Grade 5 Math Word Problems Worksheet #5 - Mixed Practice with real-world applications.
Grade 5 Math Word Problems Worksheet from K5 Learning, featuring six mixed practice word problems involving real-life scenarios like distance, money, geometry, and arithmetic.
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Show Answer Key & Explanations
Step-by-step solution for: 5th grade word problem worksheets - free and printable | Word ...
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Show Answer Key & Explanations
Step-by-step solution for: 5th grade word problem worksheets - free and printable | Word ...
Let's solve each problem step by step from the Grade 5 Math Word Problems Worksheet.
---
Mrs. Hilt traveled 21,120 feet. How many miles did she travel?
Solution:
We know that:
- 1 mile = 5,280 feet
So, to convert feet to miles:
$$
\frac{21,120}{5,280} = 4 \text{ miles}
$$
✔ Answer: Mrs. Hilt traveled 4 miles.
---
Mrs. Hilt collected 1,003 nickels in a jar. She went to the bank to cash them in. How much money did the bank give Mrs. Hilt?
Solution:
- 1 nickel = $0.05
So,
$$
1,003 \times 0.05 = 50.15
$$
✔ Answer: The bank gave her $50.15.
---
Mrs. Hilt owns a house on a lot shaped like a rectangle. The perimeter of the lot is 60 feet. What is the length and the width of the lot?
Solution:
This problem does not provide enough information to find a unique answer because there are many possible rectangles with a perimeter of 60 feet.
The formula for perimeter of a rectangle:
$$
P = 2(L + W)
$$
Given $ P = 60 $:
$$
2(L + W) = 60 \Rightarrow L + W = 30
$$
So any pair of numbers that add up to 30 could be the length and width (e.g., 10 ft and 20 ft, 15 ft and 15 ft, etc.).
But since no additional info (like area or ratio) is given, we cannot determine exact values.
⚠️ Note: This problem might be missing information. If it expects a specific answer, perhaps it assumes a square (equal sides), but it doesn't say so.
Assuming it wants possible dimensions, we can say:
✔ Answer: The length and width could be any two numbers that add to 30 feet. For example, 15 feet by 15 feet (a square), or 10 feet by 20 feet, etc.
---
Mrs. Hilt bought 15 books. She paid $11 for each book. She later sold all 15 books for $25 each. What is the difference between the total amount of money Mrs. Hilt sold the books for and the total amount of money she paid for the books?
Solution:
- Cost price per book = $11
- Number of books = 15
- Total cost = $ 15 \times 11 = 165 $
- Selling price per book = $25
- Total selling price = $ 15 \times 25 = 375 $
Now, find the difference:
$$
375 - 165 = 210
$$
✔ Answer: The difference is $210.
---
Mrs. Hilt earned $25 one week for shoveling snow and $50 for the next week. Then, she gave 2/5 of her earnings to her little sister for helping her. How much money did she give to her little sister?
Solution:
- Total earnings = $25 + $50 = $75
- Fraction given to sister = $ \frac{2}{5} $
- Amount given = $ \frac{2}{5} \times 75 = \frac{2 \times 75}{5} = \frac{150}{5} = 30 $
✔ Answer: She gave $30 to her little sister.
---
Over the weekend, the Philadelphia area received an approximate 26 7/10 inches of snowfall. If a province in Canada received three times as much snowfall, how much would the accumulation in that province be?
Solution:
First, write $ 26 \frac{7}{10} $ as an improper fraction or decimal.
$$
26 \frac{7}{10} = 26.7 \text{ inches}
$$
Now multiply by 3:
$$
26.7 \times 3 = 80.1 \text{ inches}
$$
Convert back to mixed number:
$$
80.1 = 80 \frac{1}{10} \text{ inches}
$$
✔ Answer: The Canadian province received 80 1/10 inches of snowfall.
---
1. 4 miles
2. $50.15
3. Length and width add to 30 feet; e.g., 15 ft × 15 ft
4. $210
5. $30
6. 80 1/10 inches
Let me know if you'd like these explained in simpler terms or with diagrams!
---
Problem 1:
Mrs. Hilt traveled 21,120 feet. How many miles did she travel?
Solution:
We know that:
- 1 mile = 5,280 feet
So, to convert feet to miles:
$$
\frac{21,120}{5,280} = 4 \text{ miles}
$$
✔ Answer: Mrs. Hilt traveled 4 miles.
---
Problem 2:
Mrs. Hilt collected 1,003 nickels in a jar. She went to the bank to cash them in. How much money did the bank give Mrs. Hilt?
Solution:
- 1 nickel = $0.05
So,
$$
1,003 \times 0.05 = 50.15
$$
✔ Answer: The bank gave her $50.15.
---
Problem 3:
Mrs. Hilt owns a house on a lot shaped like a rectangle. The perimeter of the lot is 60 feet. What is the length and the width of the lot?
Solution:
This problem does not provide enough information to find a unique answer because there are many possible rectangles with a perimeter of 60 feet.
The formula for perimeter of a rectangle:
$$
P = 2(L + W)
$$
Given $ P = 60 $:
$$
2(L + W) = 60 \Rightarrow L + W = 30
$$
So any pair of numbers that add up to 30 could be the length and width (e.g., 10 ft and 20 ft, 15 ft and 15 ft, etc.).
But since no additional info (like area or ratio) is given, we cannot determine exact values.
⚠️ Note: This problem might be missing information. If it expects a specific answer, perhaps it assumes a square (equal sides), but it doesn't say so.
Assuming it wants possible dimensions, we can say:
✔ Answer: The length and width could be any two numbers that add to 30 feet. For example, 15 feet by 15 feet (a square), or 10 feet by 20 feet, etc.
---
Problem 4:
Mrs. Hilt bought 15 books. She paid $11 for each book. She later sold all 15 books for $25 each. What is the difference between the total amount of money Mrs. Hilt sold the books for and the total amount of money she paid for the books?
Solution:
- Cost price per book = $11
- Number of books = 15
- Total cost = $ 15 \times 11 = 165 $
- Selling price per book = $25
- Total selling price = $ 15 \times 25 = 375 $
Now, find the difference:
$$
375 - 165 = 210
$$
✔ Answer: The difference is $210.
---
Problem 5:
Mrs. Hilt earned $25 one week for shoveling snow and $50 for the next week. Then, she gave 2/5 of her earnings to her little sister for helping her. How much money did she give to her little sister?
Solution:
- Total earnings = $25 + $50 = $75
- Fraction given to sister = $ \frac{2}{5} $
- Amount given = $ \frac{2}{5} \times 75 = \frac{2 \times 75}{5} = \frac{150}{5} = 30 $
✔ Answer: She gave $30 to her little sister.
---
Problem 6:
Over the weekend, the Philadelphia area received an approximate 26 7/10 inches of snowfall. If a province in Canada received three times as much snowfall, how much would the accumulation in that province be?
Solution:
First, write $ 26 \frac{7}{10} $ as an improper fraction or decimal.
$$
26 \frac{7}{10} = 26.7 \text{ inches}
$$
Now multiply by 3:
$$
26.7 \times 3 = 80.1 \text{ inches}
$$
Convert back to mixed number:
$$
80.1 = 80 \frac{1}{10} \text{ inches}
$$
✔ Answer: The Canadian province received 80 1/10 inches of snowfall.
---
✔ Final Answers Summary:
1. 4 miles
2. $50.15
3. Length and width add to 30 feet; e.g., 15 ft × 15 ft
4. $210
5. $30
6. 80 1/10 inches
Let me know if you'd like these explained in simpler terms or with diagrams!
Parent Tip: Review the logic above to help your child master the concept of multiplication word problems worksheet grade 5.