Worksheet for calculating change from £2.00 using different priced items.

Let’s solve this step by step.

We are given a list of items with their prices:

- Ball: £2.00
- Paintbrush: 50p (which is £0.50)
- Toy car: £1.50
- Ice cream: 50p (£0.50)
- Kettle: £1.20
- Book: £1.80
- Cake: £3.05
- Lollipops: 50p each → so if you buy more than one, multiply 50p × number bought

The table has 8 rows. Each row says “Money Given” = £2.00 — that means for each purchase, the customer pays with £2.00 and we must calculate how much change they get back.

But wait — the problem doesn’t tell us *what* was bought in each row! That seems odd.

Looking again at the original task: It says “Complete the table below. Work out the change from £2.00.”

And then there’s a grid with columns: Items Bought | Total Cost | Money Given | Change

But no specific items are listed per row. So perhaps the student is meant to choose any combination of items (from the picture) that cost less than or equal to £2.00, calculate total cost, subtract from £2.00 to get change.

However, since it's a worksheet with 8 blank rows, and all say “£2.00” under “Money Given”, it’s likely that the student is expected to pick different combinations of items (each costing ≤ £2.00) and compute change.

But without being told which items to use per row, we can’t give exact answers unless we assume something.

Wait — maybe the intention is to show examples? Or perhaps the student is supposed to fill in any valid purchases?

Actually, looking at common worksheets like this, sometimes the teacher expects students to create their own scenarios — but since this is an answer key request, perhaps we should provide 8 possible valid purchases using the items shown, each totaling ≤ £2.00, and compute change from £2.00.

Let me check item prices again:

Available items and prices:

- Ball: £2.00 → if bought alone, change = £0.00
- Paintbrush: £0.50
- Toy car: £1.50
- Ice cream: £0.50
- Kettle: £1.20
- Book: £1.80
- Cake: £3.05 → too expensive! Can’t buy with £2.00 → skip
- Lollipops: £0.50 each → can buy 1, 2, 3, or 4 (since 4×0.50=£2.00)

So cake is over £2.00 — cannot be purchased with £2.00 note. So we ignore cake for these calculations.

Now let’s make 8 realistic shopping scenarios where total cost ≤ £2.00, and compute change from £2.00.

I’ll create 8 different combinations:

Row 1: Buy 1 ball → £2.00 → change = £0.00
Row 2: Buy 1 paintbrush + 1 ice cream → £0.50 + £0.50 = £1.00 → change = £1.00
Row 3: Buy 1 toy car → £1.50 → change = £0.50
Row 4: Buy 1 kettle → £1.20 → change = £0.80
Row 5: Buy 1 book → £1.80 → change = £0.20
Row 6: Buy 2 lollipops → 2 × £0.50 = £1.00 → change = £1.00
Row 7: Buy 1 paintbrush + 1 lollipop → £0.50 + £0.50 = £1.00 → change = £1.00
Row 8: Buy 4 lollipops → 4 × £0.50 = £2.00 → change = £0.00

Alternatively, maybe the worksheet expects only single-item purchases? But then we’d have fewer than 8 options (excluding cake). Let’s count affordable single items:

Affordable single items (≤ £2.00):

- Ball: £2.00
- Paintbrush: £0.50
- Toy car: £1.50
- Ice cream: £0.50
- Kettle: £1.20
- Book: £1.80
→ That’s 6 items. Plus lollipops as multiples.

To fill 8 rows, we need to include multi-item combos or multiple lollipops.

Since the problem doesn’t specify, I think the best approach is to provide 8 reasonable examples that a student might come up with, ensuring all totals are ≤ £2.00.

Let me write them clearly:

Example Row 1:
Items Bought: 1 Ball
Total Cost: £2.00
Money Given: £2.00
Change: £0.00

Example Row 2:
Items Bought: 1 Paintbrush
Total Cost: £0.50
Money Given: £2.00
Change: £1.50

Example Row 3:
Items Bought: 1 Toy Car
Total Cost: £1.50
Money Given: £2.00
Change: £0.50

Example Row 4:
Items Bought: 1 Ice Cream
Total Cost: £0.50
Money Given: £2.00
Change: £1.50

Example Row 5:
Items Bought: 1 Kettle
Total Cost: £1.20
Money Given: £2.00
Change: £0.80

Example Row 6:
Items Bought: 1 Book
Total Cost: £1.80
Money Given: £2.00
Change: £0.20

Example Row 7:
Items Bought: 2 Lollipops
Total Cost: £1.00
Money Given: £2.00
Change: £1.00

Example Row 8:
Items Bought: 1 Paintbrush + 1 Ice Cream
Total Cost: £1.00
Money Given: £2.00
Change: £1.00

This gives variety and uses most items.

Note: We avoided cake because it costs £3.05 > £2.00.

Also, note that 50p = £0.50 — important for calculation.

All changes calculated correctly:

- £2.00 - £2.00 = £0.00
- £2.00 - £0.50 = £1.50
- £2.00 - £1.50 = £0.50
- £2.00 - £0.50 = £1.50
- £2.00 - £1.20 = £0.80
- £2.00 - £1.80 = £0.20
- £2.00 - £1.00 = £1.00
- £2.00 - £1.00 = £1.00

Perfect.

Final Answer:

Here is a completed version of the table with 8 possible purchases:

| Items Bought | Total Cost | Money Given | Change |
|--------------------------|------------|-------------|----------|
| 1 Ball | £2.00 | £2.00 | £0.00 |
| 1 Paintbrush | £0.50 | £2.00 | £1.50 |
| 1 Toy Car | £1.50 | £2.00 | £0.50 |
| 1 Ice Cream | £0.50 | £2.00 | £1.50 |
| 1 Kettle | £1.20 | £2.00 | £0.80 |
| 1 Book | £1.80 | £2.00 | £0.20 |
| 2 Lollipops | £1.00 | £2.00 | £1.00 |
| 1 Paintbrush + 1 Ice Cream | £1.00 | £2.00 | £1.00 |

*(Note: Other combinations are also correct as long as total cost ≤ £2.00 and change = £2.00 - total cost.)*