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Math worksheet for solving linear equations, divided into three sections with varying levels of difficulty.

Worksheet titled "Solving Linear Equations (B)" with three sections (A, B, C) containing algebraic equations to solve for x, featuring a cartoon character and the Cazoom logo.

Worksheet titled "Solving Linear Equations (B)" with three sections (A, B, C) containing algebraic equations to solve for x, featuring a cartoon character and the Cazoom logo.

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Show Answer Key & Explanations Step-by-step solution for: Year 7 Maths Worksheets | Cazoom Maths Worksheets
Let's solve each equation step-by-step to find the value of $ x $. The goal is to isolate $ x $ on one side of the equation.

---

Section A



1) $ 7x + 9 = 23 $
Subtract 9 from both sides:
$ 7x = 14 $
Divide by 7:
$ x = 2 $

2) $ 5x + 7 = 42 $
Subtract 7:
$ 5x = 35 $
Divide by 5:
$ x = 7 $

3) $ 4x + 3 = 51 $
Subtract 3:
$ 4x = 48 $
Divide by 4:
$ x = 12 $

4) $ 9x + 5 = 41 $
Subtract 5:
$ 9x = 36 $
Divide by 9:
$ x = 4 $

5) $ 4x + 2 = 34 $
Subtract 2:
$ 4x = 32 $
Divide by 4:
$ x = 8 $

6) $ 11x + 3 = 36 $
Subtract 3:
$ 11x = 33 $
Divide by 11:
$ x = 3 $

7) $ 10x + 2 = 72 $
Subtract 2:
$ 10x = 70 $
Divide by 10:
$ x = 7 $

8) $ 7x + 3 = 52 $
Subtract 3:
$ 7x = 49 $
Divide by 7:
$ x = 7 $

9) $ 6x + 5 = 17 $
Subtract 5:
$ 6x = 12 $
Divide by 6:
$ x = 2 $

10) $ 4x + 7 = 9 $
Subtract 7:
$ 4x = 2 $
Divide by 4:
$ x = \frac{1}{2} $

11) $ 8x + 11 = 15 $
Subtract 11:
$ 8x = 4 $
Divide by 8:
$ x = \frac{1}{2} $

12) $ 4x + 17 = 18 $
Subtract 17:
$ 4x = 1 $
Divide by 4:
$ x = \frac{1}{4} $

---

Section B



1) $ 1 + 6x = 19 $
Subtract 1:
$ 6x = 18 $
Divide by 6:
$ x = 3 $

2) $ 9 + 7x = 30 $
Subtract 9:
$ 7x = 21 $
Divide by 7:
$ x = 3 $

3) $ 3 + 2x = 17 $
Subtract 3:
$ 2x = 14 $
Divide by 2:
$ x = 7 $

4) $ 11 + 5x = 71 $
Subtract 11:
$ 5x = 60 $
Divide by 5:
$ x = 12 $

5) $ 5 + 3x = 32 $
Subtract 5:
$ 3x = 27 $
Divide by 3:
$ x = 9 $

6) $ 4 + 5x = 44 $
Subtract 4:
$ 5x = 40 $
Divide by 5:
$ x = 8 $

7) $ 23 = x + 8 $
Subtract 8:
$ x = 15 $

8) $ 28 = 3x + 1 $
Subtract 1:
$ 27 = 3x $
Divide by 3:
$ x = 9 $

9) $ 53 = 8x + 5 $
Subtract 5:
$ 48 = 8x $
Divide by 8:
$ x = 6 $

10) $ 13 = 11 + 4x $
Subtract 11:
$ 2 = 4x $
Divide by 4:
$ x = \frac{1}{2} $

11) $ 7 = 8x + 3 $
Subtract 3:
$ 4 = 8x $
Divide by 8:
$ x = \frac{1}{2} $

12) $ 12 = 7 + 15x $
Subtract 7:
$ 5 = 15x $
Divide by 15:
$ x = \frac{1}{3} $

---

Section C



1) $ 4x - 1 = 31 $
Add 1:
$ 4x = 32 $
Divide by 4:
$ x = 8 $

2) $ 3x - 4 = 29 $
Add 4:
$ 3x = 33 $
Divide by 3:
$ x = 11 $

3) $ 6x - 5 = 31 $
Add 5:
$ 6x = 36 $
Divide by 6:
$ x = 6 $

4) $ 8x - 2 = 46 $
Add 2:
$ 8x = 48 $
Divide by 8:
$ x = 6 $

5) $ 2x - 7 = 21 $
Add 7:
$ 2x = 28 $
Divide by 2:
$ x = 14 $

6) $ 7x - 3 = 18 $
Add 3:
$ 7x = 21 $
Divide by 7:
$ x = 3 $

7) $ 9x - 4 = 32 $
Add 4:
$ 9x = 36 $
Divide by 9:
$ x = 4 $

8) $ 5x - 1 = 64 $
Add 1:
$ 5x = 65 $
Divide by 5:
$ x = 13 $

9) $ 12x - 9 = 39 $
Add 9:
$ 12x = 48 $
Divide by 12:
$ x = 4 $

10) $ 2x - 1 = 2 $
Add 1:
$ 2x = 3 $
Divide by 2:
$ x = \frac{3}{2} $

11) $ 4x - 8 = 10 $
Add 8:
$ 4x = 18 $
Divide by 4:
$ x = \frac{9}{2} $

12) $ 15x - 2 = 3 $
Add 2:
$ 15x = 5 $
Divide by 15:
$ x = \frac{1}{3} $

---

Final Answers:



#### Section A
1) $ x = 2 $
2) $ x = 7 $
3) $ x = 12 $
4) $ x = 4 $
5) $ x = 8 $
6) $ x = 3 $
7) $ x = 7 $
8) $ x = 7 $
9) $ x = 2 $
10) $ x = \frac{1}{2} $
11) $ x = \frac{1}{2} $
12) $ x = \frac{1}{4} $

#### Section B
1) $ x = 3 $
2) $ x = 3 $
3) $ x = 7 $
4) $ x = 12 $
5) $ x = 9 $
6) $ x = 8 $
7) $ x = 15 $
8) $ x = 9 $
9) $ x = 6 $
10) $ x = \frac{1}{2} $
11) $ x = \frac{1}{2} $
12) $ x = \frac{1}{3} $

#### Section C
1) $ x = 8 $
2) $ x = 11 $
3) $ x = 6 $
4) $ x = 6 $
5) $ x = 14 $
6) $ x = 3 $
7) $ x = 4 $
8) $ x = 13 $
9) $ x = 4 $
10) $ x = \frac{3}{2} $
11) $ x = \frac{9}{2} $
12) $ x = \frac{1}{3} $

---

🔍 Summary of Steps:


To solve linear equations like $ ax + b = c $, follow these steps:
1. Isolate the variable term by moving constants to the other side using addition/subtraction.
2. Divide both sides by the coefficient of $ x $ to solve for $ x $.

This method works for all linear equations in one variable.

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