Money problems worksheet with coin-based math questions and answer spaces.

You’ve uploaded a worksheet titled “Money problems” designed for elementary-level math practice, focusing on coin values, making change, and simple arithmetic with money. Since I can’t see the actual image (as you mentioned), I’ll reconstruct and solve the problems based on standard content from such worksheets — especially since you’ve provided text snippets like:

> “Look at these coins: How much is 15¢ and 10¢? 25¢”

> “What is the amount in the boxes?”

> “Jasmine collects nickels and has 45¢ worth. How many nickels does Jasmine have?”

> “Don has these coins... Which coins does he need to make $1.00?”

> “May has four coins that add up to 17¢. Which coins does May have?”

> “Which of these amounts is 12¢?”

> “60¢ is shared equally by 3 children. How much does each get?”

> “How much is four groups of coins...?”

> “Write the answers in the boxes.”

> And then a section of arithmetic problems:
> - 5¢ + 40¢ =
> - 10¢ + 40¢ =
> - 21¢ + 8¢ =
> - 25¢ – 10¢ =
> - 80¢ – 5¢ =
> - 12¢ – 11¢ =
> - 1¢ + 45¢ =
> - 62¢ – 15¢ =
> - 80¢ + 15¢ =

---

✔ Let’s solve each part step by step.

---

## 🪙 SECTION 1: Coin Recognition & Value

Problem 1: “Look at these coins: How much is 15¢ and 10¢?”

→ 15¢ + 10¢ = 25¢

*(This likely shows a dime and a nickel, or two dimes and a nickel — but total is 25¢)*

---

Problem 2: “What is the amount in the boxes?”

*(Since we don’t have the visual, this likely refers to rows of coins shown in boxes. Common examples:)*

- Box 1: 1 quarter + 1 dime = 25¢ + 10¢ = 35¢
- Box 2: 2 dimes + 1 nickel = 20¢ + 5¢ = 25¢
- Box 3: 3 nickels = 15¢ → 15¢

*(But without image, we assume typical groupings. You can adjust based on actual coins shown.)*

---

Problem 3: “Jasmine collects nickels and has 45¢ worth. How many nickels does Jasmine have?”

→ Each nickel = 5¢
→ 45¢ ÷ 5¢ = 9 nickels

✔ Answer: 9

---

Problem 4: “Don has these coins... Which coins does he need to make $1.00?”

*(Assuming Don has some coins totaling less than $1.00 — e.g., maybe 75¢ — he needs 25¢ more.)*

Common way: He could need 1 quarter, or 2 dimes + 1 nickel, or 5 nickels, etc.

Without exact coins shown, the most common answer is: 1 quarter (25¢) to make $1.00.

✔ Answer: 1 quarter *(or equivalent combination)*

---

Problem 5: “May has four coins that add up to 17¢. Which coins does May have?”

Let’s think: What 4 coins make 17¢?

Try combinations:

- 1 dime (10¢) + 1 nickel (5¢) + 2 pennies (1¢ each) = 10 + 5 + 1 + 1 = 17¢

✔ Answer: 1 dime, 1 nickel, 2 pennies

*(Other combos possible? 3 nickels = 15¢ → need 2¢ → 2 pennies → that’s 5 coins. Too many. So only 1 dime + 1 nickel + 2 pennies works with exactly 4 coins.)*

---

Problem 6: “Which of these amounts is 12¢?”

*(Likely multiple choice with coin images or values.)*

Possible options might be:

- A: 1 dime + 2 pennies → 12¢ ✔
- B: 2 nickels + 1 penny → 11¢
- C: 1 nickel + 7 pennies → 12¢ ✔ (also valid)

So both A and C could be correct depending on visuals.

✔ Answer: Any combination adding to 12¢ — e.g., 1 dime + 2 pennies OR 2 nickels + 2 pennies, etc.

---

Problem 7: “60¢ is shared equally by 3 children. How much does each get?”

→ 60¢ ÷ 3 = 20¢ per child

✔ Answer: 20¢

---

Problem 8: “How much is four groups of coins...?”

*(Assuming each group is, say, 25¢ — then 4 × 25¢ = 100¢ = $1.00)*

Or if each group is 15¢ → 4 × 15¢ = 60¢

Without image, we can’t be exact — but common problem: 4 groups of 25¢ = $1.00

✔ Answer: Likely $1.00 (if each group is 25¢)

---

## ➕ SECTION 2: Arithmetic with Money

Solve these:

1. 5¢ + 40¢ = 45¢
2. 10¢ + 40¢ = 50¢
3. 21¢ + 8¢ = 29¢
4. 25¢ – 10¢ = 15¢
5. 80¢ – 5¢ = 75¢
6. 12¢ – 11¢ = 1¢
7. 1¢ + 45¢ = 46¢
8. 62¢ – 15¢ = 47¢
9. 80¢ + 15¢ = 95¢

✔ Final Answers:

| Problem | Answer |
|----------------|--------|
| 5¢ + 40¢ | 45¢ |
| 10¢ + 40¢ | 50¢ |
| 21¢ + 8¢ | 29¢ |
| 25¢ – 10¢ | 15¢ |
| 80¢ – 5¢ | 75¢ |
| 12¢ – 11¢ | 1¢ |
| 1¢ + 45¢ | 46¢ |
| 62¢ – 15¢ | 47¢ |
| 80¢ + 15¢ | 95¢ |

---

## ✍️ Final Notes:

This worksheet reinforces:

- Coin recognition (penny, nickel, dime, quarter)
- Adding and subtracting cents
- Making change / finding missing coins
- Equal sharing (division)
- Word problems involving real-life money situations

---

✔ Summary of Key Answers:

- Jasmine has 9 nickels
- May has 1 dime, 1 nickel, 2 pennies
- Each child gets 20¢
- 15¢ + 10¢ = 25¢
- Arithmetic problems solved above

If you can describe or upload the actual image (or specific coin arrangements), I can give even more precise answers!

Let me know if you’d like printable versions or additional practice problems! 💰📚