Fraction measurement worksheet for learning how to combine measuring cups to achieve specific amounts.

Let's solve this step-by-step.

We are given a standard set of measuring cups:
- 1 cup (1 c.)
- ½ cup (½ c.)
- ⅓ cup (⅓ c.)
- ¼ cup (¼ c.)

There is no ⅔ cup or ¾ cup, so we must combine these cups to measure the required amounts.

We need to determine which combination(s) of these measuring cups add up to each listed amount. Then, we place a check mark under the cup(s) used.

---

Step 1: Understand what combinations we can make

Let’s look at possible combinations:

- 1 c. = 1 c.
- ½ c. = ½ c.
- ⅓ c. = ⅓ c.
- ¼ c. = ¼ c.

Now let’s find ways to make other amounts using only these four.

---

Now go through each amount:

#### 1) 1 c.
- Use 1 c. cup directly.
✔ Check: 1 c.

| Amount | 1 c. | ½ c. | ⅓ c. | ¼ c. |
|--------|------|------|------|------|
| 1) 1 c. | ✔ | | | |

---

#### 2) 3/4 c.
We don’t have a ¾ cup, but:
- ½ + ¼ = ¾
✔ Use ½ c. and ¼ c.

| Amount | 1 c. | ½ c. | ⅓ c. | ¼ c. |
|--------|------|------|------|------|
| 2) 3/4 c. | | ✔ | | ✔ |

---

#### 3) ½ c.
Use the ½ c. cup directly.
✔ Check: ½ c.

| Amount | 1 c. | ½ c. | ⅓ c. | ¼ c. |
|--------|------|------|------|------|
| 3) ½ c. | | ✔ | | |

---

#### 4) 2/3 c.
We don’t have ⅔ cup. Can we make it?

Try:
- ⅓ + ⅓ = ⅔ → But we only have one ⅓ cup.
So we cannot use two ⅓ cups unless we have two.

But we only have one ⅓ cup.

Wait — can we do something else?

Let’s try:
- ½ + ⅓ = 5/6 → too much
- ½ + ¼ = ¾ → too big
- ⅓ + ¼ = 7/12 → less than ½

No way to get exactly ⅔ with just one ⅓ cup?

Wait! Let's think differently.

Is there a way to subtract? No — we're measuring by filling cups, not pouring out.

So we can only add.

Can we use multiple uses of same cup? Probably not — we assume we have one of each.

So if we only have one ⅓ cup, we can't make ⅔ from two ⅓s.

But maybe another way?

Try:
- ½ + ⅓ = 5/6 ≈ 0.833
- ⅓ + ¼ = 7/12 ≈ 0.583
- ½ + ¼ = ¾ = 0.75
None equal ⅔ ≈ 0.666...

Wait: Is there a way to make ⅔ using these?

Actually, no, unless we use the 1 c. cup and pour out excess — but the problem says "putting the measuring cups together" — so likely only adding.

So perhaps we cannot measure ⅔ c. exactly with just these cups?

But that seems odd.

Wait — let's reconsider.

Maybe we can use the 1 c. cup and subtract? But the instructions say "putting the measuring cups together", implying adding.

But in cooking, sometimes you use larger cups and pour out.

But here, since we're told to "put the measuring cups together to get different measurements", it implies combining them.

So we can only add.

Let’s test: Can we make ⅔?

- ⅓ + ⅓ = ⅔ → but only one ⅓ cup available → ✘
- ½ + ¼ = ¾ = 0.75 > ⅔ ≈ 0.666 → too big
- ½ + ⅓ = 5/6 ≈ 0.833 → too big
- ¼ + ⅓ = 7/12 ≈ 0.583 < ⅔
- ½ + ¼ + ⅓ = 13/12 > 1 → too big

So cannot make ⅔ c. exactly using only one of each cup.

But wait — maybe the problem allows using the same cup more than once?

But the image shows only one of each.

Alternatively, maybe we can use fractional parts? No — we’re limited to the cups we have.

Hmm.

But look at item #9: 1 2/3 c.

That would be 1 + ⅔ → so if we can't make ⅔, how can we make 1 2/3?

Wait — maybe we can make ⅔ using ½ + ⅓ - ¼? But subtraction isn’t allowed.

Alternatively, maybe we can use the 1 c. cup and then remove ⅓? But again, not allowed.

Wait — perhaps we can use multiple uses of the ⅓ cup? But we only have one.

Unless the problem assumes we have multiple copies of each cup.

But the image shows only one of each.

Wait — actually, the image has four cups shown: 1 c., ½ c., ⅓ c., ¼ c.

So likely, we have one of each.

So we can't use ⅓ twice.

Therefore, we cannot make ⅔ c. exactly.

But that seems problematic.

Wait — let’s check if there's a trick.

Another idea: Maybe use 1 c. and pour out ⅓ c.? But again, not mentioned.

The problem says "putting the measuring cups together" — so likely only adding.

But let’s see what others suggest.

Wait — maybe 2/3 c. can be made as:

We know:
- 1 c. = 1
- ½ = 0.5
- ⅓ ≈ 0.333
- ¼ = 0.25

Try:
- ½ + ⅓ = 5/6 ≈ 0.833
- ½ + ¼ = 0.75
- ⅓ + ¼ = 0.583
- ½ + ⅓ + ¼ = 13/12 ≈ 1.083

No ⅔.

Wait — is there a way to make ⅔ using two ⅓ cups? But we only have one.

So unless we have multiple, no.

But perhaps the problem expects us to realize that we cannot make ⅔?

But that would mean leaving blank.

But let’s check online or standard practice.

In real life, people often use:
- ½ + ⅓ = 5/6 → not helpful
- Or they might use ½ + ¼ = ¾, close but not ⅔

But wait — is there a way?

Wait — perhaps use 1 c. and remove ⅓ c.? But again, not allowed.

Alternatively, maybe the problem allows using the ⅓ cup twice — but we only have one.

Hmm.

Wait — perhaps I'm missing something.

Let me check item 9: 1 2/3 c.

That’s 1 + ⅔.

If we can’t make ⅔, we can’t make this.

But maybe we can make it as:

- 1 c. + ⅓ c. = 1 ⅓ → not enough
- 1 c. + ½ c. = 1 ½ → too much
- 1 c. + ⅓ c. + ¼ c. = 1 + 0.333 + 0.25 = 1.583 → too much

Wait — 1 2/3 = 5/3 ≈ 1.666...

Can we make that?

Try:
- 1 c. + ½ c. + ⅓ c. = 1 + 0.5 + 0.333 = 1.833 → too big
- 1 c. + ½ c. + ¼ c. = 1.75 → still too big
- 1 c. + ⅓ c. = 1.333 → too small
- 1 c. + ⅓ c. + ¼ c. = 1.583 → still less than 1.666
- 1 c. + ½ c. + ⅓ c. = 1.833 → too big

No.

Wait — what about 1 c. + ½ c. + ⅓ c. - ¼ c.? But subtraction not allowed.

This is getting messy.

Wait — maybe I misread.

Let’s go back.

Perhaps the key is that we can use multiple copies of the same cup — but the image shows only one of each.

But in reality, you might have multiple.

But the problem says “a standard set” — so probably one of each.

Wait — let’s look for known combinations.

Standard measuring cup combinations:

- ¾ c. = ½ + ¼ → yes
- ⅔ c. = ? → not possible with ½, ⅓, ¼
- But ⅔ = 1/2 + 1/3 - 1/6 → but no 1/6 cup

Not helpful.

Wait — maybe the problem does not require exact? But it says “measure the amount”.

Alternatively, maybe we can use the 1 c. cup and fill it, then pour into smaller cups?

But again, not implied.

Wait — perhaps we can use the ⅓ cup twice — but we only have one.

Unless we are allowed to use it more than once.

But the image shows only one.

I think the intended answer is that we can combine cups, and some amounts require multiple uses.

But since we have only one of each, we can't use ⅓ twice.

Wait — perhaps the 1 c. cup is the largest, and we can use it with others.

But let’s try to solve the ones we can.

Let’s skip 4 for now.

---

#### 5) 1/3 c.
Use the ⅓ c. cup directly.
✔ Check: ⅓ c.

| Amount | 1 c. | ½ c. | ⅓ c. | ¼ c. |
|--------|------|------|------|------|
| 5) 1/3 c. | | | ✔ | |

---

#### 6) ¼ c.
Use ¼ c. cup directly.
✔ Check: ¼ c.

| Amount | 1 c. | ½ c. | ⅓ c. | ¼ c. |
|--------|------|------|------|------|
| 6) ¼ c. | | | | ✔ |

---

#### 7) 1 1/3 c.
This is 1 + ⅓ = 1 ⅓ c.

We can use:
- 1 c. + ⅓ c. = 1 ⅓

✔ So use 1 c. and ⅓ c.

| Amount | 1 c. | ½ c. | ⅓ c. | ¼ c. |
|--------|------|------|------|------|
| 7) 1 1/3 c. | ✔ | | ✔ | |

---

#### 8) 2 ¾ c.
This is 2 + ¾ = 2.75 c.

We can break it down:
- 2 c. = 1 c. + 1 c. → but we only have one 1 c. cup.
So we need to use 1 c. twice.

But we only have one.

So unless we can use the 1 c. cup twice, we can't.

But the problem says "putting the measuring cups together" — does that allow using the same cup twice?

Possibly.

For example, you could fill the 1 c. cup twice and add.

So likely, yes, we can use the same cup multiple times.

Similarly, we can use the ½ cup twice, etc.

So assume we can reuse cups.

Then:

#### 8) 2 ¾ c. = 2 + ¾
- 2 c. = 1 c. + 1 c. → use 1 c. twice
- ¾ c. = ½ + ¼

So total:
- Use 1 c. twice
- Use ½ c.
- Use ¼ c.

But the table only has one column per cup — so we put a check under each cup used, regardless of how many times.

So check:
- 1 c.
- ½ c.
- ¼ c.

(We don’t have a column for “use twice”, so just check the cup.)

✔ So:

| Amount | 1 c. | ½ c. | ⅓ c. | ¼ c. |
|--------|------|------|------|------|
| 8) 2 ¾ c. | ✔ | ✔ | | ✔ |

---

#### 9) 1 2/3 c. = 1 + 2/3

We need ⅔ c.

But ⅔ = ?

Can we make ⅔?

Try:
- ½ + ⅓ = 5/6 ≈ 0.833 > ⅔ ≈ 0.666
- ½ + ¼ = ¾ = 0.75 > ⅔
- ⅓ + ¼ = 7/12 ≈ 0.583 < ⅔

But ⅔ = 2/3

Note: 2/3 = 4/6

And ½ = 3/6, ⅓ = 2/6, ¼ = 1.5/6 — not helpful.

Wait — can we use:
- ½ + ⅓ = 5/6
- 5/6 - 1/6 = 4/6 = 2/3 — but no 1/6 cup.

Alternatively, use 1 c. and remove ⅓ c. — but not allowed.

Wait — another idea: Use 1 c. and pour into ⅓ c. cup until full, then pour out — but again, not measuring.

But perhaps we can use two ⅓ cups?

If we can use the ⅓ cup twice, then:
- ⅓ + ⅓ = ⅔

So use ⅓ c. twice.

Then:
- 1 2/3 c. = 1 c. + ⅓ c. + ⅓ c.

So use:
- 1 c.
- ⅓ c. (twice)

So check:
- 1 c.
- ⅓ c.

✔

| Amount | 1 c. | ½ c. | ⅓ c. | ¼ c. |
|--------|------|------|------|------|
| 9) 1 2/3 c. | ✔ | | ✔ | |

---

#### 10) 2 ½ c. = 2 + ½

We can do:
- 1 c. + 1 c. = 2 c.
- ½ c. = ½ c.

So use:
- 1 c. (twice)
- ½ c.

Check:
- 1 c.
- ½ c.

✔

| Amount | 1 c. | ½ c. | ⅓ c. | ¼ c. |
|--------|------|------|------|------|
| 10) 2 ½ c. | ✔ | ✔ | | |

---

Now back to 4) 2/3 c.

We want ⅔ c.

We can do:
- ⅓ + ⅓ = ⅔ → so use ⅓ cup twice.

Even though we only have one physical cup, we can use it twice.

So check ⅓ c.

✔

| Amount | 1 c. | ½ c. | ⅓ c. | ¼ c. |
|--------|------|------|------|------|
| 4) 2/3 c. | | | ✔ | |

---

Now let’s verify all:

Final Table:

| Amount | 1 c. | ½ c. | ⅓ c. | ¼ c. |
|--------|------|------|------|------|
| 1) 1 c. | ✔ | | | |
| 2) 3/4 c. | | ✔ | | ✔ |
| 3) ½ c. | | ✔ | | |
| 4) 2/3 c. | | | ✔ | |
| 5) 1/3 c. | | | ✔ | |
| 6) ¼ c. | | | | ✔ |
| 7) 1 1/3 c. | ✔ | | ✔ | |
| 8) 2 ¾ c. | ✔ | ✔ | | ✔ |
| 9) 1 2/3 c. | ✔ | | ✔ | |
| 10) 2 ½ c. | ✔ | ✔ | | |

---

Explanation:

- We assume we can use each measuring cup multiple times (e.g., fill the ⅓ cup twice).
- For 2/3 c., we use the ⅓ cup twice: ⅓ + ⅓ = ⅔.
- For 3/4 c., we use ½ + ¼.
- For 1 1/3 c., we use 1 + ⅓.
- For 1 2/3 c., we use 1 + ⅓ + ⅓.
- For 2 ¾ c., we use 1 + 1 + ½ + ¼.
- For 2 ½ c., we use 1 + 1 + ½.

All amounts are achievable using combinations of the standard measuring cups.

✔ The solution is complete.

---

Final Answer:

| Amount | 1 c. | ½ c. | ⅓ c. | ¼ c. |
|--------|------|------|------|------|
| 1) 1 c. | ✔ | | | |
| 2) 3/4 c. | | ✔ | | ✔ |
| 3) ½ c. | | ✔ | | |
| 4) 2/3 c. | | | ✔ | |
| 5) 1/3 c. | | | ✔ | |
| 6) ¼ c. | | | | ✔ |
| 7) 1 1/3 c. | ✔ | | ✔ | |
| 8) 2 ¾ c. | ✔ | ✔ | | ✔ |
| 9) 1 2/3 c. | ✔ | | ✔ | |
| 10) 2 ½ c. | ✔ | ✔ | | |