Pizzazz Book C Number Theory Factions Fractions and Decimals 67 | PDF - Free Printable

Let’s solve each problem step by step. We’ll do the math carefully, then match answers to letters and cross them out from the bottom string. The leftover letters will spell the answer to the riddle.

---

Problem 1:
① $\frac{2}{3} \times \frac{1}{5} = \frac{2 \times 1}{3 \times 5} = \frac{2}{15}$ → Not in answer box? Wait — let’s check all problems first. Maybe I made a mistake.

Wait — looking at the answer choices, none say $\frac{2}{15}$. Let me double-check the problem numbering and answers.

Actually, let’s go one by one and compute each:

---

① $\frac{2}{3} \times \frac{1}{5}$
= $\frac{2}{15}$ → Not listed? Hmm… maybe I misread. Let’s look again.

Wait — perhaps I should just calculate all and match.

But actually, let’s list all 17 problems with correct calculations.

---

① $\frac{2}{3} \times \frac{1}{5} = \frac{2}{15}$ → Not in answer key? That can’t be. Maybe typo? Or maybe I need to reduce or something? No, it’s already reduced.

Wait — let’s check the answer box again.

Answer box has:
R: $7\frac{1}{2}$, D: $3\frac{1}{3}$, G: $\frac{7}{16}$, W: $5\frac{2}{3}$, T: $1\frac{2}{5}$, F: 27, B: $\frac{7}{10}$, K: $\frac{2}{3}$, I: $24\frac{1}{2}$, Y: $16\frac{1}{2}$, S: $4\frac{1}{2}$, J: $\frac{2}{15}$ ← HERE! J is $\frac{2}{15}$

So ① = J

---

② $\frac{3}{4} \times \frac{7}{12}$
Multiply numerators: 3×7 = 21
Denominators: 4×12 = 48
$\frac{21}{48}$ → simplify: divide numerator and denominator by 3 → $\frac{7}{16}$ → that’s G

So ② = G

---

③ $\frac{3}{8}$ of $\frac{4}{9}$ → same as multiply: $\frac{3}{8} \times \frac{4}{9} = \frac{12}{72} = \frac{1}{6}$ → that’s Z

So ③ = Z

---

④ $\frac{7}{10} + \frac{1}{2}$
Common denominator: 10
$\frac{7}{10} + \frac{5}{10} = \frac{12}{10} = \frac{6}{5} = 1\frac{1}{5}$ → not in list? Wait — T is $1\frac{2}{5}$, no.

Wait — $\frac{12}{10} = 1.2 = 1\frac{1}{5}$ — but that’s not an option? Let me check answer box again.

T is $1\frac{2}{5}$, which is 1.4 — too big.

Wait — did I miscalculate?

$\frac{7}{10} + \frac{1}{2} = \frac{7}{10} + \frac{5}{10} = \frac{12}{10} = \frac{6}{5} = 1\frac{1}{5}$ — still not matching.

Wait — maybe I misread the problem? Problem ④ is $\frac{7}{10} + \frac{1}{2}$ — yes.

Looking at answer box: B is $\frac{7}{10}$, K is $\frac{2}{3}$, etc. None is $1\frac{1}{5}$.

Wait — perhaps I made a mistake. Let me check problem ⑤.

---

⑤ $\frac{5}{12} ÷ \frac{5}{8}$
Dividing fractions: flip second fraction → $\frac{5}{12} \times \frac{8}{5} = \frac{40}{60} = \frac{2}{3}$ → that’s K

So ⑤ = K

---

Back to ④: $\frac{7}{10} + \frac{1}{2} = \frac{7}{10} + \frac{5}{10} = \frac{12}{10} = \frac{6}{5} = 1\frac{1}{5}$ — still not in answer box.

Wait — maybe the answer is written as improper fraction? But answer box doesn't have $\frac{6}{5}$.

Hold on — let's skip and come back. Maybe I'll find it later.

---

⑥ $\frac{9}{20} ÷ \frac{4}{15}$
Flip: $\frac{9}{20} \times \frac{15}{4} = \frac{135}{80}$ → simplify: divide numerator and denominator by 5 → $\frac{27}{16} = 1\frac{11}{16}$ → that’s V

So ⑥ = V

---

⑦ $1\frac{1}{3} × 2\frac{1}{2}$
Convert to improper:
$1\frac{1}{3} = \frac{4}{3}$, $2\frac{1}{2} = \frac{5}{2}$
Multiply: $\frac{4}{3} × \frac{5}{2} = \frac{20}{6} = \frac{10}{3} = 3\frac{1}{3}$ → that’s D

So ⑦ = D

---

⑧ $5\frac{1}{4} × 3\frac{1}{7}$
Convert:
$5\frac{1}{4} = \frac{21}{4}$, $3\frac{1}{7} = \frac{22}{7}$
Multiply: $\frac{21}{4} × \frac{22}{7} = \frac{462}{28}$
Simplify: divide numerator and denominator by 14 → 462÷14=33, 28÷14=2 → $\frac{33}{2} = 16\frac{1}{2}$ → that’s Y

So ⑧ = Y

---

⑨ $1\frac{7}{8} × \frac{7}{10} × 4$
First, $1\frac{7}{8} = \frac{15}{8}$
So: $\frac{15}{8} × \frac{7}{10} × 4 = \frac{15 × 7 × 4}{8 × 10} = \frac{420}{80} = \frac{42}{8} = \frac{21}{4} = 5\frac{1}{4}$ → that’s P

So ⑨ = P

---

⑩ $4\frac{1}{2} ÷ 1\frac{4}{5}$
Convert:
$4\frac{1}{2} = \frac{9}{2}$, $1\frac{4}{5} = \frac{9}{5}$
Divide: $\frac{9}{2} ÷ \frac{9}{5} = \frac{9}{2} × \frac{5}{9} = \frac{45}{18} = \frac{5}{2} = 2\frac{1}{2}$ → that’s M

So ⑩ = M

---

⑪ $2\frac{5}{8} ÷ 3\frac{3}{4}$
Convert:
$2\frac{5}{8} = \frac{21}{8}$, $3\frac{3}{4} = \frac{15}{4}$
Divide: $\frac{21}{8} ÷ \frac{15}{4} = \frac{21}{8} × \frac{4}{15} = \frac{84}{120} = \frac{7}{10}$ → that’s B

So ⑪ = B

---

⑫ $7\frac{3}{10} ÷ 5$
$7\frac{3}{10} = \frac{73}{10}$
Divide by 5: $\frac{73}{10} ÷ 5 = \frac{73}{10} × \frac{1}{5} = \frac{73}{50} = 1\frac{23}{50}$ → that’s C

So ⑫ = C

---

⑬ $12 ÷ 3\frac{1}{2}$
$3\frac{1}{2} = \frac{7}{2}$
$12 ÷ \frac{7}{2} = 12 × \frac{2}{7} = \frac{24}{7} = 3\frac{3}{7}$ → that’s U

So ⑬ = U

---

⑭ $6\frac{1}{4} ÷ \frac{5}{6}$
$6\frac{1}{4} = \frac{25}{4}$
Divide: $\frac{25}{4} ÷ \frac{5}{6} = \frac{25}{4} × \frac{6}{5} = \frac{150}{20} = \frac{15}{2} = 7\frac{1}{2}$ → that’s R

So ⑭ = R

---

⑮ $\frac{2}{3} × \frac{2}{3} × \frac{2}{3}$
= $\frac{8}{27}$ → that’s N

So ⑮ = N

---

Now word problems:

⑯ Farmer Brown harvests $2\frac{1}{3}$ acres per day. How many acres in $10\frac{1}{2}$ days?

Multiply: $2\frac{1}{3} × 10\frac{1}{2}$

Convert:
$2\frac{1}{3} = \frac{7}{3}$, $10\frac{1}{2} = \frac{21}{2}$
Multiply: $\frac{7}{3} × \frac{21}{2} = \frac{147}{6} = \frac{49}{2} = 24\frac{1}{2}$ → that’s I

So ⑯ = I

---

⑰ Same rate: how many days to harvest $10\frac{1}{2}$ acres?

Divide total acres by daily rate:
$10\frac{1}{2} ÷ 2\frac{1}{3} = \frac{21}{2} ÷ \frac{7}{3} = \frac{21}{2} × \frac{3}{7} = \frac{63}{14} = \frac{9}{2} = 4\frac{1}{2}$ → that’s S

So ⑰ = S

---

Now let’s go back to problem ④: $\frac{7}{10} + \frac{1}{2}$

We had $\frac{7}{10} + \frac{5}{10} = \frac{12}{10} = \frac{6}{5} = 1\frac{1}{5}$ — but that’s not in the answer box.

Wait — maybe I misread the problem? Let me check original image description.

In the user’s text: “④ $\frac{7}{10} + \frac{1}{2}$” — yes.

But in answer box, we have T: $1\frac{2}{5}$ — which is 1.4, while 1.2 is 1.2.

Wait — unless... is it possible that problem ④ is actually subtraction? No, it says "+".

Wait — let me check if any answer matches $\frac{6}{5}$ or $1\frac{1}{5}$ — no.

Perhaps I made a mistake in another problem? Let me verify problem ③ again.

③ $\frac{3}{8}$ of $\frac{4}{9}$ = $\frac{3}{8} × \frac{4}{9} = \frac{12}{72} = \frac{1}{6}$ → Z — correct.

Problem ①: $\frac{2}{3} × \frac{1}{5} = \frac{2}{15}$ → J — correct.

Problem ④ must be matched. Let me see — is there an answer for $1\frac{1}{5}$? No.

Wait — perhaps the answer is written as decimal? No, all are fractions.

Another thought: maybe problem ④ is $\frac{7}{10} + \frac{1}{2}$ but they want it as mixed number, and perhaps I need to see if it's equivalent to something else.

$\frac{6}{5} = 1.2$, and T is $1\frac{2}{5} = 1.4$ — different.

Wait — let's list all answers we have so far:

① J
② G
③ Z
④ ?
⑤ K
⑥ V
⑦ D
⑧ Y
⑨ P
⑩ M
⑪ B
⑫ C
⑬ U
⑭ R
⑮ N
⑯ I
⑰ S

That’s 17 problems. We’re missing ④.

But we have 17 letters assigned except ④.

List of used letters: J, G, Z, K, V, D, Y, P, M, B, C, U, R, N, I, S — that’s 16. Missing one.

What about problem ④? It must be one of the remaining answers.

Remaining answers in box:
T: $1\frac{2}{5}$, F: 27, A: $8\frac{1}{4}$, L: $2\frac{5}{6}$, H: $\frac{9}{20}$, O? Wait, let's list all answer keys:

From the box:

Row 1: R, D, G, W
Row 2: T, F, B, K, I, Y
Row 3: S, J, P, U, H, A
Row 4: M, N, Z, L, V, C

All answers: R,D,G,W,T,F,B,K,I,Y,S,J,P,U,H,A,M,N,Z,L,V,C — that’s 22 answers, but only 17 problems. So some answers are distractors.

For problem ④: $\frac{7}{10} + \frac{1}{2} = \frac{12}{10} = \frac{6}{5} = 1\frac{1}{5}$ — not listed.

Unless... wait, is it possible that the problem is $\frac{7}{10} - \frac{1}{2}$? Then $\frac{7}{10} - \frac{5}{10} = \frac{2}{10} = \frac{1}{5}$ — not listed.

Or maybe $\frac{7}{10} × \frac{1}{2} = \frac{7}{20}$ — not listed.

H is $\frac{9}{20}$ — close but not.

Another idea: perhaps I miscalculated problem ④.

$\frac{7}{10} + \frac{1}{2} = \frac{7}{10} + \frac{5}{10} = \frac{12}{10} = \frac{6}{5} = 1.2$

Is there an answer like $1\frac{1}{5}$? No.

Wait — let's look at the answer box again. In row 2, T is $1\frac{2}{5}$ — which is 1.4.

But what if the problem was $\frac{7}{10} + \frac{3}{5}$? Then $\frac{7}{10} + \frac{6}{10} = \frac{13}{10} = 1.3$ — still not.

Perhaps it's a typo in my reading. Let me assume that for now and proceed to cross out letters.

We have these letters from problems:

① J
② G
③ Z
④ ???
⑤ K
⑥ V
⑦ D
⑧ Y
⑨ P
⑩ M
⑪ B
⑫ C
⑬ U
⑭ R
⑮ N
⑯ I
⑰ S

So letters to cross out: J, G, Z, K, V, D, Y, P, M, B, C, U, R, N, I, S — and whatever ④ is.

But we need to know ④.

Let me try to calculate ④ again: $\frac{7}{10} + \frac{1}{2}$

Perhaps they want it as improper fraction $\frac{6}{5}$, but it's not in the box.

Wait — in the answer box, is there a $1\frac{1}{5}$? No.

Another thought: maybe problem ④ is $\frac{7}{10} ÷ \frac{1}{2}$? Then $\frac{7}{10} × 2 = \frac{14}{10} = \frac{7}{5} = 1\frac{2}{5}$ — ah! That's T!

And T is $1\frac{2}{5}$.

Perhaps I misread the operation. Let me check the original problem statement.

In the user's text: "④ $\frac{7}{10} + \frac{1}{2}$" — it says "+", but maybe it's a division? Or perhaps in the actual image, it's division.

Because if it were division, then $\frac{7}{10} ÷ \frac{1}{2} = \frac{7}{10} × 2 = \frac{14}{10} = \frac{7}{5} = 1\frac{2}{5}$ = T.

And that makes sense because otherwise we have no match.

Moreover, in many such puzzles, sometimes operations are mixed.

Let me verify with the context. If I assume ④ is division, then it works.

Also, in the list, we have T available.

So likely, it's a typo in my reading or in the transcription, and it should be division.

So I'll take ④ = T

Then all problems are solved.

So letters to cross out:

From problems:

① J
② G
③ Z
④ T
⑤ K
⑥ V
⑦ D
⑧ Y
⑨ P
⑩ M
⑪ B
⑫ C
⑬ U
⑭ R
⑮ N
⑯ I
⑰ S

So the letters are: J, G, Z, T, K, V, D, Y, P, M, B, C, U, R, N, I, S

Now, the string at the bottom is:

T C S H G M O N D W I W P K S A R Y J F S I F T B U L Z V P E N

We need to cross out each letter every time it appears in this string, based on our answers.

Our answer letters: J, G, Z, T, K, V, D, Y, P, M, B, C, U, R, N, I, S

Note: Some letters may appear multiple times in the string, and we cross out each occurrence.

Also, note that in the answer set, we have 17 letters, but some might repeat? Let's see: all seem unique in our list.

List of letters to cross out: B, C, D, G, I, J, K, M, N, P, R, S, T, U, V, Y, Z

Now, go through the string and cross out each of these letters wherever they appear.

String: T C S H G M O N D W I W P K S A R Y J F S I F T B U L Z V P E N

Let's write it with positions or just remove the letters.

Better to list the string and remove all instances of the answer letters.

Answer letters to remove: B,C,D,G,I,J,K,M,N,P,R,S,T,U,V,Y,Z

Now, go character by character:

T → remove (in list)
C → remove
S → remove
H → keep (not in list)
G → remove
M → remove
O → keep
N → remove
D → remove
W → keep
I → remove
W → keep
P → remove
K → remove
S → remove
A → keep
R → remove
Y → remove
J → remove
F → keep
S → remove
I → remove
F → keep
T → remove
B → remove
U → remove
L → keep
Z → remove
V → remove
P → remove
E → keep
N → remove

Now, what's left? Only the letters not in the removal list.

From above:

After removing, the remaining letters are:

Position 4: H
Position 7: O
Position 10: W
Position 12: W
Position 16: A
Position 20: F
Position 23: F
Position 27: L
Position 31: E

Let me list the string with indices to be sure.

Write the string: "TCSHGMONDWIWPKSARYJFSIFTBULZVPEN"

Break into characters:

1:T, 2:C, 3:S, 4:H, 5:G, 6:M, 7:O, 8:N, 9:D, 10:W, 11:I, 12:W, 13:P, 14:K, 15:S, 16:A, 17:R, 18:Y, 19:J, 20:F, 21:S, 22:I, 23:F, 24:T, 25:B, 26:U, 27:L, 28:Z, 29:V, 30:P, 31:E, 32:N

Now, remove if letter is in {B,C,D,G,I,J,K,M,N,P,R,S,T,U,V,Y,Z}

So:

1:T → remove
2:C → remove
3:S → remove
4:H → keep
5:G → remove
6:M → remove
7:O → keep
8:N → remove
9:D → remove
10:W → keep
11:I → remove
12:W → keep
13:P → remove
14:K → remove
15:S → remove
16:A → keep
17:R → remove
18:Y → remove
19:J → remove
20:F → keep
21:S → remove
22:I → remove
23:F → keep
24:T → remove
25:B → remove
26:U → remove
27:L → keep
28:Z → remove
29:V → remove
30:P → remove
31:E → keep
32:N → remove

So kept letters: positions 4,7,10,12,16,20,23,27,31 → H, O, W, W, A, F, F, L, E

So the remaining letters are: H, O, W, W, A, F, F, L, E

Now, arrange them in order: H O W W A F F L E

That spells "HOWWAFFLE" — but that doesn't make sense.

Perhaps it's "HOW WAFFLE" but missing space.

The riddle is: "What Did the Ms. Snerd Say When Her Son Ate 17 Chocolate-Chip Waffles with 2 Pints of Maple Syrup?"

So probably the answer is a phrase.

"HOWWAFFLE" — maybe "How waffle?" but that doesn't fit.

Perhaps I have extra letters.

List: H,O,W,W,A,F,F,L,E — that's 9 letters.

Maybe it's "HOW MANY WAFFLES" but we have only 9 letters.

Another thought: perhaps when crossing out, we cross out each occurrence, but in the string, some letters appear multiple times, and we cross out all instances, even if not in our answer set? No, the instruction is: "look for this letter in the string of letters near the bottom of the page and CROSS IT OUT each time it appears." And "this letter" refers to the letter next to the answer for each problem.

So for each problem, we get a letter, and we cross out every occurrence of that letter in the string.

In our case, we have 17 letters from the 17 problems, and we cross out all occurrences of those letters in the string.

But in the string, some letters may appear multiple times, and we cross out all of them if the letter is in our answer set.

In our answer set, we have letters like S, which appears multiple times in the string, and we cross out all S's.

Similarly for others.

In the remaining letters, we have H,O,W,W,A,F,F,L,E

But "HOWWAFFLE" isn't a word.

Perhaps it's "HOW MANY" but we don't have M,N,Y — they are crossed out.

Another idea: perhaps the remaining letters form "I'M FULL" or something, but we have H,O,W,W,A,F,F,L,E.

Let's sort them or see if it's an anagram.

Letters: A, E, F, F, H, L, O, W, W

Possible words: "Waffle" is there, but "how" and "full"?

"Full" would require U,L,L — we have L, but only one L, and U is crossed out.

We have two F's, two W's, etc.

Perhaps it's "HOW ABOUT WAFFLES" but too long.

Another thought: maybe I made a mistake in problem ④.

Earlier I assumed ④ is division to get T, but if it's addition, we have no match, so probably it is division.

Perhaps the answer is "SHE SAID 'OH NO!'" but not matching.

Let's list the remaining letters again: from the string, after removing all instances of the answer letters, we have:

H, O, W, W, A, F, F, L, E

Now, perhaps it's "HOW WAFFLE" but that's 9 letters, and "how waffle" doesn't make sense.

Maybe it's "I ATE TOO MANY" but not matching.

Another idea: perhaps the remaining letters are to be read as a phrase, and "HOWWAFFLE" is meant to be "How waffle?" but that's silly.

Perhaps I missed that some letters are not to be crossed out if they are not in the answer set, but we did that.

Let's count how many times each letter appears in the string and how many we cross out.

But that might be complicated.

Perhaps the answer is "FULL" but we have only one L.

Let's look at the kept letters: H,O,W,W,A,F,F,L,E

If we group: HOW WAF FLE — not good.

Perhaps it's "Waffle" and "how" and "e" — no.

Another thought: maybe the puzzle is to realize that "Ms. Snerd" is "Mrs. Snerd" and she said "Oh no!" but not matching.

Perhaps I have a calculation error in one of the problems.

Let me double-check problem ⑳ — wait, only 17 problems.

Problem ⑰ is S, which is 4 1/2, correct.

Perhaps problem ④ is indeed addition, and the answer is not in the box, but that can't be.

Let's calculate problem ④ as addition: 7/10 + 1/2 = 12/10 = 6/5 = 1 1/5

Is 1 1/5 in the answer box? No, but T is 1 2/5, which is close.

Perhaps it's a different problem.

Another idea: in the answer box, is there a 1 1/5? No, but let's see if any answer is 6/5.

No.

Perhaps for problem ④, the answer is B, but B is 7/10, which is not.

Let's try to see what letter is left if I omit ④ or something.

Perhaps the string has 32 characters, and we cross out 17 letters, but since some letters repeat, we cross out more than 17 characters.

In our case, we crossed out all occurrences of the 17 letters, but some letters like S appear multiple times, so we cross out more than 17 characters.

In the string, let's count how many characters are removed.

From earlier, we kept 9 characters, so removed 32-9=23 characters.

The answer letters are 17, but since some letters repeat in the string, we remove multiple instances.

For example, S appears in the string at positions 3,15,21 — three times, and S is in our answer set (from ⑰), so we remove all three S's.

Similarly, T appears at 1,24 — twice, and T is in answer set (from ④), so remove both.

etc.

So our calculation seems correct.

Now, the remaining letters are H,O,W,W,A,F,F,L,E

Perhaps it's "HOW MANY WAFFLES" but we don't have M,N,Y.

Unless I have a mistake in the answer set.

Let's list the answer letters again:

From problems:

① J
② G
③ Z
④ T (assumed division)
⑤ K
⑥ V
⑦ D
⑧ Y
⑨ P
⑩ M
⑪ B
⑫ C
⑬ U
⑭ R
⑮ N
⑯ I
⑰ S

So letters: B,C,D,G,I,J,K,M,N,P,R,S,T,U,V,Y,Z

Now, in the string "TCSHGMONDWIWPKSARYJFSIFTBULZVPEN", let's remove all these letters.

As before, kept: H,O,W,W,A,F,F,L,E

Now, perhaps the phrase is "HOW ABOUT WAFFLES" but we have only 9 letters.

Maybe it's "I'M FULL" but not matching.

Another idea: perhaps "Ms. Snerd" is a play on "Mrs. Snerd" and she said "Oh, waffle!" but not.

Let's try to read the remaining letters as "HOW WAFFLE" and perhaps it's "How waffle?" meaning she is surprised, but that doesn't make sense.

Perhaps it's "FULL" and "HOW" but we have extra letters.

Let's see the sequence: H O W W A F F L E

If we take it as "HOW" "WAFFLE" but "waffle" is W A F F L E, and we have an extra W and H O.

H O W W A F F L E — so "HOW" + "WAFFLE" but "WAFFLE" is 6 letters, we have W A F F L E, and before that H O W, so "HOW WAFFLE" — 9 letters.

But "how waffle" isn't a phrase.

Perhaps it's "Waffle how" but same thing.

Another thought: maybe the answer is "SHE SAID 'OH NO!'" but not matching.

Perhaps I have a mistake in problem ⑳ — wait, no.

Let's check problem ⑱ — only 17.

Perhaps problem ④ is not T.

Let's assume that problem ④ is addition, and the answer is 1 1/5, and perhaps it's not in the box, but that can't be.

Maybe in the answer box, T is 1 2/5, but for a different problem.

Let's calculate problem ④ as is: 7/10 + 1/2 = 12/10 = 6/5 = 1.2

Is there an answer like 1.2? No.

Perhaps it's 7/10 * 1/2 = 7/20, and H is 9/20, close but not.

Or 7/10 - 1/2 = 2/10 = 1/5, not in box.

Another idea: perhaps the operation is division, and it's correct, and the remaining letters are to be interpreted as "HOW MANY" but we have W,W,A,F,F,L,E,H,O — no M,N,Y.

Unless I have a wrong answer for one problem.

Let's check problem ⑩: 4 1/2 ÷ 1 4/5 = 9/2 ÷ 9/5 = 9/2 * 5/9 = 5/2 = 2 1/2 = M — correct.

Problem ⑪: 2 5/8 ÷ 3 3/4 = 21/8 ÷ 15/4 = 21/8 * 4/15 = 84/120 = 7/10 = B — correct.

Problem ⑫: 7 3/10 ÷ 5 = 73/10 / 5 = 73/50 = 1 23/50 = C — correct.

Problem ⑬: 12 ÷ 3 1/2 = 12 / 7/2 = 24/7 = 3 3/7 = U — correct.

Problem ⑭: 6 1/4 ÷ 5/6 = 25/4 * 6/5 = 150/20 = 15/2 = 7 1/2 = R — correct.

Problem ⑮: 2/3 * 2/3 * 2/3 = 8/27 = N — correct.

Problem ⑯: 2 1/3 * 10 1/2 = 7/3 * 21/2 = 147/6 = 49/2 = 24 1/2 = I — correct.

Problem ⑰: 10 1/2 ÷ 2 1/3 = 21/2 ÷ 7/3 = 21/2 * 3/7 = 63/14 = 9/2 = 4 1/2 = S — correct.

So only problem ④ is questionable.

Perhaps in the original image, problem ④ is $\frac{7}{10} \div \frac{1}{2}$, which is 7/5 = 1 2/5 = T, and that's standard.

So I think it's correct.

Now, the remaining letters are H,O,W,W,A,F,F,L,E

Perhaps it's "HOW ABOUT WAFFLES" but we have only 9 letters.

Maybe it's "I ATE 17 WAFFLES" but not matching.

Another idea: perhaps the phrase is "FULL" and "HOW" but we have extra.

Let's count the letters: 9 letters.

Perhaps it's "Waffle" and "how" and "e" for "eh" but not.

Maybe it's "OH WELL" but we have H,O,W,W,A,F,F,L,E — no E at the end for "well".

" Well" would be W,E,L,L — we have W,E,L, but only one L, and extra letters.

Perhaps the answer is "SHE SAID 'NO MORE!'" but not.

Let's try to see if the remaining letters can be rearranged to "FULL HOUSE" or something, but we have A,F,F,H,L,O,W,W,E — not matching.

Another thought: perhaps "Ms. Snerd" is "Mrs. Snerd" and she said "Oh, my goodness!" but not.

Maybe the answer is "HOW MANY" but we don't have M,N,Y.

Unless I have a mistake in the answer for problem ⑰ or something.

Problem ⑰ is S, which is 4 1/2, and S is in the string, crossed out.

Perhaps for problem ④, if I take it as addition, and assume the answer is not in the box, but that can't be.

Let's look online or think differently.

Perhaps the remaining letters are "H O W W A F F L E" and it's "How waffle?" but that doesn't make sense for the riddle.

The riddle is: "What Did the Ms. Snerd Say When Her Son Ate 17 Chocolate-Chip Waffles with 2 Pints of Maple Syrup?"

Probably she said something like "Oh no!" or "That's too much!" or "You're full!"

With the letters H,O,W,W,A,F,F,L,E, perhaps it's "FULL" and "HOW" but not.

Let's try to read it as "HOW WAFFLE" and perhaps it's a pun on "how awful" but "waffle" instead of "awful".

"How waffle" sounds like "how awful"!

Yes! "How waffle" is a play on "how awful"!

Because "waffle" sounds like "awful" when said quickly, especially with accent.

So Ms. Snerd said "How waffle!" meaning "How awful!"

That makes sense for the riddle.

So the answer is "HOW WAFFLE" but since it's a pun, it's "How awful!"

But in the puzzle, the remaining letters spell "HOWWAFFLE", which is "HOW WAFFLE", and that's the punchline.

So the answer to the puzzle is "HOW WAFFLE" or "How waffle!"

But typically, it's written as a phrase.

In the rectangle, we put the remaining letters in order: H O W W A F F L E

So "HOWWAFFLE"

But to make it readable, perhaps "HOW WAFFLE"

Since the instruction is to write the remaining letters in the rectangle, and they are in order, so "HOWWAFFLE"

But for the final answer, we can say the phrase is "How waffle!" implying "How awful!"

So I think that's it.

To confirm, let's see if there's any other interpretation.

Perhaps it's "I'm full" but we have H,O,W,W,A,F,F,L,E — not matching.

So I'll go with that.

Final Answer: HOWWAFFLE

But to box it, and since it's a phrase, perhaps write it as is.

In the context, the answer to the puzzle is the string of remaining letters: H,O,W,W,A,F,F,L,E which forms "HOWWAFFLE"

So for the Final Answer section, we put that.

But let's make sure about problem ④.

If problem ④ is addition, we have no match, so it must be division, giving T, which is correct.

And the pun works.

So I think it's correct.