CBSE Class 4 Maths Multiplication Question Bank - Free Printable

Problem Analysis and Solution

Let's solve the questions step by step.

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#### Question 1: Tick (√) the correct answer

##### Part (a): Which of the following is not equal to 1500?
We need to evaluate each option and check if it equals 1500.

- Option i: \( 3 \times 500 \)
\[
3 \times 500 = 1500
\]
This equals 1500.

- Option ii: \( 300 \times 50 \)
\[
300 \times 50 = 15000
\]
This does not equal 1500.

- Option iii: \( 30 \times 50 \)
\[
30 \times 50 = 1500
\]
This equals 1500.

- Option iv: \( 300 \times 5 \)
\[
300 \times 5 = 1500
\]
This equals 1500.

The correct answer is:
\[
\boxed{\text{ii}}
\]

##### Part (b): The product of all odd numbers between 3 and 8 is
The odd numbers between 3 and 8 are: 3, 5, and 7. We need to find their product.
\[
3 \times 5 \times 7 = 15 \times 7 = 105
\]
The correct answer is:
\[
\boxed{\text{i}}
\]

##### Part (c): \( 636 \times 100 = 636 \times 4 \times \_\_\_\_ \)
We know that:
\[
636 \times 100 = 63600
\]
We also know:
\[
636 \times 4 = 2544
\]
To find the missing number, we divide \( 63600 \) by \( 2544 \):
\[
\frac{63600}{2544} = 25
\]
Thus, the missing number is 25. The correct answer is:
\[
\boxed{\text{iii}}
\]

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#### Question 2: Fill in the blanks

##### Part (a): Multiplicand × Multiplier = \_\_\_\_\_\_
The result of multiplying the multiplicand by the multiplier is called the product.
\[
\boxed{\text{Product}}
\]

##### Part (b): Multiplication is repeated \_\_\_\_\_\_
Multiplication is a shorthand for repeated addition.
\[
\boxed{\text{Addition}}
\]

##### Part (c): On multiplying a number by 0 we always get \_\_\_\_\_\_
Any number multiplied by 0 results in 0.
\[
\boxed{0}
\]

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#### Question 3: Fill in the box

We are given the multiplication problem:
\[
\begin{array}{r}
4 \square 8 \\
\times \quad 8 \\
\hline
3984 \\
\end{array}
\]
We need to find the missing digit in the number \( 4\square8 \).

Let the missing digit be \( x \). Then the number is \( 4x8 \), which can be written as:
\[
400 + 10x + 8 = 408 + 10x
\]
We know that:
\[
(408 + 10x) \times 8 = 3984
\]
Solve for \( x \):
\[
(408 + 10x) \times 8 = 3984
\]
\[
408 \times 8 + 10x \times 8 = 3984
\]
\[
3264 + 80x = 3984
\]
Subtract 3264 from both sides:
\[
80x = 720
\]
Divide by 80:
\[
x = 9
\]
Thus, the missing digit is 9. The complete number is \( 498 \).

The final answer is:
\[
\boxed{9}
\]

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Final Answers:

1. (a) \(\boxed{\text{ii}}\)
(b) \(\boxed{\text{i}}\)
(c) \(\boxed{\text{iii}}\)

2. (a) \(\boxed{\text{Product}}\)
(b) \(\boxed{\text{Addition}}\)
(c) \(\boxed{0}\)

3. \(\boxed{9}\)