Math worksheet focusing on multiplication properties and multiplying by 10, 100, and 1000.

Worksheet-17: Properties of Multiplication/Multiplying with 10, 100, and 1000

#### Section 1: Fill in the blanks

We will solve each part step by step.

---

#### Part (a):
$$
4312 \times 4119 = 4119 \times \_\_\_\_\_
$$
- Property Used: Commutative Property of Multiplication ($a \times b = b \times a$).
- Solution: The order of multiplication does not matter. Therefore:
$$
4312 \times 4119 = 4119 \times 4312
$$
- Answer: $\boxed{4312}$

---

#### Part (b):
$$
\_\_\_\_\_ \times 7136 = 7136 \times 2108
$$
- Property Used: Commutative Property of Multiplication ($a \times b = b \times a$).
- Solution: The order of multiplication does not matter. Therefore:
$$
2108 \times 7136 = 7136 \times 2108
$$
- Answer: $\boxed{2108}$

---

#### Part (c):
$$
\_\_\_\_\_ \times 3131 = 3131 \times 2482
$$
- Property Used: Commutative Property of Multiplication ($a \times b = b \times a$).
- Solution: The order of multiplication does not matter. Therefore:
$$
2482 \times 3131 = 3131 \times 2482
$$
- Answer: $\boxed{2482}$

---

#### Part (d):
$$
7395 \times \_\_\_\_\_ = 3322 \times 7395
$$
- Property Used: Commutative Property of Multiplication ($a \times b = b \times a$).
- Solution: The order of multiplication does not matter. Therefore:
$$
7395 \times 3322 = 3322 \times 7395
$$
- Answer: $\boxed{3322}$

---

#### Part (e):
$$
[3427 \times 4327] \times 5162 = 5982 \times [3427 \times \_\_\_\_\_]
$$
- Property Used: Associative Property of Multiplication ($a \times (b \times c) = (a \times b) \times c$).
- Solution: The grouping of factors does not matter. Therefore:
$$
[3427 \times 4327] \times 5162 = 5982 \times [3427 \times 4327]
$$
- Answer: $\boxed{4327}$

---

#### Part (f):
$$
[7672 \times 5688] \times 3213 = \_\_\_\_\_ \times [5688 \times 3213]
$$
- Property Used: Associative Property of Multiplication ($a \times (b \times c) = (a \times b) \times c$).
- Solution: The grouping of factors does not matter. Therefore:
$$
[7672 \times 5688] \times 3213 = 7672 \times [5688 \times 3213]
$$
- Answer: $\boxed{7672}$

---

#### Part (g):
$$
[1528 \times 4642] \times 5991 = 1528 \times [\_\_\_\_\_ \times 5991]
$$
- Property Used: Associative Property of Multiplication ($a \times (b \times c) = (a \times b) \times c$).
- Solution: The grouping of factors does not matter. Therefore:
$$
[1528 \times 4642] \times 5991 = 1528 \times [4642 \times 5991]
$$
- Answer: $\boxed{4642}$

---

#### Part (h):
$$
[\_\_\_\_\_ \times 4125] \times 2563 = 3139 \times [4125 \times \_\_\_\_\_]
$$
- Property Used: Associative Property of Multiplication ($a \times (b \times c) = (a \times b) \times c$).
- Solution: The grouping of factors does not matter. Therefore:
$$
[3139 \times 4125] \times 2563 = 3139 \times [4125 \times 2563]
$$
- Answer: $\boxed{3139, 2563}$

---

#### Part (i):
$$
1 \times \_\_\_\_\_ = 3972 \times 1 = 2725 \times 1 = 2725
$$
- Property Used: Identity Property of Multiplication ($a \times 1 = a$).
- Solution: Multiplying any number by 1 gives the same number. Therefore:
$$
1 \times 3972 = 3972 \quad \text{and} \quad 2725 \times 1 = 2725
$$
- Answer: $\boxed{3972}$

---

#### Part (j):
$$
4616 \times 1 = \_\_\_\_\_
$$
- Property Used: Identity Property of Multiplication ($a \times 1 = a$).
- Solution: Multiplying any number by 1 gives the same number. Therefore:
$$
4616 \times 1 = 4616
$$
- Answer: $\boxed{4616}$

---

#### Part (k):
$$
2396 \times \_\_\_\_\_ = 2396
$$
- Property Used: Identity Property of Multiplication ($a \times 1 = a$).
- Solution: Multiplying any number by 1 gives the same number. Therefore:
$$
2396 \times 1 = 2396
$$
- Answer: $\boxed{1}$

---

#### Part (l):
$$
0 \times 7734 = \_\_\_\_\_ \times 4619 = 0
$$
- Property Used: Zero Property of Multiplication ($a \times 0 = 0$).
- Solution: Multiplying any number by 0 gives 0. Therefore:
$$
0 \times 7734 = 0 \quad \text{and} \quad 0 \times 4619 = 0
$$
- Answer: $\boxed{0}$

---

#### Part (m):
$$
2796 \times 0 = \_\_\_\_\_
$$
- Property Used: Zero Property of Multiplication ($a \times 0 = 0$).
- Solution: Multiplying any number by 0 gives 0. Therefore:
$$
2796 \times 0 = 0
$$
- Answer: $\boxed{0}$

---

#### Part (n):
$$
1 \times 4115 = \_\_\_\_\_
$$
- Property Used: Identity Property of Multiplication ($a \times 1 = a$).
- Solution: Multiplying any number by 1 gives the same number. Therefore:
$$
1 \times 4115 = 4115
$$
- Answer: $\boxed{4115}$

---

#### Part (o):
$$
5358 \times \_\_\_\_\_ = 0
$$
- Property Used: Zero Property of Multiplication ($a \times 0 = 0$).
- Solution: Multiplying any number by 0 gives 0. Therefore:
$$
5358 \times 0 = 0
$$
- Answer: $\boxed{0}$

---

#### Part (p):
$$
0 \times 23 \times 126 = \_\_\_\_\_
$$
- Property Used: Zero Property of Multiplication ($a \times 0 = 0$).
- Solution: Multiplying any number by 0 gives 0. Therefore:
$$
0 \times 23 \times 126 = 0
$$
- Answer: $\boxed{0}$

---

#### Part (q):
$$
143 \times 82 \times 1 \times 0 = \_\_\_\_\_
$$
- Property Used: Zero Property of Multiplication ($a \times 0 = 0$).
- Solution: Multiplying any number by 0 gives 0. Therefore:
$$
143 \times 82 \times 1 \times 0 = 0
$$
- Answer: $\boxed{0}$

---

Section 2: Fill in the blanks

#### Part (a):
$$
217 \times 10 = \_\_\_\_\_
$$
- Solution: Multiply 217 by 10.
$$
217 \times 10 = 2170
$$
- Answer: $\boxed{2170}$

---

#### Part (b):
$$
368 \times 10 = \_\_\_\_\_
$$
- Solution: Multiply 368 by 10.
$$
368 \times 10 = 3680
$$
- Answer: $\boxed{3680}$

---

#### Part (c):
$$
\text{A box has } 627 \text{ pouches. Each pouch has } 10 \text{ pens. How many pens in all does the box have?}
$$
- Solution: Multiply the number of pouches by the number of pens per pouch.
$$
627 \times 10 = 6270
$$
- Answer: $\boxed{6270}$

---

#### Part (d):
$$
17 \times 100 = \_\_\_\_\_
$$
- Solution: Multiply 17 by 100.
$$
17 \times 100 = 1700
$$
- Answer: $\boxed{1700}$

---

#### Part (e):
$$
22 \times 100 = \_\_\_\_\_
$$
- Solution: Multiply 22 by 100.
$$
22 \times 100 = 2200
$$
- Answer: $\boxed{2200}$

---

#### Part (f):
$$
\text{A packet has } 100 \text{ pins. How many pins will } 29 \text{ such packets have?}
$$
- Solution: Multiply the number of pins per packet by the number of packets.
$$
100 \times 29 = 2900
$$
- Answer: $\boxed{2900}$

---

#### Part (g):
$$
6 \times 1000 = \_\_\_\_\_
$$
- Solution: Multiply 6 by 1000.
$$
6 \times 1000 = 6000
$$
- Answer: $\boxed{6000}$

---

#### Part (h):
$$
3 \times 1000 = \_\_\_\_\_
$$
- Solution: Multiply 3 by 1000.
$$
3 \times 1000 = 3000
$$
- Answer: $\boxed{3000}$

---

#### Part (i):
$$
\text{A train can carry } 1000 \text{ passengers in a trip. How many passengers can it carry in } 5 \text{ trips?}
$$
- Solution: Multiply the number of passengers per trip by the number of trips.
$$
1000 \times 5 = 5000
$$
- Answer: $\boxed{5000}$

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Final Answers:

1. (a) $\boxed{4312}$, (b) $\boxed{2108}$, (c) $\boxed{2482}$, (d) $\boxed{3322}$, (e) $\boxed{4327}$, (f) $\boxed{7672}$, (g) $\boxed{4642}$, (h) $\boxed{3139, 2563}$, (i) $\boxed{3972}$, (j) $\boxed{4616}$, (k) $\boxed{1}$, (l) $\boxed{0}$, (m) $\boxed{0}$, (n) $\boxed{4115}$, (o) $\boxed{0}$, (p) $\boxed{0}$, (q) $\boxed{0}$
2. (a) $\boxed{2170}$, (b) $\boxed{3680}$, (c) $\boxed{6270}$, (d) $\boxed{1700}$, (e) $\boxed{2200}$, (f) $\boxed{2900}$, (g) $\boxed{6000}$, (h) $\boxed{3000}$, (i) $\boxed{5000}$

Boxed Final Answer:
$$
\boxed{\text{See detailed solutions above.}}
$$