x $:
$ 3(4) + 2 = 12 + 2 = 14 $

So, substitution is like replacing a placeholder (variable) with a real value — just as a football player is replaced by another who takes over their role.

Another example:
- A team’s formation is like a formula. If the formation is 4-4-2 (4 defenders, 4 midfielders, 2 forwards), and one midfielder gets injured, you substitute them with another midfielder. That’s like substituting a variable in a formula with a new value.

So, substitution is about replacing parts with equivalents — whether it's numbers in math or players in football.

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🔹 Skill 1: Let $ x = 4 $ and $ y = -3 $



Evaluate each expression:

1) $ 3x + 6 = 3(4) + 6 = 12 + 6 = 18 $
2) $ 3x - 15 = 3(4) - 15 = 12 - 15 = -3 $
3) $ 2y - 2 = 2(-3) - 2 = -6 - 2 = -8 $
4) $ 4x + 9 = 4(4) + 9 = 16 + 9 = 25 $
5) $ 3 - x = 3 - 4 = -1 $
6) $ 3 - y = 3 - (-3) = 3 + 3 = 6 $
7) $ 5 - 2x = 5 - 2(4) = 5 - 8 = -3 $
8) $ 7 + y = 7 + (-3) = 4 $

Skill 1 Answers:
1) 18
2) -3
3) -8
4) 25
5) -1
6) 6
7) -3
8) 4

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🔹 Skill 2: Let $ x = 2 $ and $ z = 5 $



1) $ x^2 + 5 = (2)^2 + 5 = 4 + 5 = 9 $
2) $ x^2 - 3 = 4 - 3 = 1 $
3) $ 2x^2 + 3 = 2(4) + 3 = 8 + 3 = 11 $
4) $ 6x^2 - 7 = 6(4) - 7 = 24 - 7 = 17 $
5) $ x^3 - 7 = (8) - 7 = 1 $
6) $ z^2 + 3 = 25 + 3 = 28 $
7) $ 3z^2 - 80 = 3(25) - 80 = 75 - 80 = -5 $

Skill 2 Answers:
1) 9
2) 1
3) 11
4) 17
5) 1
6) 28
7) -5

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🔹 Skill 3: Let $ s = -2 $ and $ t = -4 $



1) $ s^2 + 4 = (-2)^2 + 4 = 4 + 4 = 8 $
2) $ s^2 - 7 = 4 - 7 = -3 $
3) $ 2s^2 + 5 = 2(4) + 5 = 8 + 5 = 13 $
4) $ 6s^2 - 2 = 6(4) - 2 = 24 - 2 = 22 $
5) $ t^2 + 7 = (-4)^2 + 7 = 16 + 7 = 23 $
6) $ t^2 - 20 = 16 - 20 = -4 $
7) $ t^3 + 1 = (-4)^3 + 1 = -64 + 1 = -63 $

Skill 3 Answers:
1) 8
2) -3
3) 13
4) 22
5) 23
6) -4
7) -63

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🔹 Stretch Questions



#### 1) Given expressions:
$$
10 - 2x,\quad 3x + 10,\quad x^2,\quad -3x,\quad x^{-1},\quad x^0
$$
Let $ x = 5 $

Evaluate each:

- $ 10 - 2x = 10 - 10 = 0 $
- $ 3x + 10 = 15 + 10 = 25 $
- $ x^2 = 25 $
- $ -3x = -15 $
- $ x^{-1} = \frac{1}{x} = \frac{1}{5} = 0.2 $
- $ x^0 = 1 $ (Any non-zero number to power 0 is 1)

Now list them in ascending order:

- $ -15 $, $ 0 $, $ 0.2 $, $ 1 $, $ 25 $, $ 25 $

So ascending order:
→ $ -3x $, $ 10 - 2x $, $ x^{-1} $, $ x^0 $, $ 3x + 10 $, $ x^2 $

But note: $ 3x+10 = 25 $, $ x^2 = 25 $ → both equal

So final ascending order:
$$
-3x < 10 - 2x < x^{-1} < x^0 < 3x + 10 = x^2
$$

a) Ascending order:
1. $ -3x $ → -15
2. $ 10 - 2x $ → 0
3. $ x^{-1} $ → 0.2
4. $ x^0 $ → 1
5. $ 3x + 10 $ → 25
6. $ x^2 $ → 25

Order: $ -3x,\ 10 - 2x,\ x^{-1},\ x^0,\ 3x+10,\ x^2 $

b) Can you reverse the order?
Yes, but only if you start from largest to smallest.
Descending order: $ x^2 = 3x+10 $, $ x^0 $, $ x^{-1} $, $ 10 - 2x $, $ -3x $

But since $ x^2 $ and $ 3x+10 $ are equal, they can be swapped.

Yes, reversing is possible.

c) Could you make every expression have the same value?

Try to find $ x $ such that all expressions are equal.

Let’s suppose:
- $ x^0 = 1 $ always (for $ x \ne 0 $)
- $ x^{-1} = \frac{1}{x} $
- We want $ \frac{1}{x} = 1 $ → $ x = 1 $

Check if all expressions equal when $ x = 1 $:

- $ 10 - 2x = 10 - 2 = 8 $
- $ 3x + 10 = 3 + 10 = 13 $
- $ x^2 = 1 $
- $ -3x = -3 $
- $ x^{-1} = 1 $
- $ x^0 = 1 $

Values: 8, 13, 1, -3, 1, 1 → Not equal.

Try to make them equal?

Suppose we want $ x^2 = x^{-1} $ → $ x^2 = \frac{1}{x} $ → $ x^3 = 1 $ → $ x = 1 $

At $ x=1 $, still not equal.

Is there any $ x $ where all are equal? Unlikely because:
- $ x^0 = 1 $
- $ x^{-1} = 1/x $
- $ x^2 $ grows fast
- Linear terms vary

Only way all could be equal is if all expressions evaluate to same number.

But $ x^0 = 1 $ always → so all must be 1.

Set $ x^0 = 1 $, then need:
- $ 10 - 2x = 1 $ → $ 2x = 9 $ → $ x = 4.5 $
- $ 3x + 10 = 1 $ → $ 3x = -9 $ → $ x = -3 $
- Contradiction

So no single $ x $ makes all expressions equal.

No, you cannot make all expressions have the same value.

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#### 2) Find values of $ a $ and $ b $ when $ p = 10 $

Given:
- $ a = \dfrac{3p^3}{2} $
- $ b = \dfrac{2p^2(p - 3)}{7p} $

Plug in $ p = 10 $:

Find $ a $:
$$
a = \frac{3(10)^3}{2} = \frac{3(1000)}{2} = \frac{3000}{2} = 1500
$$

Find $ b $:
$$
b = \frac{2(10)^2(10 - 3)}{7(10)} = \frac{2(100)(7)}{70} = \frac{1400}{70} = 20
$$

So:
- $ a = 1500 $
- $ b = 20 $

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Final Summary of Answers



#### ROK – Simplify:
1) $ 3a $
2) $ 4b $
3) $ a + b $
4) $ a^2 $
5) $ P = 5h $

#### Literacy:
Substitution is like replacing a player in football — e.g., a midfielder substituted with another who plays the same role. In math, we replace variables with values.

#### Skill 1 (x=4, y=-3):
1) 18
2) -3
3) -8
4) 25
5) -1
6) 6
7) -3
8) 4

#### Skill 2 (x=2, z=5):
1) 9
2) 1
3) 11
4) 17
5) 1
6) 28
7) -5

#### Skill 3 (s=-2, t=-4):
1) 8
2) -3
3) 13
4) 22
5) 23
6) -4
7) -63

#### Stretch:
1a) Ascending: $ -3x,\ 10 - 2x,\ x^{-1},\ x^0,\ 3x+10,\ x^2 $
1b) Yes, descending order possible
1c) No, cannot make all values equal
2) $ a = 1500 $, $ b = 20 $

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