Tree Adding Puzzle 3: Solve the number puzzles by filling in the blanks so each number is the sum of the two numbers below it.

Problem Description:

The task involves solving a "Tree Adding Puzzle" where each number in the tree is the sum of the two numbers directly below it. The goal is to fill in the missing numbers in the trees provided, ensuring that the sums are correct.

Given Trees:

1. Completed Example Tree:
- Top: 24
- Second row: 11, 13
- Third row: 5, 6, 7
- Fourth row: 3, 2, 4, 3

2. Tree 1:
- Top: 20
- Second row: Missing
- Third row: Missing
- Fourth row: 3, 2, Missing, Missing

3. Tree 2:
- Top: 25
- Second row: Missing
- Third row: Missing
- Fourth row: 4, Missing, Missing, 3

4. Tree 3:
- Top: 32
- Second row: Missing
- Third row: Missing
- Fourth row: 2, Missing, 5, Missing

Solution Approach:

We will solve each tree step by step, working from the bottom up (since each number is the sum of the two numbers directly below it).

---

#### Tree 1:
- Top: 20
- Fourth row: 3, 2, Missing, Missing

1. Let the fourth row be: \(3, 2, x, y\).
2. The third row will then be:
- First number: \(3 + 2 = 5\)
- Second number: \(2 + x\)
- Third number: \(x + y\)
3. The second row will then be:
- First number: \(5 + (2 + x) = 7 + x\)
- Second number: \((2 + x) + (x + y) = 2 + 2x + y\)
4. The top number is given as 20:
\[
(7 + x) + (2 + 2x + y) = 20
\]
Simplifying:
\[
9 + 3x + y = 20 \implies 3x + y = 11
\]

We can choose values for \(x\) and \(y\) that satisfy this equation. Let's try \(x = 3\) and \(y = 2\):
- Fourth row: \(3, 2, 3, 2\)
- Third row: \(5, 5, 5\)
- Second row: \(10, 10\)

This works because:
- \(10 + 10 = 20\)

So, the completed tree is:
- Fourth row: \(3, 2, 3, 2\)
- Third row: \(5, 5, 5\)
- Second row: \(10, 10\)
- Top: \(20\)

---

#### Tree 2:
- Top: 25
- Fourth row: 4, Missing, Missing, 3

1. Let the fourth row be: \(4, x, y, 3\).
2. The third row will then be:
- First number: \(4 + x\)
- Second number: \(x + y\)
- Third number: \(y + 3\)
3. The second row will then be:
- First number: \((4 + x) + (x + y) = 4 + 2x + y\)
- Second number: \((x + y) + (y + 3) = x + 2y + 3\)
4. The top number is given as 25:
\[
(4 + 2x + y) + (x + 2y + 3) = 25
\]
Simplifying:
\[
7 + 3x + 3y = 25 \implies 3x + 3y = 18 \implies x + y = 6
\]

We can choose values for \(x\) and \(y\) that satisfy this equation. Let's try \(x = 3\) and \(y = 3\):
- Fourth row: \(4, 3, 3, 3\)
- Third row: \(7, 6, 6\)
- Second row: \(13, 12\)

This works because:
- \(13 + 12 = 25\)

So, the completed tree is:
- Fourth row: \(4, 3, 3, 3\)
- Third row: \(7, 6, 6\)
- Second row: \(13, 12\)
- Top: \(25\)

---

#### Tree 3:
- Top: 32
- Fourth row: 2, Missing, 5, Missing

1. Let the fourth row be: \(2, x, 5, y\).
2. The third row will then be:
- First number: \(2 + x\)
- Second number: \(x + 5\)
- Third number: \(5 + y\)
3. The second row will then be:
- First number: \((2 + x) + (x + 5) = 7 + 2x\)
- Second number: \((x + 5) + (5 + y) = x + y + 10\)
4. The top number is given as 32:
\[
(7 + 2x) + (x + y + 10) = 32
\]
Simplifying:
\[
17 + 3x + y = 32 \implies 3x + y = 15
\]

We can choose values for \(x\) and \(y\) that satisfy this equation. Let's try \(x = 4\) and \(y = 3\):
- Fourth row: \(2, 4, 5, 3\)
- Third row: \(6, 9, 8\)
- Second row: \(13, 17\)

This works because:
- \(13 + 17 = 32\)

So, the completed tree is:
- Fourth row: \(2, 4, 5, 3\)
- Third row: \(6, 9, 8\)
- Second row: \(13, 17\)
- Top: \(32\)

---

Final Answer:

\[
\boxed{
\begin{array}{l}
\text{Tree 1:} \\
\text{Fourth row: } 3, 2, 3, 2 \\
\text{Third row: } 5, 5, 5 \\
\text{Second row: } 10, 10 \\
\text{Top: } 20 \\
\\
\text{Tree 2:} \\
\text{Fourth row: } 4, 3, 3, 3 \\
\text{Third row: } 7, 6, 6 \\
\text{Second row: } 13, 12 \\
\text{Top: } 25 \\
\\
\text{Tree 3:} \\
\text{Fourth row: } 2, 4, 5, 3 \\
\text{Third row: } 6, 9, 8 \\
\text{Second row: } 13, 17 \\
\text{Top: } 32 \\
\end{array}
}
\]