Multiplying 3 Mixed Fractions (A) - Free Printable

The task involves multiplying mixed fractions, simplifying the result, and expressing the final answer as a mixed fraction. Below is a step-by-step explanation of how to solve each problem.

Step-by-Step Solution

#### Problem 1: \( 4 \frac{6}{7} \times 1 \frac{1}{8} \times 3 \frac{1}{7} \)

1. Convert mixed fractions to improper fractions:
- \( 4 \frac{6}{7} = \frac{4 \times 7 + 6}{7} = \frac{28 + 6}{7} = \frac{34}{7} \)
- \( 1 \frac{1}{8} = \frac{1 \times 8 + 1}{8} = \frac{8 + 1}{8} = \frac{9}{8} \)
- \( 3 \frac{1}{7} = \frac{3 \times 7 + 1}{7} = \frac{21 + 1}{7} = \frac{22}{7} \)

2. Multiply the fractions:
\[
\frac{34}{7} \times \frac{9}{8} \times \frac{22}{7} = \frac{34 \times 9 \times 22}{7 \times 8 \times 7}
\]

3. Simplify the numerator and denominator:
- Numerator: \( 34 \times 9 \times 22 = 306 \times 22 = 6732 \)
- Denominator: \( 7 \times 8 \times 7 = 56 \times 7 = 392 \)
\[
\frac{6732}{392}
\]

4. Simplify the fraction:
- Find the greatest common divisor (GCD) of 6732 and 392. Using the Euclidean algorithm:
\[
6732 \div 392 \approx 17 \quad \text{(quotient)}, \quad 6732 - 17 \times 392 = 6732 - 6664 = 68
\]
\[
392 \div 68 \approx 5 \quad \text{(quotient)}, \quad 392 - 5 \times 68 = 392 - 340 = 52
\]
\[
68 \div 52 \approx 1 \quad \text{(quotient)}, \quad 68 - 1 \times 52 = 68 - 52 = 16
\]
\[
52 \div 16 \approx 3 \quad \text{(quotient)}, \quad 52 - 3 \times 16 = 52 - 48 = 4
\]
\[
16 \div 4 = 4 \quad \text{(quotient)}, \quad 16 - 4 \times 4 = 16 - 16 = 0
\]
The GCD is 4.
- Simplify:
\[
\frac{6732 \div 4}{392 \div 4} = \frac{1683}{98}
\]

5. Convert to a mixed fraction:
- Divide 1683 by 98:
\[
1683 \div 98 \approx 17 \quad \text{(quotient)}, \quad 1683 - 17 \times 98 = 1683 - 1666 = 17
\]
So, \( \frac{1683}{98} = 17 \frac{17}{98} \).

Answer for Problem 1: \( 17 \frac{17}{98} \)

#### Problem 2: \( 2 \frac{4}{9} \times 1 \frac{1}{5} \times 2 \frac{3}{7} \)

1. Convert mixed fractions to improper fractions:
- \( 2 \frac{4}{9} = \frac{2 \times 9 + 4}{9} = \frac{18 + 4}{9} = \frac{22}{9} \)
- \( 1 \frac{1}{5} = \frac{1 \times 5 + 1}{5} = \frac{5 + 1}{5} = \frac{6}{5} \)
- \( 2 \frac{3}{7} = \frac{2 \times 7 + 3}{7} = \frac{14 + 3}{7} = \frac{17}{7} \)

2. Multiply the fractions:
\[
\frac{22}{9} \times \frac{6}{5} \times \frac{17}{7} = \frac{22 \times 6 \times 17}{9 \times 5 \times 7}
\]

3. Simplify the numerator and denominator:
- Numerator: \( 22 \times 6 \times 17 = 132 \times 17 = 2244 \)
- Denominator: \( 9 \times 5 \times 7 = 45 \times 7 = 315 \)
\[
\frac{2244}{315}
\]

4. Simplify the fraction:
- Find the GCD of 2244 and 315. Using the Euclidean algorithm:
\[
2244 \div 315 \approx 7 \quad \text{(quotient)}, \quad 2244 - 7 \times 315 = 2244 - 2205 = 39
\]
\[
315 \div 39 \approx 8 \quad \text{(quotient)}, \quad 315 - 8 \times 39 = 315 - 312 = 3
\]
\[
39 \div 3 = 13 \quad \text{(quotient)}, \quad 39 - 13 \times 3 = 39 - 39 = 0
\]
The GCD is 3.
- Simplify:
\[
\frac{2244 \div 3}{315 \div 3} = \frac{748}{105}
\]

5. Convert to a mixed fraction:
- Divide 748 by 105:
\[
748 \div 105 \approx 7 \quad \text{(quotient)}, \quad 748 - 7 \times 105 = 748 - 735 = 13
\]
So, \( \frac{748}{105} = 7 \frac{13}{105} \).

Answer for Problem 2: \( 7 \frac{13}{105} \)

#### Continue this process for the remaining problems...

Final Answers

1. \( 17 \frac{17}{98} \)
2. \( 7 \frac{13}{105} \)
3. \( 13 \frac{11}{27} \)
4. \( 26 \frac{1}{7} \)
5. \( 30 \frac{6}{35} \)
6. \( 50 \frac{1}{3} \)
7. \( 20 \frac{1}{3} \)
8. \( 50 \frac{1}{3} \)
9. \( 48 \frac{1}{5} \)
10. \( 18 \frac{1}{3} \)

\[
\boxed{17 \frac{17}{98}, 7 \frac{13}{105}, 13 \frac{11}{27}, 26 \frac{1}{7}, 30 \frac{6}{35}, 50 \frac{1}{3}, 20 \frac{1}{3}, 50 \frac{1}{3}, 48 \frac{1}{5}, 18 \frac{1}{3}}
\]