Grade 5 Fractions Worksheet: Practice multiplying fractions by whole numbers with fill-in-the-blank exercises.

Problem: Solve the fraction multiplication problems and fill in the blanks.

The worksheet involves multiplying fractions by whole numbers or finding the missing number to satisfy the given equation. Let's solve each problem step by step.

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#### 1. $\frac{1}{2} \times 4 = \_\_\_$
- Multiply the numerator of the fraction by the whole number:
$$
\frac{1}{2} \times 4 = \frac{1 \times 4}{2} = \frac{4}{2} = 2
$$
- Answer: $2$

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#### 2. $9 \times \frac{2}{3} = \_\_\_$
- Multiply the whole number by the numerator of the fraction, then divide by the denominator:
$$
9 \times \frac{2}{3} = \frac{9 \times 2}{3} = \frac{18}{3} = 6
$$
- Answer: $6$

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#### 3. $\frac{7}{2} \times 8 = \_\_\_$
- Multiply the numerator of the fraction by the whole number, then simplify if possible:
$$
\frac{7}{2} \times 8 = \frac{7 \times 8}{2} = \frac{56}{2} = 28
$$
- Answer: $28$

---

#### 4. $\_\_\_ \times \frac{3}{14} = \frac{3}{2}$
- Let the missing number be $x$. The equation is:
$$
x \times \frac{3}{14} = \frac{3}{2}
$$
- Solve for $x$ by isolating it:
$$
x = \frac{3}{2} \div \frac{3}{14} = \frac{3}{2} \times \frac{14}{3} = \frac{3 \times 14}{2 \times 3} = \frac{42}{6} = 7
$$
- Answer: $7$

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#### 5. $\_\_\_ \times 10 = \frac{2}{3}$
- Let the missing number be $x$. The equation is:
$$
x \times 10 = \frac{2}{3}
$$
- Solve for $x$ by isolating it:
$$
x = \frac{2}{3} \div 10 = \frac{2}{3} \times \frac{1}{10} = \frac{2 \times 1}{3 \times 10} = \frac{2}{30} = \frac{1}{15}
$$
- Answer: $\frac{1}{15}$

---

#### 6. $\_\_\_ \times 5 = \frac{15}{8}$
- Let the missing number be $x$. The equation is:
$$
x \times 5 = \frac{15}{8}
$$
- Solve for $x$ by isolating it:
$$
x = \frac{15}{8} \div 5 = \frac{15}{8} \times \frac{1}{5} = \frac{15 \times 1}{8 \times 5} = \frac{15}{40} = \frac{3}{8}
$$
- Answer: $\frac{3}{8}$

---

#### 7. $\frac{1}{6} \times \_\_\_ = 3$
- Let the missing number be $x$. The equation is:
$$
\frac{1}{6} \times x = 3
$$
- Solve for $x$ by isolating it:
$$
x = 3 \div \frac{1}{6} = 3 \times 6 = 18
$$
- Answer: $18$

---

#### 8. $44 \times \_\_\_ = 4$
- Let the missing number be $x$. The equation is:
$$
44 \times x = 4
$$
- Solve for $x$ by isolating it:
$$
x = 4 \div 44 = \frac{4}{44} = \frac{1}{11}
$$
- Answer: $\frac{1}{11}$

---

#### 9. $12 \times \_\_\_ = \frac{4}{7}$
- Let the missing number be $x$. The equation is:
$$
12 \times x = \frac{4}{7}
$$
- Solve for $x$ by isolating it:
$$
x = \frac{4}{7} \div 12 = \frac{4}{7} \times \frac{1}{12} = \frac{4 \times 1}{7 \times 12} = \frac{4}{84} = \frac{1}{21}
$$
- Answer: $\frac{1}{21}$

---

#### 10. $\_\_\_ \times \frac{7}{6} = 21$
- Let the missing number be $x$. The equation is:
$$
x \times \frac{7}{6} = 21
$$
- Solve for $x$ by isolating it:
$$
x = 21 \div \frac{7}{6} = 21 \times \frac{6}{7} = \frac{21 \times 6}{7} = \frac{126}{7} = 18
$$
- Answer: $18$

---

#### 11. $\_\_\_ \times 24 = 16$
- Let the missing number be $x$. The equation is:
$$
x \times 24 = 16
$$
- Solve for $x$ by isolating it:
$$
x = 16 \div 24 = \frac{16}{24} = \frac{2}{3}
$$
- Answer: $\frac{2}{3}$

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#### 12. $10 \times \_\_\_ = \frac{45}{2}$
- Let the missing number be $x$. The equation is:
$$
10 \times x = \frac{45}{2}
$$
- Solve for $x$ by isolating it:
$$
x = \frac{45}{2} \div 10 = \frac{45}{2} \times \frac{1}{10} = \frac{45 \times 1}{2 \times 10} = \frac{45}{20} = \frac{9}{4}
$$
- Answer: $\frac{9}{4}$

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Final Answers:

$$
\boxed{
\begin{array}{ll}
1. & 2 \\
2. & 6 \\
3. & 28 \\
4. & 7 \\
5. & \frac{1}{15} \\
6. & \frac{3}{8} \\
7. & 18 \\
8. & \frac{1}{11} \\
9. & \frac{1}{21} \\
10. & 18 \\
11. & \frac{2}{3} \\
12. & \frac{9}{4}
\end{array}
}
$$