This worksheet challenges students to apply statistical concepts to real-world scenarios like pizza sales and birthday money.
Math worksheet with word problems for calculating mean, median, mode, and range from number sets.
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Step-by-step solution for: Mean Median Mode & Range Worksheets | Free - Distance Learning ...
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Show Answer Key & Explanations
Step-by-step solution for: Mean Median Mode & Range Worksheets | Free - Distance Learning ...
Let's solve each problem step by step and explain the solution.
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At Oliver's Pizza Palace in the 6 hours they were open, they sold the following number of pizzas: 55 pepperoni, 57 sausage, 50 cheese, 51 mushrooms, 61 anchovies, and 50 pineapple. Determine the mean (rounded to the nearest tenth), median, mode, and range of pizzas sold.
#### Step 1: List the data
The numbers are:
55, 57, 50, 51, 61, 50
#### Step 2: Find the Mean
Add all the numbers and divide by the count.
Sum = 55 + 57 + 50 + 51 + 61 + 50 =
= (55 + 57) = 112
+ 50 = 162
+ 51 = 213
+ 61 = 274
+ 50 = 324
Count = 6
Mean = 324 ÷ 6 = 54.0
#### Step 3: Find the Median
Order the numbers from least to greatest:
50, 50, 51, 55, 57, 61
There are 6 numbers (even), so median is average of 3rd and 4th:
(51 + 55) ÷ 2 = 106 ÷ 2 = 53.0
#### Step 4: Find the Mode
The number that appears most often:
50 appears twice, others appear once → 50
#### Step 5: Find the Range
Range = Max – Min = 61 – 50 = 11
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✔ Answer 1:
- Mean: 54.0
- Median: 53.0
- Mode: 50
- Range: 11
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Jerry was counting the money he received for his birthday. From his aunt he received $9. From his uncle he received $9. His best friends gave him $22, $23, and $22. And his sister gave him $7. Determine the mean (rounded to the nearest tenth), median, mode, and range of the money he received.
#### Step 1: List the amounts:
$9, $9, $22, $23, $22, $7
#### Step 2: Order them:
7, 9, 9, 22, 22, 23
#### Step 3: Find the Mean
Sum = 7 + 9 + 9 + 22 + 22 + 23 =
= 7 + 9 = 16
+ 9 = 25
+ 22 = 47
+ 22 = 69
+ 23 = 92
Count = 6
Mean = 92 ÷ 6 ≈ 15.3 (rounded to nearest tenth)
#### Step 4: Find the Median
Ordered: 7, 9, 9, 22, 22, 23
Middle two: 9 and 22 → (9 + 22)/2 = 31/2 = 15.5
#### Step 5: Find the Mode
Both 9 and 22 appear twice → Bimodal: 9 and 22
But typically we list both if there are multiple modes.
#### Step 6: Find the Range
Max – Min = 23 – 7 = 16
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✔ Answer 2:
- Mean: 15.3
- Median: 15.5
- Mode: 9 and 22
- Range: 16
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Dave counted the number of times people sharpened their pencils in class for a week. He counted: 4, 13, 4, 1, 14 and 11. Determine the mean (rounded to the nearest tenth), median, mode, and range of the numbers.
#### Step 1: Data: 4, 13, 4, 1, 14, 11
#### Step 2: Order: 1, 4, 4, 11, 13, 14
#### Step 3: Mean
Sum = 1 + 4 + 4 + 11 + 13 + 14 =
= 1+4=5; +4=9; +11=20; +13=33; +14=47
Count = 6
Mean = 47 ÷ 6 ≈ 7.8 (rounded to nearest tenth)
#### Step 4: Median
Middle two: 4 and 11 → (4 + 11)/2 = 15/2 = 7.5
#### Step 5: Mode
4 appears twice, others once → 4
#### Step 6: Range
Max – Min = 14 – 1 = 13
---
✔ Answer 3:
- Mean: 7.8
- Median: 7.5
- Mode: 4
- Range: 13
---
Victor was selling chocolate for a school fund raiser. On the first week he sold 75. On the second week he sold 67. On the third week he sold 75. On the fourth week he sold 70 and on the last week he sold 68. Determine the mean (rounded to the nearest tenth), median, mode, and range of the chocolate bars sold.
#### Step 1: Data: 75, 67, 75, 70, 68
#### Step 2: Order: 67, 68, 70, 75, 75
#### Step 3: Mean
Sum = 67 + 68 + 70 + 75 + 75 =
= 67+68=135; +70=205; +75=280; +75=355
Count = 5
Mean = 355 ÷ 5 = 71.0
#### Step 4: Median
Middle number (3rd): 70
#### Step 5: Mode
75 appears twice → 75
#### Step 6: Range
Max – Min = 75 – 67 = 8
---
✔ Answer 4:
- Mean: 71.0
- Median: 70
- Mode: 75
- Range: 8
---
During the first 6 hours of the fair there were the following number of customers: 58, 56, 62, 55, 49 and 48. Determine the mean (rounded to the nearest tenth), median, mode, and range of the number of customers.
#### Step 1: Data: 58, 56, 62, 55, 49, 48
#### Step 2: Order: 48, 49, 55, 56, 58, 62
#### Step 3: Mean
Sum = 48 + 49 + 55 + 56 + 58 + 62 =
= 48+49=97; +55=152; +56=208; +58=266; +62=328
Count = 6
Mean = 328 ÷ 6 ≈ 54.7 (rounded to nearest tenth)
#### Step 4: Median
Middle two: 55 and 56 → (55 + 56)/2 = 111/2 = 55.5
#### Step 5: Mode
All numbers appear once → No mode
#### Step 6: Range
Max – Min = 62 – 48 = 14
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✔ Answer 5:
- Mean: 54.7
- Median: 55.5
- Mode: No mode
- Range: 14
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1. Mean: 54.0, Median: 53.0, Mode: 50, Range: 11
2. Mean: 15.3, Median: 15.5, Mode: 9 and 22, Range: 16
3. Mean: 7.8, Median: 7.5, Mode: 4, Range: 13
4. Mean: 71.0, Median: 70, Mode: 75, Range: 8
5. Mean: 54.7, Median: 55.5, Mode: No mode, Range: 14
Let me know if you'd like this formatted for printing or submission!
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Problem 1:
At Oliver's Pizza Palace in the 6 hours they were open, they sold the following number of pizzas: 55 pepperoni, 57 sausage, 50 cheese, 51 mushrooms, 61 anchovies, and 50 pineapple. Determine the mean (rounded to the nearest tenth), median, mode, and range of pizzas sold.
#### Step 1: List the data
The numbers are:
55, 57, 50, 51, 61, 50
#### Step 2: Find the Mean
Add all the numbers and divide by the count.
Sum = 55 + 57 + 50 + 51 + 61 + 50 =
= (55 + 57) = 112
+ 50 = 162
+ 51 = 213
+ 61 = 274
+ 50 = 324
Count = 6
Mean = 324 ÷ 6 = 54.0
#### Step 3: Find the Median
Order the numbers from least to greatest:
50, 50, 51, 55, 57, 61
There are 6 numbers (even), so median is average of 3rd and 4th:
(51 + 55) ÷ 2 = 106 ÷ 2 = 53.0
#### Step 4: Find the Mode
The number that appears most often:
50 appears twice, others appear once → 50
#### Step 5: Find the Range
Range = Max – Min = 61 – 50 = 11
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✔ Answer 1:
- Mean: 54.0
- Median: 53.0
- Mode: 50
- Range: 11
---
Problem 2:
Jerry was counting the money he received for his birthday. From his aunt he received $9. From his uncle he received $9. His best friends gave him $22, $23, and $22. And his sister gave him $7. Determine the mean (rounded to the nearest tenth), median, mode, and range of the money he received.
#### Step 1: List the amounts:
$9, $9, $22, $23, $22, $7
#### Step 2: Order them:
7, 9, 9, 22, 22, 23
#### Step 3: Find the Mean
Sum = 7 + 9 + 9 + 22 + 22 + 23 =
= 7 + 9 = 16
+ 9 = 25
+ 22 = 47
+ 22 = 69
+ 23 = 92
Count = 6
Mean = 92 ÷ 6 ≈ 15.3 (rounded to nearest tenth)
#### Step 4: Find the Median
Ordered: 7, 9, 9, 22, 22, 23
Middle two: 9 and 22 → (9 + 22)/2 = 31/2 = 15.5
#### Step 5: Find the Mode
Both 9 and 22 appear twice → Bimodal: 9 and 22
But typically we list both if there are multiple modes.
#### Step 6: Find the Range
Max – Min = 23 – 7 = 16
---
✔ Answer 2:
- Mean: 15.3
- Median: 15.5
- Mode: 9 and 22
- Range: 16
---
Problem 3:
Dave counted the number of times people sharpened their pencils in class for a week. He counted: 4, 13, 4, 1, 14 and 11. Determine the mean (rounded to the nearest tenth), median, mode, and range of the numbers.
#### Step 1: Data: 4, 13, 4, 1, 14, 11
#### Step 2: Order: 1, 4, 4, 11, 13, 14
#### Step 3: Mean
Sum = 1 + 4 + 4 + 11 + 13 + 14 =
= 1+4=5; +4=9; +11=20; +13=33; +14=47
Count = 6
Mean = 47 ÷ 6 ≈ 7.8 (rounded to nearest tenth)
#### Step 4: Median
Middle two: 4 and 11 → (4 + 11)/2 = 15/2 = 7.5
#### Step 5: Mode
4 appears twice, others once → 4
#### Step 6: Range
Max – Min = 14 – 1 = 13
---
✔ Answer 3:
- Mean: 7.8
- Median: 7.5
- Mode: 4
- Range: 13
---
Problem 4:
Victor was selling chocolate for a school fund raiser. On the first week he sold 75. On the second week he sold 67. On the third week he sold 75. On the fourth week he sold 70 and on the last week he sold 68. Determine the mean (rounded to the nearest tenth), median, mode, and range of the chocolate bars sold.
#### Step 1: Data: 75, 67, 75, 70, 68
#### Step 2: Order: 67, 68, 70, 75, 75
#### Step 3: Mean
Sum = 67 + 68 + 70 + 75 + 75 =
= 67+68=135; +70=205; +75=280; +75=355
Count = 5
Mean = 355 ÷ 5 = 71.0
#### Step 4: Median
Middle number (3rd): 70
#### Step 5: Mode
75 appears twice → 75
#### Step 6: Range
Max – Min = 75 – 67 = 8
---
✔ Answer 4:
- Mean: 71.0
- Median: 70
- Mode: 75
- Range: 8
---
Problem 5:
During the first 6 hours of the fair there were the following number of customers: 58, 56, 62, 55, 49 and 48. Determine the mean (rounded to the nearest tenth), median, mode, and range of the number of customers.
#### Step 1: Data: 58, 56, 62, 55, 49, 48
#### Step 2: Order: 48, 49, 55, 56, 58, 62
#### Step 3: Mean
Sum = 48 + 49 + 55 + 56 + 58 + 62 =
= 48+49=97; +55=152; +56=208; +58=266; +62=328
Count = 6
Mean = 328 ÷ 6 ≈ 54.7 (rounded to nearest tenth)
#### Step 4: Median
Middle two: 55 and 56 → (55 + 56)/2 = 111/2 = 55.5
#### Step 5: Mode
All numbers appear once → No mode
#### Step 6: Range
Max – Min = 62 – 48 = 14
---
✔ Answer 5:
- Mean: 54.7
- Median: 55.5
- Mode: No mode
- Range: 14
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✔ Final Answers Summary:
1. Mean: 54.0, Median: 53.0, Mode: 50, Range: 11
2. Mean: 15.3, Median: 15.5, Mode: 9 and 22, Range: 16
3. Mean: 7.8, Median: 7.5, Mode: 4, Range: 13
4. Mean: 71.0, Median: 70, Mode: 75, Range: 8
5. Mean: 54.7, Median: 55.5, Mode: No mode, Range: 14
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Parent Tip: Review the logic above to help your child master the concept of mean median mode range word problems worksheet.