Free Printable Mole Calculation Worksheets - Free Printable
Educational worksheet: Free Printable Mole Calculation Worksheets. Download and print for classroom or home learning activities.
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Step-by-step solution for: Free Printable Mole Calculation Worksheets
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Show Answer Key & Explanations
Step-by-step solution for: Free Printable Mole Calculation Worksheets
To solve this “Grams to Moles” worksheet, we use the fundamental formula:
> Moles = Mass (grams) ÷ Molar Mass (g/mol)
We must first calculate or look up the molar mass of each compound, then divide the given mass by that molar mass to get the number of moles.
---
Let’s go through each substance one by one.
---
- Molar mass:
H = 1.008 × 3 = 3.024
P = 30.97
O = 16.00 × 4 = 64.00
→ Total = 3.024 + 30.97 + 64.00 = 97.994 g/mol
- Moles = 30 / 97.994 ≈ 0.306 mol
---
- Molar mass:
C = 12.01
O = 16.00 × 2 = 32.00
→ Total = 12.01 + 32.00 = 44.01 g/mol
- Moles = 12.3 / 44.01 ≈ 0.279 mol
---
- Molar mass:
C = 12.01 × 6 = 72.06
H = 1.008 × 6 = 6.048
→ Total = 72.06 + 6.048 = 78.108 g/mol
- Moles = 436.8 / 78.108 ≈ 5.592 mol
---
- Molar mass:
H = 1.008
F = 19.00
→ Total = 20.008 g/mol
- Moles = 25 / 20.008 ≈ 1.249 mol
---
- Molar mass:
Zn = 65.38
O = 16.00
→ Total = 81.38 g/mol
- Moles = 537.2 / 81.38 ≈ 6.601 mol
---
- Molar mass:
Na = 22.99
H = 1.008
C = 12.01
O = 16.00 × 3 = 48.00
→ Total = 22.99 + 1.008 + 12.01 + 48.00 = 84.008 g/mol
- Moles = 110 / 84.008 ≈ 1.309 mol
---
- Molar mass:
Fe = 55.85
Cl = 35.45 × 3 = 106.35
→ Total = 55.85 + 106.35 = 162.20 g/mol
- Moles = 1.1 / 162.20 ≈ 0.00678 mol
---
- Molar mass:
Ba = 137.33
C = 12.01
O = 16.00 × 3 = 48.00
→ Total = 137.33 + 12.01 + 48.00 = 197.34 g/mol
- Moles = 4202.5 / 197.34 ≈ 21.296 mol
---
- Molar mass = 63.55 g/mol (atomic mass of copper)
- Moles = 564 / 63.55 ≈ 8.875 mol
---
- Molar mass:
Cu = 63.55
C = 12.01 × 2 = 24.02
N = 14.01 × 2 = 28.02
→ Total = 63.55 + 24.02 + 28.02 = 115.59 g/mol
- Moles = 462 / 115.59 ≈ 3.997 mol ≈ 4.00 mol
---
- Molar mass:
Sm = 150.36 (Samarium)
O = 16.00
→ Total = 166.36 g/mol
- Moles = 1.5 / 166.36 ≈ 0.00902 mol
---
This is lead(IV) acetate. Formula: Pb(C₂H₃O₂)₄
- Break down:
Pb = 207.2
C = 12.01 × 8 = 96.08
H = 1.008 × 12 = 12.096
O = 16.00 × 8 = 128.00
→ Total = 207.2 + 96.08 + 12.096 + 128.00 = 443.376 g/mol
- Moles = 89 / 443.376 ≈ 0.2007 mol
---
- Molar mass:
K = 39.10 × 2 = 78.20
S = 32.07
O = 16.00 × 4 = 64.00
→ Total = 78.20 + 32.07 + 64.00 = 174.27 g/mol
- Moles = 941.2 / 174.27 ≈ 5.401 mol
---
Note: This is likely a typo — ammonium phosphite is usually (NH₄)₃PO₃, but more commonly written as (NH₄)₃PO₃ for phosphite ion (PO₃³⁻). Let's proceed with that.
- Molar mass:
N = 14.01 × 3 = 42.03
H = 1.008 × 12 = 12.096
P = 30.97
O = 16.00 × 3 = 48.00
→ Total = 42.03 + 12.096 + 30.97 + 48.00 = 133.096 g/mol
- Moles = 159.6 / 133.096 ≈ 1.199 mol ≈ 1.20 mol
---
- Molar mass:
Ra = 226.0 (Radium — approximate atomic mass)
O = 16.00 × 2 = 32.00
H = 1.008 × 2 = 2.016
→ Total = 226.0 + 32.00 + 2.016 = 260.016 g/mol
- Moles = 987 / 260.016 ≈ 3.796 mol
---
- Molar mass:
N = 14.01
I = 126.90 × 3 = 380.70
→ Total = 14.01 + 380.70 = 394.71 g/mol
- Moles = 34679.3 / 394.71 ≈ 87.86 mol
---
## ✔ Final Answer Table:
| Weight of the Substance | Moles (rounded to 3 significant figures unless otherwise noted) |
|-------------------------------|------------------------------------------------------------------|
| 30 grams of H₃PO₄ | 0.306 mol |
| 12.3 grams of CO₂ | 0.279 mol |
| 436.8 grams of C₆H₆ | 5.59 mol |
| 25 grams of HF | 1.25 mol |
| 537.2 grams of ZnO | 6.60 mol |
| 110 grams of NaHCO₃ | 1.31 mol |
| 1.1 grams of FeCl₃ | 0.00678 mol |
| 4202.5 grams of BaCO₃ | 21.3 mol |
| 564 grams of Cu | 8.88 mol |
| 462 grams of Cu(CN)₂ | 4.00 mol |
| 1.5 grams of SmO | 0.00902 mol |
| 89 grams of Pb(CH₃COO)₄ | 0.201 mol |
| 941.2 grams of K₂SO₄ | 5.40 mol |
| 159.6 grams of (NH₄)₃PO₃ | 1.20 mol |
| 987 grams of Ra(OH)₂ | 3.80 mol |
| 34679.3 grams of NI₃ | 87.9 mol |
---
📌 Note: All values are calculated using standard atomic masses from the periodic table (rounded to 2 decimal places for most elements). For precision, some values (like Ra, Sm) may vary slightly depending on isotope abundance, but we used typical values taught in high school/college chemistry.
Let me know if you’d like the calculations shown with more decimal places or step-by-step breakdowns!
> Moles = Mass (grams) ÷ Molar Mass (g/mol)
We must first calculate or look up the molar mass of each compound, then divide the given mass by that molar mass to get the number of moles.
---
Let’s go through each substance one by one.
---
1. 30 grams of H₃PO₄
- Molar mass:
H = 1.008 × 3 = 3.024
P = 30.97
O = 16.00 × 4 = 64.00
→ Total = 3.024 + 30.97 + 64.00 = 97.994 g/mol
- Moles = 30 / 97.994 ≈ 0.306 mol
---
2. 12.3 grams of CO₂
- Molar mass:
C = 12.01
O = 16.00 × 2 = 32.00
→ Total = 12.01 + 32.00 = 44.01 g/mol
- Moles = 12.3 / 44.01 ≈ 0.279 mol
---
3. 436.8 grams of C₆H₆
- Molar mass:
C = 12.01 × 6 = 72.06
H = 1.008 × 6 = 6.048
→ Total = 72.06 + 6.048 = 78.108 g/mol
- Moles = 436.8 / 78.108 ≈ 5.592 mol
---
4. 25 grams of HF
- Molar mass:
H = 1.008
F = 19.00
→ Total = 20.008 g/mol
- Moles = 25 / 20.008 ≈ 1.249 mol
---
5. 537.2 grams of ZnO
- Molar mass:
Zn = 65.38
O = 16.00
→ Total = 81.38 g/mol
- Moles = 537.2 / 81.38 ≈ 6.601 mol
---
6. 110 grams of NaHCO₃
- Molar mass:
Na = 22.99
H = 1.008
C = 12.01
O = 16.00 × 3 = 48.00
→ Total = 22.99 + 1.008 + 12.01 + 48.00 = 84.008 g/mol
- Moles = 110 / 84.008 ≈ 1.309 mol
---
7. 1.1 grams of FeCl₃
- Molar mass:
Fe = 55.85
Cl = 35.45 × 3 = 106.35
→ Total = 55.85 + 106.35 = 162.20 g/mol
- Moles = 1.1 / 162.20 ≈ 0.00678 mol
---
8. 4202.5 grams of BaCO₃
- Molar mass:
Ba = 137.33
C = 12.01
O = 16.00 × 3 = 48.00
→ Total = 137.33 + 12.01 + 48.00 = 197.34 g/mol
- Moles = 4202.5 / 197.34 ≈ 21.296 mol
---
9. 564 grams of Cu
- Molar mass = 63.55 g/mol (atomic mass of copper)
- Moles = 564 / 63.55 ≈ 8.875 mol
---
10. 462 grams of Cu(CN)₂
- Molar mass:
Cu = 63.55
C = 12.01 × 2 = 24.02
N = 14.01 × 2 = 28.02
→ Total = 63.55 + 24.02 + 28.02 = 115.59 g/mol
- Moles = 462 / 115.59 ≈ 3.997 mol ≈ 4.00 mol
---
11. 1.5 grams of SmO
- Molar mass:
Sm = 150.36 (Samarium)
O = 16.00
→ Total = 166.36 g/mol
- Moles = 1.5 / 166.36 ≈ 0.00902 mol
---
12. 89 grams of Pb(CH₃COO)₄
This is lead(IV) acetate. Formula: Pb(C₂H₃O₂)₄
- Break down:
Pb = 207.2
C = 12.01 × 8 = 96.08
H = 1.008 × 12 = 12.096
O = 16.00 × 8 = 128.00
→ Total = 207.2 + 96.08 + 12.096 + 128.00 = 443.376 g/mol
- Moles = 89 / 443.376 ≈ 0.2007 mol
---
13. 941.2 grams of K₂SO₄
- Molar mass:
K = 39.10 × 2 = 78.20
S = 32.07
O = 16.00 × 4 = 64.00
→ Total = 78.20 + 32.07 + 64.00 = 174.27 g/mol
- Moles = 941.2 / 174.27 ≈ 5.401 mol
---
14. 159.6 grams of (NH₄)₃PO₃
Note: This is likely a typo — ammonium phosphite is usually (NH₄)₃PO₃, but more commonly written as (NH₄)₃PO₃ for phosphite ion (PO₃³⁻). Let's proceed with that.
- Molar mass:
N = 14.01 × 3 = 42.03
H = 1.008 × 12 = 12.096
P = 30.97
O = 16.00 × 3 = 48.00
→ Total = 42.03 + 12.096 + 30.97 + 48.00 = 133.096 g/mol
- Moles = 159.6 / 133.096 ≈ 1.199 mol ≈ 1.20 mol
---
15. 987 grams of Ra(OH)₂
- Molar mass:
Ra = 226.0 (Radium — approximate atomic mass)
O = 16.00 × 2 = 32.00
H = 1.008 × 2 = 2.016
→ Total = 226.0 + 32.00 + 2.016 = 260.016 g/mol
- Moles = 987 / 260.016 ≈ 3.796 mol
---
16. 34679.3 grams of NI₃
- Molar mass:
N = 14.01
I = 126.90 × 3 = 380.70
→ Total = 14.01 + 380.70 = 394.71 g/mol
- Moles = 34679.3 / 394.71 ≈ 87.86 mol
---
## ✔ Final Answer Table:
| Weight of the Substance | Moles (rounded to 3 significant figures unless otherwise noted) |
|-------------------------------|------------------------------------------------------------------|
| 30 grams of H₃PO₄ | 0.306 mol |
| 12.3 grams of CO₂ | 0.279 mol |
| 436.8 grams of C₆H₆ | 5.59 mol |
| 25 grams of HF | 1.25 mol |
| 537.2 grams of ZnO | 6.60 mol |
| 110 grams of NaHCO₃ | 1.31 mol |
| 1.1 grams of FeCl₃ | 0.00678 mol |
| 4202.5 grams of BaCO₃ | 21.3 mol |
| 564 grams of Cu | 8.88 mol |
| 462 grams of Cu(CN)₂ | 4.00 mol |
| 1.5 grams of SmO | 0.00902 mol |
| 89 grams of Pb(CH₃COO)₄ | 0.201 mol |
| 941.2 grams of K₂SO₄ | 5.40 mol |
| 159.6 grams of (NH₄)₃PO₃ | 1.20 mol |
| 987 grams of Ra(OH)₂ | 3.80 mol |
| 34679.3 grams of NI₃ | 87.9 mol |
---
📌 Note: All values are calculated using standard atomic masses from the periodic table (rounded to 2 decimal places for most elements). For precision, some values (like Ra, Sm) may vary slightly depending on isotope abundance, but we used typical values taught in high school/college chemistry.
Let me know if you’d like the calculations shown with more decimal places or step-by-step breakdowns!
Parent Tip: Review the logic above to help your child master the concept of moles calculations worksheet.
