Let's solve each problem step by step.
---
Problem 1:
Tickets to the movies cost $24 for 1 adult. The price for 1 child was 2/3 of that price. How much did a family with 2 adults and 2 children have to pay?
#### Step-by-Step Solution:
1.
Price for 1 adult: $24.
2.
Price for 1 child:
\[
\text{Price for 1 child} = \frac{2}{3} \times 24 = \frac{2 \times 24}{3} = \frac{48}{3} = 16
\]
So, the price for 1 child is $16.
3.
Total cost for 2 adults:
\[
\text{Cost for 2 adults} = 2 \times 24 = 48
\]
4.
Total cost for 2 children:
\[
\text{Cost for 2 children} = 2 \times 16 = 32
\]
5.
Total cost for the family:
\[
\text{Total cost} = \text{Cost for 2 adults} + \text{Cost for 2 children} = 48 + 32 = 80
\]
#### Final Answer:
\[
\boxed{80}
\]
---
Problem 2:
Mary earned $420 in May and only 5/7 of this in June. How much money did she earn in June?
#### Step-by-Step Solution:
1.
Earnings in May: $420.
2.
Earnings in June:
\[
\text{Earnings in June} = \frac{5}{7} \times 420 = \frac{5 \times 420}{7} = \frac{2100}{7} = 300
\]
#### Final Answer:
\[
\boxed{300}
\]
---
Problem 3:
Sam and Peter loved pizza. Peter ate \(1 \frac{1}{2}\) pizza and Sam ate \(4 \frac{2}{3}\) pizza over a 2-week period. How much pizza did they eat in that time?
#### Step-by-Step Solution:
1.
Convert mixed numbers to improper fractions:
- Peter ate \(1 \frac{1}{2}\):
\[
1 \frac{1}{2} = \frac{2 \times 1 + 1}{2} = \frac{3}{2}
\]
- Sam ate \(4 \frac{2}{3}\):
\[
4 \frac{2}{3} = \frac{3 \times 4 + 2}{3} = \frac{12 + 2}{3} = \frac{14}{3}
\]
2.
Add the amounts of pizza eaten by Peter and Sam:
\[
\text{Total pizza} = \frac{3}{2} + \frac{14}{3}
\]
3.
Find a common denominator (the least common multiple of 2 and 3 is 6):
\[
\frac{3}{2} = \frac{3 \times 3}{2 \times 3} = \frac{9}{6}
\]
\[
\frac{14}{3} = \frac{14 \times 2}{3 \times 2} = \frac{28}{6}
\]
4.
Add the fractions:
\[
\frac{9}{6} + \frac{28}{6} = \frac{9 + 28}{6} = \frac{37}{6}
\]
5.
Convert the improper fraction back to a mixed number:
\[
\frac{37}{6} = 6 \frac{1}{6}
\]
#### Final Answer:
\[
\boxed{6 \frac{1}{6}}
\]
---
Problem 4:
John and Allan started a business. In their first month they made $700. They decided to split the earnings in a ratio of 3:4, with Allan earning slightly more as he had invested more. How much did each of them earn?
#### Step-by-Step Solution:
1.
Total earnings: $700.
2.
Ratio of earnings: 3:4.
3.
Sum of the parts of the ratio:
\[
3 + 4 = 7
\]
4.
Value of one part:
\[
\text{Value of one part} = \frac{700}{7} = 100
\]
5.
John's earnings (3 parts):
\[
\text{John's earnings} = 3 \times 100 = 300
\]
6.
Allan's earnings (4 parts):
\[
\text{Allan's earnings} = 4 \times 100 = 400
\]
#### Final Answer:
\[
\boxed{300 \text{ and } 400}
\]
---
Final Answers:
1. \(\boxed{80}\)
2. \(\boxed{300}\)
3. \(\boxed{6 \frac{1}{6}}\)
4. \(\boxed{300 \text{ and } 400}\)
Parent Tip: Review the logic above to help your child master the concept of multiplication word problems worksheet grade 5.