Problem Analysis:
The task involves understanding blood typing based on genetics and solving inheritance problems using Punnett squares. Blood types are determined by the alleles of the
A and
B genes, which are codominant to each other but dominant over the recessive
O allele. The possible genotypes and phenotypes are as follows:
-
Genotypes:
-
AA or AO: Type A blood
-
BB or BO: Type B blood
-
AB: Type AB blood (codominant)
-
OO: Type O blood
Solution to Each Part:
####
(a) What are the two genotypes possible for a person who has A blood?
-
Type A blood can be produced by two possible genotypes:
-
AA (homozygous dominant)
-
AO (heterozygous)
Answer:
$$
\boxed{AA \text{ or } AO}
$$
---
####
(b) What genotypes does a person with B blood have?
-
Type B blood can be produced by two possible genotypes:
-
BB (homozygous dominant)
-
BO (heterozygous)
Answer:
$$
\boxed{BB \text{ or } BO}
$$
---
####
(c) What genotype does a person with O blood have?
-
Type O blood is produced by only one genotype:
-
OO (homozygous recessive)
Answer:
$$
\boxed{OO}
$$
---
####
(d) What are the two possibilities for a person who has AB blood?
-
Type AB blood is produced by only one genotype due to codominance:
-
AB (heterozygous, with both A and B alleles expressed)
Answer:
$$
\boxed{AB}
$$
---
####
3. A man with type B blood (genotype BB) is married to a woman with type O blood (genotype OO). Show the cross. What proportion of their children will have?
-
Father's genotype:
BB (Type B)
-
Mother's genotype:
OO (Type O)
We use a Punnett square to determine the possible genotypes of their offspring:
| | O | O |
|-----|-----|-----|
|
B | BO | BO |
|
B | BO | BO |
From the Punnett square, all offspring will have the genotype
BO, which corresponds to
Type B blood.
Proportions of children's blood types:
-
100% Type B blood
Answer:
$$
\boxed{\text{100% Type B}}
$$
---
####
4. A woman with type B blood (genotype AB) is married to a type B person (genotype BO). Show the cross. What proportion of their children will have?
-
Mother's genotype:
AB (Type AB)
-
Father's genotype:
BO (Type B)
We use a Punnett square to determine the possible genotypes of their offspring:
| | B | O |
|-----|-----|-----|
|
A | AB | AO |
|
B | BB | BO |
From the Punnett square, the possible genotypes and their corresponding blood types are:
-
AB: Type AB
-
AO: Type A
-
BB: Type B
-
BO: Type B
Now, we calculate the proportions:
-
AB: 25%
-
AO: 25%
-
BB: 25%
-
BO: 25%
Converting these to blood types:
-
Type AB: 25%
-
Type A: 25%
-
Type B: 50% (BB + BO)
Proportions of children's blood types:
-
Type A: 25%
-
Type B: 50%
-
Type AB: 25%
-
Type O: 0%
Answer:
$$
\boxed{\text{Type A: 25%, Type B: 50%, Type AB: 25%, Type O: 0%}}
$$
---
Final Answers:
1.
(a) $\boxed{AA \text{ or } AO}$
2.
(b) $\boxed{BB \text{ or } BO}$
3.
(c) $\boxed{OO}$
4.
(d) $\boxed{AB}$
5.
(3) $\boxed{\text{100% Type B}}$
6.
(4) $\boxed{\text{Type A: 25%, Type B: 50%, Type AB: 25%, Type O: 0%}}$
Parent Tip: Review the logic above to help your child master the concept of multiple alleles worksheet.