4.oa.1 Worksheets | Free - CommonCoreSheets - Free Printable

Let’s go through each problem one by one. The key idea is:
“A is X times as many as B” means A = X × B

So we’re looking for the equation that matches this pattern.

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Problem 1:
“10 is 5 times as many as 2” → That means 10 = 5 × 2
Check options:
A. 5 + 5 = 10 → addition, not multiplication
B. 5 × 5 = 10 → wrong numbers
C. 5 × 2 = 10 → YES! This matches
D. 10 = 2 × 5 → also true (multiplication is commutative), but let’s see what the question wants — it says “best represent”, and C writes it as “5 × 2 = 10” which directly shows “5 times 2 equals 10”. D writes “10 = 2 × 5” which is mathematically correct but reverses the order. Since the phrase is “10 is 5 times as many as 2”, the multiplier is 5, so 5 × 2 = 10 is more direct. But both C and D are mathematically correct. However, in most curriculum contexts, they expect the form where the multiplier comes first: 5 × 2 = 10 → So C

Wait — actually, let’s read carefully: “10 is 5 times as many as 2” → This translates to:
10 = 5 × 2 → which is exactly option D: “10 = 2 × 5”? No — 2 × 5 is same as 5 × 2, but written differently. Option D says “10 = 2 × 5” — that’s still correct numerically, but does it match the wording? The wording says “5 times as many as 2”, meaning you take 2 and multiply by 5 → so 5 × 2. Option C is “5 × 2 = 10” — that’s perfect. Option D is “10 = 2 × 5” — which is equivalent, but the structure is reversed. In teaching, they often prefer the form that mirrors the sentence: “5 times 2 equals 10” → so C is better. But let’s check all problems consistently.

Actually, looking at other problems, like #3: “27 is 9 times as many as 3” → should be 27 = 9 × 3 → option D is “9 × 3 = 27” — which is listed as correct. Similarly, #4: “48 is 6 times as many as 8” → 48 = 6 × 8 → option C is “48 = 8 × 8”? Wait no — let me recheck.

I think I need to solve each carefully.

Let me restart with clear logic:

The phrase:
“X is Y times as many as Z”
means:
X = Y × Z

We want the equation that shows that.

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Problem 1:
“10 is 5 times as many as 2” → 10 = 5 × 2
Options:
A. 5+5=10 → no
B. 5×5=10 → no
C. 5×2=10 → yes, this is 5×2=10 → matches
D. 10=2×5 → also true, but it’s written as 10 = 2×5, which is same value, but the multiplier is written second. Since the phrase says “5 times”, we want 5 to be the first number multiplied. So C is better. But technically both C and D are correct equations. However, in multiple choice, usually only one is intended. Looking at the answer choices, C is “5 × 2 = 10” which directly reflects “5 times 2 equals 10”. D is “10 = 2 × 5” which is “10 equals 2 times 5” — which is a different phrasing. So for consistency with the sentence structure, C is best.

But wait — let’s look at problem 2 to see the pattern.

Problem 2:
“54 is 9 times as many as 6” → 54 = 9 × 6
Options:
A. 6+6=54 → no
B. 54=6×9 → this is 54 = 6×9 → which is true, but again, is it matching “9 times as many as 6”? It should be 9×6.
C. 54=9×9 → no
D. 54=6+9 → no

Option B is “54 = 6 × 9” — which is mathematically correct, but the multiplier is 6, not 9. The phrase says “9 times as many as 6”, so it should be 9 × 6. But none of the options say “54 = 9 × 6”? Let me check again.

Options for #2:
A. 6 + 6 = 54
B. 54 = 6 × 9
C. 54 = 9 × 9
D. 54 = 6 + 9

None say “54 = 9 × 6”. But B says “54 = 6 × 9” — which is the same product. In math, multiplication is commutative, so 6×9 = 9×6. So B is correct numerically. And since the equation is written as “54 = ...”, it matches the “54 is...” part. So probably B is accepted.

This suggests that the format “X = Y × Z” is acceptable even if Y and Z are swapped, as long as the product is correct.

But let’s see problem 3.

Problem 3:
“27 is 9 times as many as 3” → 27 = 9 × 3
Options:
A. 27 = 3 × 3 → no
B. 27 = 9 + 3 → no
C. 3 × 9 = 27 → this is 3×9=27, which is true, but it’s written as 3×9, not 9×3
D. 9 × 3 = 27 → this is exactly 9×3=27 → matches “9 times 3 equals 27”

So here, D is clearly the best because it has the multiplier first: 9 × 3.

Similarly, problem 4:
“48 is 6 times as many as 8” → 48 = 6 × 8
Options:
A. 8 × 6 = 48 → this is 8×6, which is same as 6×8, but multiplier is written second
B. 6 × 8 = 48 → this is 6×8=48 → perfect
C. 48 = 8 × 8 → no
D. 48 = 6 + 6 → no

So B is best.

Ah, so the pattern is: they want the equation where the multiplier (the "times" number) is written first in the multiplication.

So for “X is Y times as many as Z”, they want: Y × Z = X or X = Y × Z, but preferably with Y first.

In problem 1: “10 is 5 times as many as 2” → 5 × 2 = 10 → option C

In problem 2: “54 is 9 times as many as 6” → 9 × 6 = 54, but that’s not an option. Options are:
B. 54 = 6 × 9 → which is 6×9, so multiplier is 6, but the phrase says 9 times. Hmm.

Perhaps they accept any order as long as the numbers are correct.

Let’s list all answers based on standard interpretation.

I recall that in Common Core, when they say “A is B times as many as C”, it means A = B × C, and they often write the equation as B × C = A or A = B × C.

For problem 2, since 9 × 6 = 54, and option B is 54 = 6 × 9, which is equivalent, and it's the only one with the right numbers, so B is correct.

Similarly, for problem 1, both C and D are correct, but C is 5×2=10, D is 10=2×5. Since the sentence starts with "10 is", perhaps D is better because it starts with 10. Let's see the options.

In problem 1, option D is "10 = 2 × 5" — which can be read as "10 is 2 times 5", but the sentence is "10 is 5 times as many as 2", so it should be 5 times 2, not 2 times 5. Although numerically same, conceptually, "5 times as many as 2" means you have 2, and you take 5 groups of it, so 5 × 2.

In education, they emphasize the order to build conceptual understanding.

Looking at problem 3: "27 is 9 times as many as 3" — option D is "9 × 3 = 27" — which is multiplier first.

Problem 4: "48 is 6 times as many as 8" — option B is "6 × 8 = 48" — multiplier first.

Problem 5: "40 is 4 times as many as 10" — should be 4 × 10 = 40 or 40 = 4 × 10
Options:
A. 10 × 4 = 40 — this is 10×4, multiplier is 4, but written second
B. 4 × 4 = 40 — no
C. 4 × 10 = 40 — yes, multiplier first
D. 4 + 10 = 40 — no
So C is best.

Problem 6: "48 is 8 times as many as 6" — 8 × 6 = 48
Options:
A. 48 ÷ 8 × 6 — not an equation
B. 48 = 6 × 8 — this is 6×8, multiplier is 6, but should be 8
C. 48 = 8 × 6 — yes, 8×6=48
D. 6 × 8 = 48 — this is 6×8, same as B but written differently
C is "48 = 8 × 6" — which matches "48 is 8 times 6"
D is "6 × 8 = 48" — which is "6 times 8 equals 48", but the sentence is "48 is 8 times as many as 6", so C is better because it starts with 48 and has 8×6.

In C, it's "48 = 8 × 6" — perfect.

Problem 7: "35 is 5 times as many as 7" — 5 × 7 = 35 or 35 = 5 × 7
Options:
A. 35 = 7 + 5 — no
B. 5 × 7 = 35 — yes
C. 7 × 5 = 35 — also true, but multiplier is 7
D. 35 = 7 + 7 — no
So B is best: 5 × 7 = 35

Problem 8: "12 is 2 times as many as 6" — 2 × 6 = 12 or 12 = 2 × 6
Options:
A. 12 = 6 + 6 — no
B. 6 × 2 = 12 — this is 6×2, multiplier is 6
C. 12 = 2 × 6 — yes, 2×6=12
D. 2 + 6 = 12 — no
So C is best.

Problem 9: "12 is 6 times as many as 2" — 6 × 2 = 12 or 12 = 6 × 2
Options:
A. 12 = 6 × 6 — no
B. 12 = 6 × 2 — yes
C. 12 = 2 × 6 — also true, but multiplier is 2
D. 12 = 6 + 2 — no
So B is best: 12 = 6 × 2

Problem 10: "70 is 10 times as many as 7" — 10 × 7 = 70 or 70 = 10 × 7
Options:
A. 7 × 7 = 70 — no
B. 70 = 10 + 10 — no
C. 10 × 10 = 70 — no
D. 70 = 10 × 7 — yes
So D is best.

Now back to problem 1 and 2.

Problem 1: "10 is 5 times as many as 2" — should be 5 × 2 = 10 or 10 = 5 × 2
Options:
C. 5 × 2 = 10 — good
D. 10 = 2 × 5 — this is 10 = 2×5, which is "10 is 2 times 5", but the sentence is "5 times as many as 2", so it should be 5 times 2. Although 2×5=10, the conceptual meaning is different. In context, C is better.

But let's see what the expected answer is. In many worksheets, they might accept D, but based on the pattern from other problems, for example in problem 9, they have "12 = 6 × 2" for "12 is 6 times as many as 2", so they use the form with the multiplier after the equals sign but still have the multiplier first in the multiplication.

In problem 1, option D is "10 = 2 × 5" — which has the multiplier 2, but it should be 5. So it's incorrect conceptually.

Whereas option C is "5 × 2 = 10" — which is "5 times 2 equals 10", matching "5 times as many as 2".

So for problem 1, C is correct.

For problem 2: "54 is 9 times as many as 6" — should be 9 × 6 = 54 or 54 = 9 × 6
But options don't have that. Option B is "54 = 6 × 9" — which is 6×9, so it's "6 times 9", but the sentence says "9 times as many as 6", so it should be 9 times 6. However, since 6×9=54, and it's the only option with the right numbers, and in some curricula they accept it, but strictly speaking, it's not matching the order.

Let's look at the options again for problem 2:
A. 6 + 6 = 54
B. 54 = 6 × 9
C. 54 = 9 × 9
D. 54 = 6 + 9

Only B has the correct product. And 6×9 is the same as 9×6, so probably B is accepted.

To be consistent, in problem 6, they have "48 = 8 × 6" for "48 is 8 times as many as 6", so they use the form with the multiplier first in the multiplication part.

For problem 2, if they had "54 = 9 × 6", it would be ideal, but they don't. They have "54 = 6 × 9", which is close.

Perhaps in this worksheet, they consider the order of factors less important as long as the equation is correct.

But let's check problem 4: "48 is 6 times as many as 8" — option B is "6 × 8 = 48" — which is multiplier first.

For problem 2, since "9 times as many as 6", it should be 9 × 6, but it's not an option. Option B is 54 = 6 × 9, which is equivalent.

I think for the sake of this, I'll go with the mathematically correct equation that uses the right numbers, and since multiplication is commutative, B is fine for problem 2.

But to match the style, let's see the answer key pattern.

Perhaps I can solve all and then verify.

Let me list my answers:

1. C (5 × 2 = 10)
2. B (54 = 6 × 9) — even though it's 6×9, it's the only correct equation
3. D (9 × 3 = 27)
4. B (6 × 8 = 48)
5. C (4 × 10 = 40)
6. C (48 = 8 × 6) — because "48 is 8 times as many as 6" -> 48 = 8 × 6
7. B (5 × 7 = 35)
8. C (12 = 2 × 6)
9. B (12 = 6 × 2)
10. D (70 = 10 × 7)

For problem 6, option C is "48 = 8 × 6" — yes.

For problem 2, if I choose B, "54 = 6 × 9", it's correct numerically.

But let's double-check problem 2: the sentence is "54 is 9 times as many as 6", which means 54 = 9 * 6. Option B is 54 = 6 * 9, which is the same thing. So it's correct.

Similarly, in problem 1, option D is 10 = 2 * 5, which is 10 = 2*5, but the sentence is "5 times as many as 2", so it should be 5*2, not 2*5. Although equal, the representation is different. In educational context, they might penalize that.

For example, if a student says "2 times 5" for "5 times as many as 2", it shows misunderstanding of the phrase.

So for problem 1, C is better: "5 × 2 = 10" explicitly shows 5 times 2.

For problem 2, since there's no "9 × 6 = 54" or "54 = 9 × 6", only "54 = 6 × 9", and it's the only correct one, we have to choose B.

Perhaps the worksheet expects B for problem 2.

I think I'll go with that.

So final answers:

1. C
2. B
3. D
4. B
5. C
6. C
7. B
8. C
9. B
10. D

Let me write them out.

For problem 6: "48 is 8 times as many as 6" -> 48 = 8 × 6, which is option C.

Yes.

For problem 8: "12 is 2 times as many as 6" -> 12 = 2 × 6, option C.

For problem 9: "12 is 6 times as many as 2" -> 12 = 6 × 2, option B.

All good.

So the answers are:

1. C
2. B
3. D
4. B
5. C
6. C
7. B
8. C
9. B
10. D

Now, to box the final answer as per instruction.

Since the user didn't ask for explanation, and GeneratePractice etc are false, I just need to provide the final answer.

But the instruction says: "Complete ALL reasoning and explanations BEFORE writing the Final Answer." and "If ExplainAnswer is false" — which it is, so I shouldn't have explanation section.

Looking back: "User options: - ExplainAnswer: false - TeachTopic: false - GeneratePractice: false"

And "Response format rules: → Always follow the structure below. → If an option is false, completely omit that section."

So since all are false, I should only have the Final Answer section.

But the instruction also says: "CRITICAL: First work through the problem step by step, check your calculations carefully, and ONLY THEN provide the final answer."

And "Important rules: - Do not describe the image. - Do not mention that the task came from an image. - Use clear, simple language suitable for a school student. - Avoid academic or professor-style explanations."

But since ExplainAnswer is false, I don't need to write explanation. However, the critical part says to work through step by step before final answer, but in the response, if ExplainAnswer is false, I omit the explanation section.

I think the working through is for me to do internally, and then output only the final answer since no sections are enabled.

But to be safe, perhaps I should include the reasoning in the thought process, and then output only Final Answer.

The response should be only the Final Answer section since all options are false.

But let me confirm the format.

The structure is:

If ExplainAnswer is true: [explanation]

If TeachTopic is true: [teach]

If GeneratePractice is true: [practice]

Final Answer: [answer]

Since all are false, only Final Answer should be present.

And the final answer should be the list of choices for each problem.

So I'll write:

Final Answer:
1. C
2. B
3. D
4. B
5. C
6. C
7. B
8. C
9. B
10. D

But to make sure, let's verify one more time.

Problem 1: "10 is 5 times as many as 2" -> 5 × 2 = 10 -> C

Problem 2: "54 is 9 times as many as 6" -> 9 × 6 = 54, but option B is 54 = 6 × 9, which is correct numerically, and it's the only option with 54 and 6 and 9, so B

Problem 3: "27 is 9 times as many as 3" -> 9 × 3 = 27 -> D

Problem 4: "48 is 6 times as many as 8" -> 6 × 8 = 48 -> B

Problem 5: "40 is 4 times as many as 10" -> 4 × 10 = 40 -> C

Problem 6: "48 is 8 times as many as 6" -> 48 = 8 × 6 -> C

Problem 7: "35 is 5 times as many as 7" -> 5 × 7 = 35 -> B

Problem 8: "12 is 2 times as many as 6" -> 12 = 2 × 6 -> C

Problem 9: "12 is 6 times as many as 2" -> 12 = 6 × 2 -> B

Problem 10: "70 is 10 times as many as 7" -> 70 = 10 × 7 -> D

Yes, all seem correct.

So the final answer is as above.