Solving an inequality to find the maximum number of blocks for a pedi-cab ride.

Let's solve the problem step by step and verify the solution.

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Problem Statement:

A ride in a pedi-cab costs $2 per block, and you want to give a $5 tip.
You have at most $19 to spend.
How many blocks can you ride?

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Step 1: Define the variable

Let:
- $ x $ = number of blocks you can ride

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Step 2: Set up the inequality

Cost of riding $ x $ blocks = $ 2x $
Tip = $ 5 $
Total cost = $ 2x + 5 $

You have at most $19, so:

$$
2x + 5 \leq 19
$$

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Step 3: Solve the inequality

Subtract 5 from both sides:

$$
2x \leq 14
$$

Divide both sides by 2:

$$
x \leq 7
$$

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Step 4: Interpret the result

You can ride at most 7 blocks.

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Check the answer:

If $ x = 7 $:
- Ride cost: $ 7 \times 2 = 14 $
- Tip: $ 5 $
- Total: $ 14 + 5 = 19 $ ✔ (within budget)

If $ x = 8 $:
- Ride cost: $ 8 \times 2 = 16 $
- Tip: $ 5 $
- Total: $ 21 $ ✘ (over budget)

So, maximum is 7 blocks.

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✔ Final Answer:

You can ride at most 7 blocks.

The work shown in the image is correct! The solution is properly set up and solved. The red box says "At most 7 blocks" — that's accurate.

✔ Answer: 7 blocks