Mean Mode Median Worksheets | Mean Mode Median and Range Worksheets - Free Printable

Let’s solve each problem one by one. For each set of numbers, we’ll find:

- Mean: Add all numbers, then divide by how many numbers there are.
- Median: Put numbers in order from smallest to largest, then pick the middle number (or average the two middle ones if there’s an even count).
- Mode: The number that appears most often.
- Range: Biggest number minus smallest number.

We’ll go step by step for each question.

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Problem 1: 7, 6, 9, 8, 6, 7, 7, 7, 6

Step 1: Order them → 6, 6, 6, 7, 7, 7, 7, 8, 9
Count = 9 numbers

→ Mean: (6+6+6+7+7+7+7+8+9) = 63 → 63 ÷ 9 = 7
→ Median: Middle is 5th number → 7
→ Mode: 7 appears 4 times → 7
→ Range: 9 - 6 = 3

✔ Answer: Mean=7, Median=7, Mode=7, Range=3

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Problem 2: 8, 3, 6, 9, 7, 9

Order: 3, 6, 7, 8, 9, 9
Count = 6

→ Mean: (3+6+7+8+9+9) = 42 → 42 ÷ 6 = 7
→ Median: Average of 3rd and 4th → (7+8)/2 = 7.5
→ Mode: 9 appears twice → 9
→ Range: 9 - 3 = 6

✔ Answer: Mean=7, Median=7.5, Mode=9, Range=6

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Problem 3: 8, 9, 9, 8, 2, 3, 2, 3, 1

Order: 1, 2, 2, 3, 3, 8, 8, 9, 9
Count = 9

→ Mean: (1+2+2+3+3+8+8+9+9) = 45 → 45 ÷ 9 = 5
→ Median: 5th number → 3
→ Mode: 2, 3, 8, 9 each appear twice? Wait — let’s check:
Actually: 1(1), 2(2), 3(2), 8(2), 9(2) → multiple modes? But usually we list all or say “no unique mode”. However, since all repeated same amount, maybe no single mode? But wait — actually, they all appear exactly twice except 1 which appears once. So modes are 2,3,8,9? That’s unusual. Let me recount:

Original: 8,9,9,8,2,3,2,3,1 →
1:1, 2:2, 3:2, 8:2, 9:2 → yes, four numbers tied at 2 appearances. In school math, sometimes they expect you to list all, or say “multiple modes”. But looking at typical worksheets, they might accept listing all. However, let’s see — perhaps I made a mistake? No, it’s correct.

But to be safe — in many curricula, if more than one number ties for most frequent, you list them all as modes. So Mode = 2, 3, 8, 9? That seems messy. Wait — let me double-check original data: “8 ,9 ,9 ,8 ,2 ,3 ,2 ,3 ,1” — yes, that’s right.

Alternatively, maybe the worksheet expects only one mode? But technically, this has multiple modes. Hmm. Let’s proceed with what’s mathematically correct: modes are 2, 3, 8, 9.

But wait — perhaps I miscounted? Let’s write frequencies:

Number | Count
1 → 1
2 → 2
3 → 2
8 → 2
9 → 2

Yes — so four modes. But in practice, some teachers might say “no mode” if no single number stands out, but that’s not accurate. Actually, standard definition: mode is any value that occurs most frequently. Since 2,3,8,9 all occur twice (which is max), they are all modes.

However, looking ahead — maybe the worksheet assumes single mode? Let’s hold on and come back if needed. For now, I’ll note it.

→ Range: 9 - 1 = 8

So: Mean=5, Median=3, Mode=2,3,8,9 (but perhaps write as "multiple" or list them), Range=8

Wait — let me check online or standard approach. Actually, in elementary/middle school, sometimes they avoid such cases. Maybe I should recheck the problem? Original says: “8 ,9 ,9 ,8 ,2 ,3 ,2 ,3 ,1” — yes.

Perhaps the intended answer is to list all modes? Or maybe I made error? Another thought: maybe “mode” here means the most frequent, and if tie, pick one? No, that’s wrong.

I think for accuracy, I’ll state: Mode = 2, 3, 8, 9 (all appear twice)

But to match typical worksheet expectations, perhaps they expect us to say “no mode” if no single mode? No — that’s incorrect. Let’s keep it as multiple modes.

Actually, upon second thought — in many standardized tests and worksheets, if there is a tie, they still consider those values as modes. So I’ll write: Mode = 2, 3, 8, 9

But let’s move on and see other problems — maybe this is intentional.

For now:

✔ Answer: Mean=5, Median=3, Mode=2,3,8,9, Range=8

But to make it clean, perhaps write Mode as “2, 3, 8, 9”

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Problem 4: 2, 4, 8, 3, 6, 7

Order: 2, 3, 4, 6, 7, 8
Count = 6

→ Mean: (2+3+4+6+7+8)=30 → 30÷6=5
→ Median: (4+6)/2 = 5
→ Mode: All appear once → no mode? Or sometimes written as “none”
In math, if no number repeats, there is no mode.
→ Range: 8-2=6

✔ Answer: Mean=5, Median=5, Mode=none, Range=6

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Problem 5: 6, 3, 9, 5, 7, 2, 5, 5, 3

Order: 2, 3, 3, 5, 5, 5, 6, 7, 9
Count = 9

→ Mean: (2+3+3+5+5+5+6+7+9)=45 → 45÷9=5
→ Median: 5th number → 5
→ Mode: 5 appears 3 times → 5
→ Range: 9-2=7

✔ Answer: Mean=5, Median=5, Mode=5, Range=7

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Problem 6: 8, 9, 5, 8, 3, 7, 3, 9, 2

Order: 2, 3, 3, 5, 7, 8, 8, 9, 9
Count = 9

→ Mean: (2+3+3+5+7+8+8+9+9)=54 → 54÷9=6
→ Median: 5th number → 7
→ Mode: 3,8,9 each appear twice? Let’s see:
2:1, 3:2, 5:1, 7:1, 8:2, 9:2 → so modes are 3,8,9
→ Range: 9-2=7

✔ Answer: Mean=6, Median=7, Mode=3,8,9, Range=7

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Problem 7: 9, 3, 8, 5, 2, 9

Order: 2, 3, 5, 8, 9, 9
Count = 6

→ Mean: (2+3+5+8+9+9)=36 → 36÷6=6
→ Median: (5+8)/2 = 6.5
→ Mode: 9 appears twice → 9
→ Range: 9-2=7

✔ Answer: Mean=6, Median=6.5, Mode=9, Range=7

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Problem 8: 8, 2, 3, 4, 4, 3

Order: 2, 3, 3, 4, 4, 8
Count = 6

→ Mean: (2+3+3+4+4+8)=24 → 24÷6=4
→ Median: (3+4)/2 = 3.5
→ Mode: 3 and 4 both appear twice → 3,4
→ Range: 8-2=6

✔ Answer: Mean=4, Median=3.5, Mode=3,4, Range=6

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Problem 9: 8, 6, 2, 5, 7, 8

Order: 2, 5, 6, 7, 8, 8
Count = 6

→ Mean: (2+5+6+7+8+8)=36 → 36÷6=6
→ Median: (6+7)/2 = 6.5
→ Mode: 8 appears twice → 8
→ Range: 8-2=6

✔ Answer: Mean=6, Median=6.5, Mode=8, Range=6

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Problem 10: 5, 3, 9, 7, 2, 4

Order: 2, 3, 4, 5, 7, 9
Count = 6

→ Mean: (2+3+4+5+7+9)=30 → 30÷6=5
→ Median: (4+5)/2 = 4.5
→ Mode: All appear once → no mode
→ Range: 9-2=7

✔ Answer: Mean=5, Median=4.5, Mode=none, Range=7

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Now, compiling all answers clearly:

Note: For problems with multiple modes, I listed them. If your teacher prefers to write "multiple" or something else, adjust accordingly. But mathematically, listing all is correct.

Also, for "no mode", I wrote "none".

Final Answers:

1) Mean=7, Median=7, Mode=7, Range=3
2) Mean=7, Median=7.5, Mode=9, Range=6
3) Mean=5, Median=3, Mode=2,3,8,9, Range=8
4) Mean=5, Median=5, Mode=none, Range=6
5) Mean=5, Median=5, Mode=5, Range=7
6) Mean=6, Median=7, Mode=3,8,9, Range=7
7) Mean=6, Median=6.5, Mode=9, Range=7
8) Mean=4, Median=3.5, Mode=3,4, Range=6
9) Mean=6, Median=6.5, Mode=8, Range=6
10) Mean=5, Median=4.5, Mode=none, Range=7

Wait — for Problem 3, having four modes might be unexpected. Let me verify the data again: “8 ,9 ,9 ,8 ,2 ,3 ,2 ,3 ,1” — yes, that’s nine numbers. Frequencies: 1:1, 2:2, 3:2, 8:2, 9:2. So indeed, four numbers tied for highest frequency. In some contexts, they might say “bimodal” or “multimodal”, but for this level, perhaps the worksheet expects us to list all or recognize it's multimodal. I think it's fine.

Similarly for Problem 6 and 8.

I think these are correct.

Final Answer:

1) Mean: 7, Median: 7, Mode: 7, Range: 3
2) Mean: 7, Median: 7.5, Mode: 9, Range: 6
3) Mean: 5, Median: 3, Mode: 2, 3, 8, 9, Range: 8
4) Mean: 5, Median: 5, Mode: none, Range: 6
5) Mean: 5, Median: 5, Mode: 5, Range: 7
6) Mean: 6, Median: 7, Mode: 3, 8, 9, Range: 7
7) Mean: 6, Median: 6.5, Mode: 9, Range: 7
8) Mean: 4, Median: 3.5, Mode: 3, 4, Range: 6
9) Mean: 6, Median: 6.5, Mode: 8, Range: 6
10) Mean: 5, Median: 4.5, Mode: none, Range: 7