Let’s solve each problem step by step. We’re converting
grams to moles, which means we need to use the formula:
>
Moles = Mass (g) ÷ Molar Mass (g/mol)
We’ll find the molar mass of each compound using atomic masses from the periodic table (rounded to 2 decimal places for simplicity):
- C = 12.01 g/mol
- O = 16.00 g/mol
- Fe = 55.85 g/mol
- H = 1.01 g/mol
- Cl = 35.45 g/mol
- Na = 22.99 g/mol
- Ca = 40.08 g/mol
---
① CO₂ → 28 grams
Molar mass of CO₂ = 12.01 + (2 × 16.00) = 12.01 + 32.00 =
44.01 g/mol
Moles = 28 ÷ 44.01 ≈
0.636 mol
✔ Check: 44.01 × 0.636 ≈ 28 — good.
---
② Fe₂O₃ → 79.85 grams
Molar mass of Fe₂O₃ = (2 × 55.85) + (3 × 16.00) = 111.70 + 48.00 =
159.70 g/mol
Moles = 79.85 ÷ 159.70 =
0.500 mol
✔ Check: 159.70 × 0.5 = 79.85 — perfect.
---
③ H₂CO₃ → 8.045 grams
Molar mass of H₂CO₃ = (2 × 1.01) + 12.01 + (3 × 16.00) = 2.02 + 12.01 + 48.00 =
62.03 g/mol
Moles = 8.045 ÷ 62.03 ≈
0.1297 mol
✔ Check: 62.03 × 0.1297 ≈ 8.045 — yes.
---
④ H₂O → 27.2 grams
Molar mass of H₂O = (2 × 1.01) + 16.00 = 2.02 + 16.00 =
18.02 g/mol
Moles = 27.2 ÷ 18.02 ≈
1.509 mol
✔ Check: 18.02 × 1.509 ≈ 27.2 — correct.
---
⑤ HCl → 72.9 grams
Molar mass of HCl = 1.01 + 35.45 =
36.46 g/mol
Moles = 72.9 ÷ 36.46 ≈
2.000 mol
✔ Check: 36.46 × 2 = 72.92 — very close (rounding error is tiny).
---
⑥ NaOH → 140 grams
Molar mass of NaOH = 22.99 + 16.00 + 1.01 =
40.00 g/mol
Moles = 140 ÷ 40.00 =
3.50 mol
✔ Check: 40 × 3.5 = 140 — exact.
---
⑦ CaCO₃ → 45.7 grams
Molar mass of CaCO₃ = 40.08 + 12.01 + (3 × 16.00) = 40.08 + 12.01 + 48.00 =
100.09 g/mol
Moles = 45.7 ÷ 100.09 ≈
0.4566 mol
✔ Check: 100.09 × 0.4566 ≈ 45.7 — good.
---
Final Answer:
① 0.636 mol
② 0.500 mol
③ 0.1297 mol
④ 1.509 mol
⑤ 2.000 mol
⑥ 3.50 mol
⑦ 0.4566 mol
Parent Tip: Review the logic above to help your child master the concept of mole conversion worksheet key.