Mathematics homework worksheet focusing on multiplication and division word problems.
A mathematics homework worksheet titled "Multiplying and Dividing" with seven word problems involving multiplication and division, featuring illustrations of children with math symbols and a fruit stand.
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Step-by-step solution for: Multiplication and Division Word Problems interactive worksheet ...
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Show Answer Key & Explanations
Step-by-step solution for: Multiplication and Division Word Problems interactive worksheet ...
Let's solve each problem step by step and provide clear explanations.
---
- A week has 7 days.
- So, total distance = $ 11 \text{ km/day} \times 7 \text{ days} $
- $ 11 \times 7 = 77 $
✔ Answer: 77 km
---
- Each bundle needs 6 Yellow Elders.
- For 10 bundles: $ 10 \times 6 = 60 $
- But she only has 50.
Since $ 50 < 60 $, she does not have enough.
✔ Answer: No
---
- Total kits = $ 49 \times 604 $
Let’s calculate:
$$
49 \times 604 = (50 - 1) \times 604 = 50 \times 604 - 1 \times 604
$$
$$
50 \times 604 = 30,200
$$
$$
30,200 - 604 = 29,596
$$
✔ Answer: 29,596 First-aid Kits
---
#### (a) How many passengers can the boat take on one trip if an equal number are placed on each of the five trips?
We divide total passengers by number of trips:
$$
642 \div 5 = 128.4
$$
But we can’t have a fraction of a person. Since it says "equal number", and 642 is not divisible by 5, let's check how many full passengers per trip.
But actually, we assume they distribute as evenly as possible, so:
$$
642 \div 5 = 128 \text{ remainder } 2
$$
So, each trip carries 128 passengers, and 2 trips will carry 1 extra passenger (but since it asks for "how many passengers can the boat take on one trip" assuming equal distribution, we must interpret this carefully).
However, if the same number must be carried each time, then it's impossible to split 642 equally into 5 trips.
But likely, the question assumes that the boat carries the same number each time, and we need to find the maximum number per trip such that all 5 trips are equal.
So:
- $ 642 \div 5 = 128.4 $ → Not whole.
- So maximum equal number per trip is 128, but $ 128 \times 5 = 640 $, which leaves 2 people behind.
But the question says: “if an equal number of passengers are placed on the boat for each of the five trips?”
So we must have equal numbers.
So, the boat can carry 128 passengers per trip, and 2 remain.
But the question is asking: How many passengers can the boat take on one trip?
Assuming the boat can carry up to 128 per trip (since 128 × 5 = 640), and 642 > 640, so maximum equal number per trip is 128.
✔ Answer: 128 passengers
#### (b) How many passengers still remained at Potter’s Cay after the fifth trip?
Total transported: $ 128 \times 5 = 640 $
Remaining: $ 642 - 640 = 2 $
✔ Answer: 2 passengers
---
Total containers = $ 568 \times 48 $
Break it down:
$$
568 \times 48 = 568 \times (50 - 2) = 568 \times 50 - 568 \times 2
$$
$$
568 \times 50 = 28,400
$$
$$
568 \times 2 = 1,136
$$
$$
28,400 - 1,136 = 27,264
$$
✔ Answer: 27,264 containers
---
#### (a) 100 yards of fabric
$ 100 \times 15 = 1,500 $
✔ Answer: 1,500 dollars
#### (b) 1000 yards of fabric
$ 1000 \times 15 = 15,000 $
✔ Answer: 15,000 dollars
---
#### (a) How many crates can he fill?
Divide total bags by capacity per crate:
$$
2,462 \div 9
$$
Do the division:
- $ 9 \times 273 = 2,457 $
- $ 2,462 - 2,457 = 5 $
So, he can fill 273 full crates
✔ Answer: 273 crates
#### (b) How many bags of mangoes will be left over?
Remainder = 5
✔ Answer: 5 bags
---
1. 77 km
2. No
3. 29,596 First-aid kits
4. (a) 128 passengers
(b) 2 passengers
5. 27,264 containers
6. (a) 1,500 dollars
(b) 15,000 dollars
7. (a) 273 crates
(b) 5 bags
---
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---
1. Jason runs 11 km every day. How far will he run in a week?
- A week has 7 days.
- So, total distance = $ 11 \text{ km/day} \times 7 \text{ days} $
- $ 11 \times 7 = 77 $
✔ Answer: 77 km
---
2. Mrs. Smith has 50 Yellow Elders. She wants to make ten bundles of 6. Does she have enough Yellow Elders? Write yes or no.
- Each bundle needs 6 Yellow Elders.
- For 10 bundles: $ 10 \times 6 = 60 $
- But she only has 50.
Since $ 50 < 60 $, she does not have enough.
✔ Answer: No
---
3. Dr. Brennen donated 49 duffle bags of First-aid kits to the Bahamas Red Cross. Each bag contained 604 First-aid kits. How many First-aid kits did the Red Cross receive in all?
- Total kits = $ 49 \times 604 $
Let’s calculate:
$$
49 \times 604 = (50 - 1) \times 604 = 50 \times 604 - 1 \times 604
$$
$$
50 \times 604 = 30,200
$$
$$
30,200 - 604 = 29,596
$$
✔ Answer: 29,596 First-aid Kits
---
4. 642 persons are at Potter’s Cay Dock trying to get from New Providence to the Berry Islands. A boat made 5 trips to the islands to carry the passengers.
#### (a) How many passengers can the boat take on one trip if an equal number are placed on each of the five trips?
We divide total passengers by number of trips:
$$
642 \div 5 = 128.4
$$
But we can’t have a fraction of a person. Since it says "equal number", and 642 is not divisible by 5, let's check how many full passengers per trip.
But actually, we assume they distribute as evenly as possible, so:
$$
642 \div 5 = 128 \text{ remainder } 2
$$
So, each trip carries 128 passengers, and 2 trips will carry 1 extra passenger (but since it asks for "how many passengers can the boat take on one trip" assuming equal distribution, we must interpret this carefully).
However, if the same number must be carried each time, then it's impossible to split 642 equally into 5 trips.
But likely, the question assumes that the boat carries the same number each time, and we need to find the maximum number per trip such that all 5 trips are equal.
So:
- $ 642 \div 5 = 128.4 $ → Not whole.
- So maximum equal number per trip is 128, but $ 128 \times 5 = 640 $, which leaves 2 people behind.
But the question says: “if an equal number of passengers are placed on the boat for each of the five trips?”
So we must have equal numbers.
So, the boat can carry 128 passengers per trip, and 2 remain.
But the question is asking: How many passengers can the boat take on one trip?
Assuming the boat can carry up to 128 per trip (since 128 × 5 = 640), and 642 > 640, so maximum equal number per trip is 128.
✔ Answer: 128 passengers
#### (b) How many passengers still remained at Potter’s Cay after the fifth trip?
Total transported: $ 128 \times 5 = 640 $
Remaining: $ 642 - 640 = 2 $
✔ Answer: 2 passengers
---
5. A truck delivered 568 cases of Clorox Wipes to Solomon’s Super Center yesterday. In each case there was 48 containers of Clorox Wipes. How many containers of Clorox Wipes were there in total?
Total containers = $ 568 \times 48 $
Break it down:
$$
568 \times 48 = 568 \times (50 - 2) = 568 \times 50 - 568 \times 2
$$
$$
568 \times 50 = 28,400
$$
$$
568 \times 2 = 1,136
$$
$$
28,400 - 1,136 = 27,264
$$
✔ Answer: 27,264 containers
---
6. The Androsia factory in Andros sells Androsia fabric for $15 per yard. Calculate how much money will be needed to purchase:
#### (a) 100 yards of fabric
$ 100 \times 15 = 1,500 $
✔ Answer: 1,500 dollars
#### (b) 1000 yards of fabric
$ 1000 \times 15 = 15,000 $
✔ Answer: 15,000 dollars
---
7. Tony has 2,462 bags of mangoes. He packs them into crates that can hold 9 bags.
#### (a) How many crates can he fill?
Divide total bags by capacity per crate:
$$
2,462 \div 9
$$
Do the division:
- $ 9 \times 273 = 2,457 $
- $ 2,462 - 2,457 = 5 $
So, he can fill 273 full crates
✔ Answer: 273 crates
#### (b) How many bags of mangoes will be left over?
Remainder = 5
✔ Answer: 5 bags
---
✔ Final Answers Summary:
1. 77 km
2. No
3. 29,596 First-aid kits
4. (a) 128 passengers
(b) 2 passengers
5. 27,264 containers
6. (a) 1,500 dollars
(b) 15,000 dollars
7. (a) 273 crates
(b) 5 bags
---
Let me know if you'd like this formatted for printing or with steps shown!
Parent Tip: Review the logic above to help your child master the concept of multiplication and division word problems worksheet grade 3.