Word Problems Worksheets | Dynamically Created Word Problems - Free Printable

Here is the step-by-step solution to all 10 word problems on the worksheet. Each problem involves adding mixed numbers. The key steps are:

1. Convert mixed numbers to improper fractions (optional, but helpful for some).
2. Find a common denominator.
3. Add the fractions.
4. Simplify the result and convert back to a mixed number if needed.

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Problem 1:
Tom completed \(1\frac{3}{4}\) crosswords on Wednesday and \(2\frac{1}{4}\) on Thursday.

Add:
\(1\frac{3}{4} + 2\frac{1}{4} = (1 + 2) + (\frac{3}{4} + \frac{1}{4}) = 3 + \frac{4}{4} = 3 + 1 = 4\)

✔ Answer: 4 crosswords

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Problem 2:
Dan has \(1\frac{3}{7}\) weeks’ pay in wallet and \(1\frac{1}{7}\) in bank.

Add:
\(1\frac{3}{7} + 1\frac{1}{7} = (1 + 1) + (\frac{3}{7} + \frac{1}{7}) = 2 + \frac{4}{7} = 2\frac{4}{7}\)

✔ Answer: \(2\frac{4}{7}\) weeks of pay

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Problem 3:
Tim drank \(1\frac{2}{3}\) cups at breakfast and \(1\frac{3}{7}\) at dinner.

We need a common denominator. LCM of 3 and 7 is 21.

Convert:
- \(1\frac{2}{3} = \frac{5}{3} = \frac{35}{21}\)
- \(1\frac{3}{7} = \frac{10}{7} = \frac{30}{21}\)

Add:
\(\frac{35}{21} + \frac{30}{21} = \frac{65}{21} = 3\frac{2}{21}\) (since 65 ÷ 21 = 3 with remainder 2)

✔ Answer: \(3\frac{2}{21}\) cups of milk

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Problem 4:
Mary read \(1\frac{1}{12}\) books Thursday and \(1\frac{5}{12}\) Saturday.

Add:
\(1\frac{1}{12} + 1\frac{5}{12} = (1 + 1) + (\frac{1}{12} + \frac{5}{12}) = 2 + \frac{6}{12} = 2 + \frac{1}{2} = 2\frac{1}{2}\)

✔ Answer: \(2\frac{1}{2}\) books

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Problem 5:
Keith ate \(1\frac{1}{6}\) pies, Jessica ate \(1\frac{5}{8}\) pies.

Common denominator of 6 and 8 is 24.

Convert:
- \(1\frac{1}{6} = \frac{7}{6} = \frac{28}{24}\)
- \(1\frac{5}{8} = \frac{13}{8} = \frac{39}{24}\)

Add:
\(\frac{28}{24} + \frac{39}{24} = \frac{67}{24} = 2\frac{19}{24}\) (since 67 ÷ 24 = 2 with remainder 19)

✔ Answer: \(2\frac{19}{24}\) pies

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Problem 6:
Tim planted \(1\frac{2}{5}\) rows of peppers and \(1\frac{1}{5}\) rows of beans.

Add:
\(1\frac{2}{5} + 1\frac{1}{5} = (1 + 1) + (\frac{2}{5} + \frac{1}{5}) = 2 + \frac{3}{5} = 2\frac{3}{5}\)

✔ Answer: \(2\frac{3}{5}\) rows of vegetables

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Problem 7:
Recipe calls for \(1\frac{2}{7}\) cups chopped tomatoes and \(1\frac{3}{7}\) cups diced tomatoes.

Add:
\(1\frac{2}{7} + 1\frac{3}{7} = (1 + 1) + (\frac{2}{7} + \frac{3}{7}) = 2 + \frac{5}{7} = 2\frac{5}{7}\)

✔ Answer: \(2\frac{5}{7}\) cups of tomatoes

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Problem 8:
Sam did \(1\frac{1}{2}\) loads Saturday and \(1\frac{1}{3}\) loads Friday.

Common denominator of 2 and 3 is 6.

Convert:
- \(1\frac{1}{2} = \frac{3}{2} = \frac{9}{6}\)
- \(1\frac{1}{3} = \frac{4}{3} = \frac{8}{6}\)

Add:
\(\frac{9}{6} + \frac{8}{6} = \frac{17}{6} = 2\frac{5}{6}\)

✔ Answer: \(2\frac{5}{6}\) loads of laundry

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Problem 9:
Benny bought \(1\frac{1}{6}\) pounds chicken and \(1\frac{2}{6}\) pounds turkey.

Note: \(\frac{2}{6} = \frac{1}{3}\), but we can add as is since denominators are same.

Add:
\(1\frac{1}{6} + 1\frac{2}{6} = (1 + 1) + (\frac{1}{6} + \frac{2}{6}) = 2 + \frac{3}{6} = 2 + \frac{1}{2} = 2\frac{1}{2}\)

✔ Answer: \(2\frac{1}{2}\) pounds of meat

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Problem 10:
Alyssa picked \(1\frac{3}{8}\) buckets, Jason picked \(2\frac{1}{4}\) buckets.

Common denominator of 8 and 4 is 8.

Convert:
- \(1\frac{3}{8} = \frac{11}{8}\)
- \(2\frac{1}{4} = \frac{9}{4} = \frac{18}{8}\)

Add:
\(\frac{11}{8} + \frac{18}{8} = \frac{29}{8} = 3\frac{5}{8}\)

✔ Answer: \(3\frac{5}{8}\) buckets total

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## ✔ Final Answers Summary:

1. 4
2. \(2\frac{4}{7}\)
3. \(3\frac{2}{21}\)
4. \(2\frac{1}{2}\)
5. \(2\frac{19}{24}\)
6. \(2\frac{3}{5}\)
7. \(2\frac{5}{7}\)
8. \(2\frac{5}{6}\)
9. \(2\frac{1}{2}\)
10. \(3\frac{5}{8}\)

Let me know if you’d like to see any step explained in more detail!