Educational monohybrid cross worksheet for teaching Mendelian genetics.

It looks like you've uploaded a worksheet titled "Monohybrid Cross Worksheet 2", which involves genetics problems related to monohybrid crosses (crosses between two organisms that are heterozygous for one gene). However, the image is not visible in this interface. But based on your description and the content of the worksheet (which I can infer from the text), I'll help you solve the problems step by step.

Let’s go through the worksheet logically and solve each part.

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Part 1: Punnett Squares & Genotype/Phenotype Ratios

You're given three monohybrid crosses with genotypes:

#### Cross 1: Aa x Aa
- Parental Genotypes: Aa × Aa
- Punnett Square:

| | A | a |
|-------|-------|-------|
| A | AA | Aa |
| a | Aa | aa |

- Genotypic Ratio:
- AA : Aa : aa = 1 : 2 : 1

- Phenotypic Ratio:
- Assuming A is dominant (e.g., tall), a is recessive (short):
- Dominant (A_) = AA + Aa = 3
- Recessive (aa) = 1
→ 3:1

✔ Answer:
- Genotypic: 1 AA : 2 Aa : 1 aa
- Phenotypic: 3 Dominant : 1 Recessive

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#### Cross 2: Aa x aa
- Parental Genotypes: Aa × aa
- Punnett Square:

| | A | a |
|-------|-------|-------|
| a | Aa | aa |
| a | Aa | aa |

- Genotypic Ratio:
- Aa : aa = 2 : 2 = 1:1

- Phenotypic Ratio:
- Aa = Dominant (3) → Wait! Actually:
- Aa = Dominant phenotype → 2
- aa = Recessive → 2
→ 1:1

✔ Answer:
- Genotypic: 1 Aa : 1 aa
- Phenotypic: 1 Dominant : 1 Recessive

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#### Cross 3: BB x Bb
- Parental Genotypes: BB × Bb
- Punnett Square:

| | B | b |
|-------|-------|-------|
| B | BB | Bb |
| B | BB | Bb |

- Genotypic Ratio:
- BB : Bb = 2 : 2 = 1:1

- Phenotypic Ratio:
- All have at least one B → all show dominant trait
→ All Dominant (4:0)

✔ Answer:
- Genotypic: 1 BB : 1 Bb
- Phenotypic: All Dominant (4:0)

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Part 2: Monohybrid Cross Problems

#### Problem 4:
> In pea plants, the tall (T) trait is dominant over the dwarf (t) trait. A homozygous tall plant is crossed with a homozygous dwarf plant. What are the genotypes and phenotypes of the F1 generation?

- Homozygous tall = TT
- Homozygous dwarf = tt
- Cross: TT × tt

Punnett Square:

| | T | T |
|-------|-------|-------|
| t | Tt | Tt |
| t | Tt | Tt |

- All offspring = Tt
- Genotype: All Tt
- Phenotype: All Tall (since T is dominant)

✔ Answer:
- F1 Genotype: All Tt
- F1 Phenotype: All Tall

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#### Problem 5:
> If two of the F1 generations from Question 4 are crossed with one another, what would be the genotypes and phenotypes of the F2 offspring?

- F1 = Tt × Tt
- This is a classic monohybrid cross.

Punnett Square:

| | T | t |
|-------|-------|-------|
| T | TT | Tt |
| t | Tt | tt |

- Genotypic Ratio:
- TT : Tt : tt = 1 : 2 : 1

- Phenotypic Ratio:
- Tall (TT, Tt) = 3
- Dwarf (tt) = 1
→ 3:1

✔ Answer:
- F2 Genotypes: 1 TT : 2 Tt : 1 tt
- F2 Phenotypes: 3 Tall : 1 Dwarf

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✔ Final Answers Summary:

#### Cross 1: Aa × Aa
- Genotypic: 1 AA : 2 Aa : 1 aa
- Phenotypic: 3 Dominant : 1 Recessive

#### Cross 2: Aa × aa
- Genotypic: 1 Aa : 1 aa
- Phenotypic: 1 Dominant : 1 Recessive

#### Cross 3: BB × Bb
- Genotypic: 1 BB : 1 Bb
- Phenotypic: All Dominant

#### Problem 4: TT × tt
- F1 Genotype: All Tt
- F1 Phenotype: All Tall

#### Problem 5: Tt × Tt
- F2 Genotypes: 1 TT : 2 Tt : 1 tt
- F2 Phenotypes: 3 Tall : 1 Dwarf

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