Fraction multiplication practice worksheet using cross cancelling.

Let’s solve each problem step by step using cross cancellation (also called cross simplifying) before multiplying. This means we look for common factors between any numerator and any denominator — even across the two fractions — and divide them out to make the numbers smaller and easier to multiply.

We’ll go one by one:

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1) $\frac{2}{10} \times \frac{5}{4}$

- 2 and 4 → both divisible by 2 → 2÷2=1, 4÷2=2
- 5 and 10 → both divisible by 5 → 5÷5=1, 10÷5=2

Now it becomes: $\frac{1}{2} \times \frac{1}{2} = \frac{1}{4}$

✔ Answer: $\frac{1}{4}$

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2) $\frac{4}{21} \times \frac{9}{24}$

- 4 and 24 → both divisible by 4 → 4÷4=1, 24÷4=6
- 9 and 21 → both divisible by 3 → 9÷3=3, 21÷3=7

Now: $\frac{1}{7} \times \frac{3}{6}$ → but 3 and 6 can be simplified too → 3÷3=1, 6÷3=2

So: $\frac{1}{7} \times \frac{1}{2} = \frac{1}{14}$

✔ Answer: $\frac{1}{14}$

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3) $\frac{15}{28} \times \frac{4}{3}$

- 15 and 3 → both divisible by 3 → 15÷3=5, 3÷3=1
- 4 and 28 → both divisible by 4 → 4÷4=1, 28÷4=7

Now: $\frac{5}{7} \times \frac{1}{1} = \frac{5}{7}$

✔ Answer: $\frac{5}{7}$

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4) $\frac{15}{63} \times \frac{9}{5}$

- 15 and 5 → both divisible by 5 → 15÷5=3, 5÷5=1
- 9 and 63 → both divisible by 9 → 9÷9=1, 63÷9=7

Now: $\frac{3}{7} \times \frac{1}{1} = \frac{3}{7}$

✔ Answer: $\frac{3}{7}$

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5) $\frac{17}{7} \times \frac{14}{51}$

- 17 and 51 → 51 ÷ 17 = 3 → so 17÷17=1, 51÷17=3
- 14 and 7 → 14 ÷ 7 = 2 → so 14÷7=2, 7÷7=1

Now: $\frac{1}{1} \times \frac{2}{3} = \frac{2}{3}$

✔ Answer: $\frac{2}{3}$

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6) $\frac{4}{15} \times \frac{9}{48}$

- 4 and 48 → both divisible by 4 → 4÷4=1, 48÷4=12
- 9 and 15 → both divisible by 3 → 9÷3=3, 15÷3=5

Now: $\frac{1}{5} \times \frac{3}{12}$ → 3 and 12 divisible by 3 → 3÷3=1, 12÷3=4

So: $\frac{1}{5} \times \frac{1}{4} = \frac{1}{20}$

✔ Answer: $\frac{1}{20}$

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7) $\frac{36}{25} \times \frac{5}{12}$

- 36 and 12 → both divisible by 12 → 36÷12=3, 12÷12=1
- 5 and 25 → both divisible by 5 → 5÷5=1, 25÷5=5

Now: $\frac{3}{5} \times \frac{1}{1} = \frac{3}{5}$

✔ Answer: $\frac{3}{5}$

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8) $\frac{25}{35} \times \frac{7}{15}$

- 25 and 15 → both divisible by 5 → 25÷5=5, 15÷5=3
- 7 and 35 → both divisible by 7 → 7÷7=1, 35÷7=5

Now: $\frac{5}{5} \times \frac{1}{3} = 1 \times \frac{1}{3} = \frac{1}{3}$

Wait — let me double-check:

Original: $\frac{25}{35} \times \frac{7}{15}$

After canceling 25 & 15 by 5 → 5/35 × 7/3? No — better to do:

Actually, 25 and 15 → GCF is 5 → 25÷5=5, 15÷5=3
7 and 35 → GCF is 7 → 7÷7=1, 35÷7=5

So now: $\frac{5}{5} \times \frac{1}{3} = 1 \times \frac{1}{3} = \frac{1}{3}$

Yes, correct.

✔ Answer: $\frac{1}{3}$

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9) $\frac{15}{26} \times \frac{13}{10}$

- 15 and 10 → both divisible by 5 → 15÷5=3, 10÷5=2
- 13 and 26 → 26 ÷ 13 = 2 → 13÷13=1, 26÷13=2

Now: $\frac{3}{2} \times \frac{1}{2} = \frac{3}{4}$

✔ Answer: $\frac{3}{4}$

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10) $\frac{25}{21} \times \frac{7}{15}$

- 25 and 15 → both divisible by 5 → 25÷5=5, 15÷5=3
- 7 and 21 → both divisible by 7 → 7÷7=1, 21÷7=3

Now: $\frac{5}{3} \times \frac{1}{3} = \frac{5}{9}$

✔ Answer: $\frac{5}{9}$

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11) $\frac{40}{77} \times \frac{11}{8}$

- 40 and 8 → both divisible by 8 → 40÷8=5, 8÷8=1
- 11 and 77 → 77 ÷ 11 = 7 → 11÷11=1, 77÷11=7

Now: $\frac{5}{7} \times \frac{1}{1} = \frac{5}{7}$

✔ Answer: $\frac{5}{7}$

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12) $\frac{8}{25} \times \frac{10}{36}$

- 8 and 36 → both divisible by 4 → 8÷4=2, 36÷4=9
- 10 and 25 → both divisible by 5 → 10÷5=2, 25÷5=5

Now: $\frac{2}{5} \times \frac{2}{9} = \frac{4}{45}$

✔ Answer: $\frac{4}{45}$

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13) $\frac{25}{49} \times \frac{7}{15}$

- 25 and 15 → both divisible by 5 → 25÷5=5, 15÷5=3
- 7 and 49 → 49 ÷ 7 = 7 → 7÷7=1, 49÷7=7

Now: $\frac{5}{7} \times \frac{1}{3} = \frac{5}{21}$

✔ Answer: $\frac{5}{21}$

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14) $\frac{50}{55} \times \frac{11}{45}$

- 50 and 45 → both divisible by 5 → 50÷5=10, 45÷5=9
- 11 and 55 → 55 ÷ 11 = 5 → 11÷11=1, 55÷11=5

Now: $\frac{10}{5} \times \frac{1}{9}$ → wait, no:

Wait — original after first step: $\frac{10}{55} \times \frac{11}{9}$? Let's redo carefully.

Better approach:

Start over:

$\frac{50}{55} \times \frac{11}{45}$

Cancel 50 and 45 → GCF 5 → 50÷5=10, 45÷5=9
Cancel 11 and 55 → GCF 11 → 11÷11=1, 55÷11=5

So now: $\frac{10}{5} \times \frac{1}{9}$ → 10/5 = 2 → so 2 × 1/9 = 2/9

Wait — actually, after canceling:

Numerator: 50 → 10, 11 → 1 → total num: 10×1 = 10
Denominator: 55 → 5, 45 → 9 → total den: 5×9 = 45

So $\frac{10}{45}$ → simplify by 5 → 2/9

Yes.

✔ Answer: $\frac{2}{9}$

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15) $\frac{10}{21} \times \frac{6}{15}$

- 10 and 15 → both divisible by 5 → 10÷5=2, 15÷5=3
- 6 and 21 → both divisible by 3 → 6÷3=2, 21÷3=7

Now: $\frac{2}{7} \times \frac{2}{3} = \frac{4}{21}$

✔ Answer: $\frac{4}{21}$

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16) $\frac{30}{55} \times \frac{25}{35}$

First, simplify each fraction or cross-cancel.

Cross-cancel:

- 30 and 35 → both divisible by 5 → 30÷5=6, 35÷5=7
- 25 and 55 → both divisible by 5 → 25÷5=5, 55÷5=11

Now: $\frac{6}{11} \times \frac{5}{7} = \frac{30}{77}$

Check if 30 and 77 have common factors? 30=2×3×5, 77=7×11 → no common factors.

✔ Answer: $\frac{30}{77}$

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Final Answers:

1) $\frac{1}{4}$
2) $\frac{1}{14}$
3) $\frac{5}{7}$
4) $\frac{3}{7}$
5) $\frac{2}{3}$
6) $\frac{1}{20}$
7) $\frac{3}{5}$
8) $\frac{1}{3}$
9) $\frac{3}{4}$
10) $\frac{5}{9}$
11) $\frac{5}{7}$
12) $\frac{4}{45}$
13) $\frac{5}{21}$
14) $\frac{2}{9}$
15) $\frac{4}{21}$
16) $\frac{30}{77}$

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Final Answer:
1) $\frac{1}{4}$
2) $\frac{1}{14}$
3) $\frac{5}{7}$
4) $\frac{3}{7}$
5) $\frac{2}{3}$
6) $\frac{1}{20}$
7) $\frac{3}{5}$
8) $\frac{1}{3}$
9) $\frac{3}{4}$
10) $\frac{5}{9}$
11) $\frac{5}{7}$
12) $\frac{4}{45}$
13) $\frac{5}{21}$
14) $\frac{2}{9}$
15) $\frac{4}{21}$
16) $\frac{30}{77}$