Solved Mole to Mole Stoichiometry Worksheet Use the reaction ... - Free Printable

Let's solve each question step by step using the given balanced chemical equations and mole-to-mole stoichiometry.

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Reaction 1:

$$
8H_2(g) + S_8(s) \rightarrow 8H_2S(g)
$$

#### Question 1:
What is the mole ratio of hydrogen gas to sulfur molecules in the given reaction?

From the balanced equation:
- 8 moles of $ H_2 $ react with 1 mole of $ S_8 $

So, the mole ratio of $ H_2 $ to $ S_8 $ is:
$$
\frac{8 \text{ mol } H_2}{1 \text{ mol } S_8} = 8:1
$$

✔ Answer: The mole ratio of hydrogen gas to sulfur molecules is 8:1.

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#### Question 2:
How many moles of $ H_2 $ will react with 2 moles of $ S_8 $?

From the ratio above:
- 1 mole $ S_8 $ reacts with 8 moles $ H_2 $
- So, 2 moles $ S_8 $ will react with:
$$
2 \times 8 = 16 \text{ moles of } H_2
$$

✔ Answer: 16 moles of $ H_2 $ will react with 2 moles of $ S_8 $.

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Reaction 2:

$$
Mg_{(s)} + 2AgNO_3(aq) \rightarrow 2Ag_{(s)} + Mg(NO_3)_2(aq)
$$

#### Question 3:
What is the mole ratio of the magnesium reactant with the silver produced?

From the equation:
- 1 mole of $ Mg $ produces 2 moles of $ Ag $

So, the mole ratio of $ Mg $ to $ Ag $ is:
$$
\frac{1 \text{ mol } Mg}{2 \text{ mol } Ag} = 1:2
$$

✔ Answer: The mole ratio of magnesium to silver is 1:2.

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#### Question 4:
If one starts with two moles of magnesium, how many moles of silver are produced?

From the ratio (1 mol Mg → 2 mol Ag):
- 2 moles Mg → $ 2 \times 2 = 4 $ moles Ag

✔ Answer: 4 moles of silver are produced.

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#### Question 5:
If one starts with 0.25 moles of magnesium, how many moles of silver are produced?

Using the same ratio:
- 1 mol Mg → 2 mol Ag
- So, 0.25 mol Mg → $ 0.25 \times 2 = 0.5 $ mol Ag

✔ Answer: 0.5 moles of silver are produced.

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Reaction 3:

$$
2C_8H_{18}(l) + 25O_2(g) \rightarrow 16CO_2(g) + 18H_2O(l)
$$

#### Question 6:
What is the mole ratio of oxygen used to carbon dioxide produced in the above reaction?

From the equation:
- 25 moles $ O_2 $ produce 16 moles $ CO_2 $

So, the mole ratio of $ O_2 $ to $ CO_2 $ is:
$$
\frac{25 \text{ mol } O_2}{16 \text{ mol } CO_2} = 25:16
$$

✔ Answer: The mole ratio of oxygen to carbon dioxide is 25:16.

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#### Question 7:
If one starts with 50 moles of oxygen gas, how many moles of carbon dioxide are produced?

Use the ratio:
- 25 mol $ O_2 $ → 16 mol $ CO_2 $
- So, 50 mol $ O_2 $ → ?
$$
\frac{16}{25} \times 50 = 32 \text{ moles of } CO_2
$$

✔ Answer: 32 moles of $ CO_2 $ are produced.

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#### Question 8:
If one starts with 2.5 moles of oxygen gas, how many moles of carbon dioxide are produced?

Again, use the ratio:
- 25 mol $ O_2 $ → 16 mol $ CO_2 $
- So, 2.5 mol $ O_2 $ → ?
$$
\frac{16}{25} \times 2.5 = 1.6 \text{ moles of } CO_2
$$

✔ Answer: 1.6 moles of $ CO_2 $ are produced.

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#### Question 9:
If one starts with 6 moles of $ C_8H_{18} $, how many moles of water are produced?

From the equation:
- 2 moles $ C_8H_{18} $ → 18 moles $ H_2O $
- So, 6 moles $ C_8H_{18} $ → ?
$$
\frac{18}{2} \times 6 = 9 \times 6 = 54 \text{ moles of } H_2O
$$

✔ Answer: 54 moles of water are produced.

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✔ Final Answers Summary:

1. 8:1
2. 16 moles of $ H_2 $
3. 1:2
4. 4 moles of Ag
5. 0.5 moles of Ag
6. 25:16
7. 32 moles of $ CO_2 $
8. 1.6 moles of $ CO_2 $
9. 54 moles of $ H_2O $

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