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Math worksheet for practicing mean, median, mode, and range calculations.

A math worksheet titled "Mean, Median, Mode, Range Practice" with 12 sets of numbers for calculating statistical measures, including spaces for answers.

A math worksheet titled "Mean, Median, Mode, Range Practice" with 12 sets of numbers for calculating statistical measures, including spaces for answers.

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Show Answer Key & Explanations Step-by-step solution for: Mean, Median, Mode, Range Worksheets PDF 3 Printable Worksheets ...
To solve the problem, we need to calculate the mean, median, mode, and range for each set of numbers. Let's go through each set step by step.

---

Set 1: 12, 15, 19, 97, 46, 88



#### Mean
The mean is the average of the numbers.
\[
\text{Mean} = \frac{\text{Sum of all numbers}}{\text{Number of values}}
\]
\[
\text{Sum} = 12 + 15 + 19 + 97 + 46 + 88 = 277
\]
\[
\text{Number of values} = 6
\]
\[
\text{Mean} = \frac{277}{6} \approx 46.17
\]

#### Median
The median is the middle value when the numbers are arranged in ascending order.
\[
\text{Ascending order: } 12, 15, 19, 46, 88, 97
\]
Since there are 6 numbers (an even count), the median is the average of the 3rd and 4th numbers:
\[
\text{Median} = \frac{19 + 46}{2} = \frac{65}{2} = 32.5
\]

#### Mode
The mode is the number that appears most frequently. In this set, all numbers appear once, so there is no mode.
\[
\text{Mode} = \text{None}
\]

#### Range
The range is the difference between the largest and smallest numbers.
\[
\text{Largest number} = 97
\]
\[
\text{Smallest number} = 12
\]
\[
\text{Range} = 97 - 12 = 85
\]

#### Final Answers for Set 1
\[
\text{Mean: } 46.17, \quad \text{Median: } 32.5, \quad \text{Mode: } \text{None}, \quad \text{Range: } 85
\]

---

Set 2: 33, 76, 37, 92, 88



#### Mean
\[
\text{Sum} = 33 + 76 + 37 + 92 + 88 = 326
\]
\[
\text{Number of values} = 5
\]
\[
\text{Mean} = \frac{326}{5} = 65.2
\]

#### Median
\[
\text{Ascending order: } 33, 37, 76, 88, 92
\]
The median is the middle value (3rd number):
\[
\text{Median} = 76
\]

#### Mode
All numbers appear once, so there is no mode.
\[
\text{Mode} = \text{None}
\]

#### Range
\[
\text{Largest number} = 92
\]
\[
\text{Smallest number} = 33
\]
\[
\text{Range} = 92 - 33 = 59
\]

#### Final Answers for Set 2
\[
\text{Mean: } 65.2, \quad \text{Median: } 76, \quad \text{Mode: } \text{None}, \quad \text{Range: } 59
\]

---

Set 3: 4, 12, 4, 77, 4, 4



#### Mean
\[
\text{Sum} = 4 + 12 + 4 + 77 + 4 + 4 = 105
\]
\[
\text{Number of values} = 6
\]
\[
\text{Mean} = \frac{105}{6} = 17.5
\]

#### Median
\[
\text{Ascending order: } 4, 4, 4, 4, 12, 77
\]
The median is the average of the 3rd and 4th numbers:
\[
\text{Median} = \frac{4 + 4}{2} = 4
\]

#### Mode
The mode is the number that appears most frequently. Here, 4 appears 4 times.
\[
\text{Mode} = 4
\]

#### Range
\[
\text{Largest number} = 77
\]
\[
\text{Smallest number} = 4
\]
\[
\text{Range} = 77 - 4 = 73
\]

#### Final Answers for Set 3
\[
\text{Mean: } 17.5, \quad \text{Median: } 4, \quad \text{Mode: } 4, \quad \text{Range: } 73
\]

---

Set 4: 102, 11, 46, 11



#### Mean
\[
\text{Sum} = 102 + 11 + 46 + 11 = 170
\]
\[
\text{Number of values} = 4
\]
\[
\text{Mean} = \frac{170}{4} = 42.5
\]

#### Median
\[
\text{Ascending order: } 11, 11, 46, 102
\]
The median is the average of the 2nd and 3rd numbers:
\[
\text{Median} = \frac{11 + 46}{2} = \frac{57}{2} = 28.5
\]

#### Mode
The mode is the number that appears most frequently. Here, 11 appears twice.
\[
\text{Mode} = 11
\]

#### Range
\[
\text{Largest number} = 102
\]
\[
\text{Smallest number} = 11
\]
\[
\text{Range} = 102 - 11 = 91
\]

#### Final Answers for Set 4
\[
\text{Mean: } 42.5, \quad \text{Median: } 28.5, \quad \text{Mode: } 11, \quad \text{Range: } 91
\]

---

Continuing with Sets 5–12



Following the same steps for each set, here are the final answers:

---

Set 5: 65, 65, 21, 65, 22


\[
\text{Mean: } 47.8, \quad \text{Median: } 65, \quad \text{Mode: } 65, \quad \text{Range: } 44
\]

Set 6: 44, 85, 73, 34, 34, 34


\[
\text{Mean: } 51.5, \quad \text{Median: } 39, \quad \text{Mode: } 34, \quad \text{Range: } 51
\]

Set 7: 22, 22, 26


\[
\text{Mean: } 23.33, \quad \text{Median: } 22, \quad \text{Mode: } 22, \quad \text{Range: } 4
\]

Set 8: 12, 15, 89, 97, 46, 88


\[
\text{Mean: } 57.83, \quad \text{Median: } 46, \quad \text{Mode: } \text{None}, \quad \text{Range: } 85
\]

Set 9: 33, 45, 61, 61, 43, 14


\[
\text{Mean: } 43.67, \quad \text{Median: } 44, \quad \text{Mode: } 61, \quad \text{Range: } 47
\]

Set 10: 32, 32, 32, 37, 39, 48


\[
\text{Mean: } 36.5, \quad \text{Median: } 34.5, \quad \text{Mode: } 32, \quad \text{Range: } 16
\]

Set 11: 15, 18, 16, 18, 19, 22


\[
\text{Mean: } 18, \quad \text{Median: } 18, \quad \text{Mode: } 18, \quad \text{Range: } 7
\]

Set 12: 23, 24, 29, 14, 16, 64


\[
\text{Mean: } 30.5, \quad \text{Median: } 23.5, \quad \text{Mode: } \text{None}, \quad \text{Range: } 50
\]

---

Final Answer


\[
\boxed{
\begin{array}{l}
\text{Set 1: Mean: } 46.17, \text{ Median: } 32.5, \text{ Mode: None}, \text{ Range: } 85 \\
\text{Set 2: Mean: } 65.2, \text{ Median: } 76, \text{ Mode: None}, \text{ Range: } 59 \\
\text{Set 3: Mean: } 17.5, \text{ Median: } 4, \text{ Mode: } 4, \text{ Range: } 73 \\
\text{Set 4: Mean: } 42.5, \text{ Median: } 28.5, \text{ Mode: } 11, \text{ Range: } 91 \\
\text{Set 5: Mean: } 47.8, \text{ Median: } 65, \text{ Mode: } 65, \text{ Range: } 44 \\
\text{Set 6: Mean: } 51.5, \text{ Median: } 39, \text{ Mode: } 34, \text{ Range: } 51 \\
\text{Set 7: Mean: } 23.33, \text{ Median: } 22, \text{ Mode: } 22, \text{ Range: } 4 \\
\text{Set 8: Mean: } 57.83, \text{ Median: } 46, \text{ Mode: None}, \text{ Range: } 85 \\
\text{Set 9: Mean: } 43.67, \text{ Median: } 44, \text{ Mode: } 61, \text{ Range: } 47 \\
\text{Set 10: Mean: } 36.5, \text{ Median: } 34.5, \text{ Mode: } 32, \text{ Range: } 16 \\
\text{Set 11: Mean: } 18, \text{ Median: } 18, \text{ Mode: } 18, \text{ Range: } 7 \\
\text{Set 12: Mean: } 30.5, \text{ Median: } 23.5, \text{ Mode: None}, \text{ Range: } 50 \\
\end{array}
}
\]
Parent Tip: Review the logic above to help your child master the concept of median mode range worksheet.
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