Let’s solve each problem step by step. We’re multiplying monomials by polynomials — that means we use the
distributive property: multiply the monomial outside the parentheses by *each term* inside the parentheses.
---
Problem 1:
2x (6x⁴ + x³)
Multiply 2x by 6x⁴ → 2 × 6 = 12, and x × x⁴ = x⁵ →
12x⁵
Multiply 2x by x³ → 2 × 1 = 2, and x × x³ = x⁴ →
2x⁴
✔ Final:
12x⁵ + 2x⁴
---
Problem 2:
y(7y⁵ + 8y²)
Multiply y by 7y⁵ → 1 × 7 = 7, y × y⁵ = y⁶ →
7y⁶
Multiply y by 8y² → 1 × 8 = 8, y × y² = y³ →
8y³
✔ Final:
7y⁶ + 8y³
---
Problem 3:
(8x³)(4x⁵ – xy + 2x)
Multiply 8x³ by 4x⁵ → 8×4=32, x³×x⁵=x⁸ →
32x⁸
Multiply 8x³ by –xy → 8×(-1)= -8, x³×x = x⁴, times y →
–8x⁴y
Multiply 8x³ by 2x → 8×2=16, x³×x = x⁴ →
16x⁴
✔ Final:
32x⁸ – 8x⁴y + 16x⁴
*(Note: Order doesn’t matter, but usually we write highest degree first or group like terms — here no like terms to combine.)*
---
Problem 4:
–9x³(–2x⁵ + y – 4x)
Multiply –9x³ by –2x⁵ → (-9)×(-2)=18, x³×x⁵=x⁸ →
18x⁸
Multiply –9x³ by y → –9x³y →
–9x³y
Multiply –9x³ by –4x → (-9)×(-4)=36, x³×x = x⁴ →
36x⁴
✔ Final:
18x⁸ – 9x³y + 36x⁴
*(Again, order can vary — sometimes written as 18x⁸ + 36x⁴ – 9x³y)*
---
## YOU TRY Section:
You Try #1:
–3x⁴ (8x⁴ – 2x⁷)
Multiply –3x⁴ by 8x⁴ → (-3)×8 = -24, x⁴×x⁴ = x⁸ →
–24x⁸
Multiply –3x⁴ by –2x⁷ → (-3)×(-2)=6, x⁴×x = x¹¹ →
+6x¹¹
✔ Final:
6x¹¹ – 24x⁸
*(We often write highest exponent first → so 6x¹¹ – 24x⁸ is fine)*
---
You Try #2:
5y²(4x³y + x²y – 2xy³)
Multiply 5y² by 4x³y → 5×4=20, y²×y = y³, keep x³ →
20x³y³
Multiply 5y² by x²y → 5×1=5, y²×y = y³, keep x² →
5x²y³
Multiply 5y² by –2xy³ → 5×(-2)= -10, y²×y³ = y⁵, keep x →
–10xy⁵
✔ Final:
20x³y³ + 5x²y³ – 10xy⁵
---
Final Answer:
Multiplying Monomials by Polynomials:
1. 2x(6x⁴ + x³) =
12x⁵ + 2x⁴
2. y(7y⁵ + 8y²) =
7y⁶ + 8y³
3. (8x³)(4x⁵ – xy + 2x) =
32x⁸ – 8x⁴y + 16x⁴
4. –9x³(–2x⁵ + y – 4x) =
18x⁸ – 9x³y + 36x⁴
You Try:
1. –3x⁴(8x⁴ – 2x⁷) =
6x¹¹ – 24x⁸
2. 5y²(4x³y + x²y – 2xy³) =
20x³y³ + 5x²y³ – 10xy⁵
Parent Tip: Review the logic above to help your child master the concept of multiplication of polynomials worksheet.