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Step-by-step solution for: SOLUTION: Mole concept practice papper - Studypool
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Step-by-step solution for: SOLUTION: Mole concept practice papper - Studypool
Let's solve each question step by step:
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- SO₂ consists of one sulfur (S) atom and two oxygen (O) atoms.
- Atomic mass of S = 32 amu
- Atomic mass of O = 16 amu
- Molecular weight of SO₂ = 1 × 32 + 2 × 16 = 32 + 32 = 64 amu
Answer: (2) 64 amu
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The relationship between Celsius (C) and Fahrenheit (F) is given by:
\[ F = \frac{9}{5}C + 32 \]
Rearranging for C:
\[ C = \frac{5}{9}(F - 32) \]
Answer: (1) \(\frac{C}{5} = \frac{F - 32}{9}\)
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The modern atomic weight scale is based on the isotope ¹²C, where the atomic mass of ¹²C is defined as exactly 12 amu.
Answer: (1) ¹²C
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1 atomic mass unit (amu) is defined as:
\[ 1 \, \text{amu} = \frac{1}{12} \text{ of the mass of one atom of } ^{12}\text{C} \]
Answer: (1) \(\frac{1}{12}\) of C–12
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Avogadro's number (\(N_A\)) is approximately \(6.022 \times 10^{23}\) and represents:
1. The number of atoms in one gram of the element (for monatomic elements).
2. The number of molecules present in one gram molecular mass of a substance.
3. The number of millilitres which one mole of a gaseous substance occupies at NTP (1 atm & 0°C).
All these statements are correct.
Answer: (4) All are correct
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To find the temperature where Celsius (C) and Fahrenheit (F) are equal, set \(C = F\) in the conversion formula:
\[ F = \frac{9}{5}C + 32 \]
\[ C = \frac{9}{5}C + 32 \]
Rearrange:
\[ C - \frac{9}{5}C = 32 \]
\[ \frac{5}{5}C - \frac{9}{5}C = 32 \]
\[ -\frac{4}{5}C = 32 \]
\[ C = 32 \times \left(-\frac{5}{4}\right) \]
\[ C = -40 \]
Thus, at \(-40^\circ\), both scales read the same value.
Answer: (4) –40°
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The mass of one atom in grams can be calculated using the relationship:
\[ 1 \, \text{amu} = 1.66 \times 10^{-24} \, \text{g} \]
For uranium (238 amu):
\[ \text{Mass of one atom} = 238 \times 1.66 \times 10^{-24} \]
\[ = 3.95 \times 10^{-22} \, \text{g} \]
Answer: (1) \(3.95 \times 10^{-22}\)
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The number of moles (\(n\)) is given by:
\[ n = \frac{\text{mass}}{\text{molar mass}} \]
Here, mass = 46 g and molar mass = 23 g/mol:
\[ n = \frac{46}{23} = 2 \, \text{moles} \]
Answer: (2) 2
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The atomic mass of helium (He) is 4 amu. Therefore, 100 amu of He corresponds to:
\[ \text{Number of atoms} = \frac{100 \, \text{amu}}{4 \, \text{amu/atom}} = 25 \, \text{atoms} \]
Answer: (1) 25
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1. (2) 64 amu
2. (1) \(\frac{C}{5} = \frac{F - 32}{9}\)
3. (1) ¹²C
4. (1) \(\frac{1}{12}\) of C–12
5. (4) All are correct
6. (4) –40°
7. (1) \(3.95 \times 10^{-22}\)
8. (2) 2
9. (1) 25
Boxed Final Answer:
\[
\boxed{(2), (1), (1), (1), (4), (4), (1), (2), (1)}
\]
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Question 1: Molecular weight of SO₂ is
- SO₂ consists of one sulfur (S) atom and two oxygen (O) atoms.
- Atomic mass of S = 32 amu
- Atomic mass of O = 16 amu
- Molecular weight of SO₂ = 1 × 32 + 2 × 16 = 32 + 32 = 64 amu
Answer: (2) 64 amu
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Question 2: Centigrade and Fahrenheit scales are related as:
The relationship between Celsius (C) and Fahrenheit (F) is given by:
\[ F = \frac{9}{5}C + 32 \]
Rearranging for C:
\[ C = \frac{5}{9}(F - 32) \]
Answer: (1) \(\frac{C}{5} = \frac{F - 32}{9}\)
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Question 3: The modern atomic weight scale is based on:
The modern atomic weight scale is based on the isotope ¹²C, where the atomic mass of ¹²C is defined as exactly 12 amu.
Answer: (1) ¹²C
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Question 4: 1 amu is equal to:
1 atomic mass unit (amu) is defined as:
\[ 1 \, \text{amu} = \frac{1}{12} \text{ of the mass of one atom of } ^{12}\text{C} \]
Answer: (1) \(\frac{1}{12}\) of C–12
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Question 5: Avogadro number is:
Avogadro's number (\(N_A\)) is approximately \(6.022 \times 10^{23}\) and represents:
1. The number of atoms in one gram of the element (for monatomic elements).
2. The number of molecules present in one gram molecular mass of a substance.
3. The number of millilitres which one mole of a gaseous substance occupies at NTP (1 atm & 0°C).
All these statements are correct.
Answer: (4) All are correct
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Question 6: At what temperature, both Celsius and Fahrenheit scale read the same value:
To find the temperature where Celsius (C) and Fahrenheit (F) are equal, set \(C = F\) in the conversion formula:
\[ F = \frac{9}{5}C + 32 \]
\[ C = \frac{9}{5}C + 32 \]
Rearrange:
\[ C - \frac{9}{5}C = 32 \]
\[ \frac{5}{5}C - \frac{9}{5}C = 32 \]
\[ -\frac{4}{5}C = 32 \]
\[ C = 32 \times \left(-\frac{5}{4}\right) \]
\[ C = -40 \]
Thus, at \(-40^\circ\), both scales read the same value.
Answer: (4) –40°
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Question 7: The weight of one atom of Uranium is 238 amu. Its actual weight is …… g.
The mass of one atom in grams can be calculated using the relationship:
\[ 1 \, \text{amu} = 1.66 \times 10^{-24} \, \text{g} \]
For uranium (238 amu):
\[ \text{Mass of one atom} = 238 \times 1.66 \times 10^{-24} \]
\[ = 3.95 \times 10^{-22} \, \text{g} \]
Answer: (1) \(3.95 \times 10^{-22}\)
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Question 8: If the atomic mass of Sodium is 23, the number of moles in 46 g of sodium is:
The number of moles (\(n\)) is given by:
\[ n = \frac{\text{mass}}{\text{molar mass}} \]
Here, mass = 46 g and molar mass = 23 g/mol:
\[ n = \frac{46}{23} = 2 \, \text{moles} \]
Answer: (2) 2
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Question 9: How many atoms are there in 100 amu of He?
The atomic mass of helium (He) is 4 amu. Therefore, 100 amu of He corresponds to:
\[ \text{Number of atoms} = \frac{100 \, \text{amu}}{4 \, \text{amu/atom}} = 25 \, \text{atoms} \]
Answer: (1) 25
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Final Answers:
1. (2) 64 amu
2. (1) \(\frac{C}{5} = \frac{F - 32}{9}\)
3. (1) ¹²C
4. (1) \(\frac{1}{12}\) of C–12
5. (4) All are correct
6. (4) –40°
7. (1) \(3.95 \times 10^{-22}\)
8. (2) 2
9. (1) 25
Boxed Final Answer:
\[
\boxed{(2), (1), (1), (1), (4), (4), (1), (2), (1)}
\]
Parent Tip: Review the logic above to help your child master the concept of mole concept worksheet.