2 digit by 2 digit Multiplication Worksheets - 15 Worksheets Library - Free Printable

Let’s solve each problem step by step. These are multiplication and addition puzzles where you fill in the missing numbers to make the math work.

---

Problem 1:

We have:

```
7 0
× 8 6
------
? ?
? ? ?
+ ? ? ?
--------
? ? ? ?
```

Actually, looking at the grid layout, it’s set up like this:

Top row: 7 and 0 → that’s 70
Second row: × 8 and 6 → that’s × 86
Then below, we have a “+” sign on the left, meaning we’re adding partial products.

In standard multiplication:

70 × 86 = ?

But let’s break it down as the grid suggests:

First, multiply 70 × 6 = 420
Then, multiply 70 × 80 = 5600 (since 8 is in the tens place)

Now add them: 420 + 5600 = 6020

But wait — the grid has only 3 rows under the multiplication line? Let me check the structure again.

Looking at the grid for Problem 1:

It’s arranged as:

Row 1: [ ][7][0]
Row 2: [×][ ][8][6]
Row 3: [+][ ][ ][ ]
Row 4: [ ][ ][ ][ ]
Row 5: [ ][ ][ ][ ]

This looks like a lattice or area model? Actually, no — it’s more likely a traditional multiplication setup with partial products.

Wait — perhaps it’s meant to be:

Multiply 70 × 86 using the standard algorithm:

Step 1: 70 × 6 = 420 → write that in the first partial product row
Step 2: 70 × 80 = 5600 → but since 8 is in the tens place, we shift left one position → so write 560 with a zero implied? Or just 560 shifted?

Actually, in standard written multiplication:

70
× 86
----
420 ← 70 × 6
560 ← 70 × 80 (but written as 560, shifted left by one digit)
----
6020

So the grid probably expects:

After “× 8 6”, the next row (with +) should be the first partial product: 420
Then the row below that: 560 (shifted left, so aligned under the 8 and 6?)
Then sum: 6020

But the grid has 4 columns total? Let’s count the boxes.

In Problem 1, the top number is two digits: 7 and 0 → occupies last two columns of top row.
The multiplier is × 8 6 → also two digits, same columns.
Then there’s a “+” in the first column of the third row, and then three empty boxes → so that row is for the first partial product: 3 digits? 420 fits.
Then fourth row: four empty boxes → for second partial product? But 560 is 3 digits. Maybe they want it written as 5600? No.

Wait — perhaps the grid is designed for multiplying two-digit numbers, and the answer goes in the bottom two rows?

Alternative interpretation: This might be an "area model" or "box method".

Let me try that.

For 70 × 86:

Break 70 into 70 and 0? That doesn’t help.

Perhaps it's 7 and 0 as separate digits? Like 7*10 + 0, and 8*10 + 6.

So:

Multiply each part:

7 (tens) × 8 (tens) = 56 → hundreds? Wait.

Standard box method for 70 × 86:

Write 70 as 70 and 0? Not helpful.

Actually, 70 is 7 tens and 0 ones. 86 is 8 tens and 6 ones.

So:

| 70 | 0 |
---------------------
80 | 5600| 0 |
6 | 420 | 0 |

Then add: 5600 + 0 + 420 + 0 = 6020

But the grid doesn't match that.

Looking back at the image description — it says "Name ______" and then four problems, each with a similar grid.

Each grid has:

- Top row: two numbers (e.g., 7 and 0)
- Second row: × and two numbers (e.g., 8 and 6)
- Third row: + and three blanks
- Fourth row: four blanks
- Fifth row: four blanks? No, in the text it shows for problem 1:

"1)
7 0
× 8 6
+
[blank row]"

Actually, from the user's text:

For problem 1:

```
7 0
× 8 6
+
[three blanks in row, then another row of four blanks?]
```

I think I need to interpret it as the standard multiplication algorithm with partial products.

Let me do it properly.

Problem 1: 70 × 86

Step 1: Multiply 70 by 6 (the ones digit of 86):
70 × 6 = 420

Step 2: Multiply 70 by 80 (the tens digit of 86, which is 8 × 10):
70 × 80 = 5600

Step 3: Add the two results:
420 + 5600 = 6020

So the final answer is 6020.

Now, how does this fit in the grid?

The grid likely wants:

- After the "× 8 6", the next line (with "+") is for the first partial product: 420 → so in the three boxes after "+", put 4, 2, 0
- Then the next line is for the second partial product: 5600, but since it's multiplied by tens, it's shifted left, so perhaps write 560 in the first three boxes of the next row, and the last box is for the carry or something? But 5600 is four digits.

Perhaps the grid is expecting:

Row 3 (after +): 420 → so positions: blank, 4, 2, 0? But there are only three blanks after "+" in row 3.

Let's look at the structure described:

For problem 1:

"1)
7 0
× 8 6
+
[row with three blanks?]
[row with four blanks?]"

From the user's input:

"1)
7 0
× 8 6
+
[then a row with three cells? and then a row with four cells?]"

Actually, in the initial description, it's shown as:

For 1):

Top: two cells: 7, 0
Below: ×, then two cells: 8, 6
Then: +, then three cells in that row?
Then a full row of four cells?
Then another full row of four cells?

No, let's read carefully:

User wrote:

"1)
7 0
× 8 6
+
[and then presumably the grid continues]"

But in the text, it's formatted as:

"1)
7 0
× 8 6
+
[blank] [blank] [blank] ?
[blank] [blank] [blank] [blank]"

I think for simplicity, since the instruction is to solve the problem, and the problem is to find the product, I'll calculate each multiplication.

Similarly for others.

Let me do all four problems.

Problem 1: 70 × 86

70 × 86 = ?

Calculate: 70 × 80 = 5600; 70 × 6 = 420; total 5600 + 420 = 6020

Problem 2: 36 × 74

36 × 74

First, 36 × 70 = 2520
36 × 4 = 144
Total: 2520 + 144 = 2664

Or: 36 × 74 = 36 × (70 + 4) = 36×70 + 36×4 = 2520 + 144 = 2664

Problem 3: 78 × 85

78 × 85

78 × 80 = 6240
78 × 5 = 390
Total: 6240 + 390 = 6630

Problem 4: 57 × 10

57 × 10 = 570

That's straightforward.

Now, to confirm:

Problem 1: 70 × 86 = 6020
Problem 2: 36 × 74 = 2664
Problem 3: 78 × 85 = 6630
Problem 4: 57 × 10 = 570

These are the final answers for each problem.

Since the grid might expect the partial products, but the question is to "solve the problem", and given the options, I think providing the final product for each is sufficient.

Moreover, the user didn't specify to fill the grid, just to solve the problem.

So I'll go with that.

Final Answer:
1) 6020
2) 2664
3) 6630
4) 570