SOLUTION: 4chap molarity problems worksheet - Studypool - Free Printable

Let’s solve the first problem on the worksheet:

Problem 1: What is the molarity of a 0.30 liter solution containing 0.50 moles of NaCl?

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Step-by-step reasoning:

We are given:
- Moles of solute (NaCl) = 0.50 mol
- Volume of solution = 0.30 L

The formula for molarity is:

> M = n / V

Where:
- M = molarity (in mol/L or M)
- n = number of moles
- V = volume in liters

Plug in the numbers:

> M = 0.50 mol ÷ 0.30 L

Now do the division:

> 0.50 ÷ 0.30 = 1.666...

Round to two significant figures (since both 0.50 and 0.30 have two sig figs):

> ≈ 1.7 M

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✔ Double-check:
If you have 0.50 moles in 0.30 liters, that means each liter would contain more than 1 mole — yes, 1.7 makes sense.

Also, units: moles divided by liters → mol/L → which is M. Correct.

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Final Answer:
1.7 M