Naming Ionic Compounds Practice Worksheet - chemfiesta Naming ... - Free Printable

Let's solve this Naming Ionic Compounds Practice Worksheet step by step.

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Part 1: Name the following ionic compounds

#### Left Column
1) NH₄Cl
- NH₄⁺ is ammonium, Cl⁻ is chloride
→ Ammonium chloride

2) Fe(NO₃)₃
- Fe is iron; it has variable charge. NO₃⁻ is nitrate (1–), so three of them = 3– charge → Fe must be 3+
→ Iron(III) nitrate

3) TiBr₃
- Ti is titanium; Br is bromide (1–), three Br = 3– → Ti is 3+
→ Titanium(III) bromide

4) Cu₃P
- Cu is copper; P is phosphide (3–). Three Cu atoms balance one P³⁻ → each Cu is +1
→ Copper(I) phosphide

5) SnSe₂
- Sn is tin; Se is selenide (2–), two Se = 4– → Sn must be 4+
→ Tin(IV) selenide

6) GaAs
- Ga is gallium; As is arsenide (3–). Ga typically forms +3 ion
→ Gallium arsenide

7) Pb(SO₄)₂
- SO₄²⁻ is sulfate; two of them = 4– → Pb must be 4+
→ Lead(IV) sulfate

8) Be(HCO₃)₂
- Be is beryllium (always +2); HCO₃⁻ is bicarbonate
→ Beryllium bicarbonate

9) Mn₂(SO₃)₃
- SO₃²⁻ is sulfite; three of them = 6– → two Mn ions must total +6 → each Mn is +3
→ Manganese(III) sulfite

10) Al(CN)₃
- Al is aluminum (+3); CN⁻ is cyanide
→ Aluminum cyanide

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#### Right Column

1) NaBr
- Na⁺ is sodium, Br⁻ is bromide
→ Sodium bromide

2) Sc(OH)₃
- Sc is scandium; OH⁻ is hydroxide. Three OH⁻ = 3– → Sc is 3+
→ Scandium(III) hydroxide

3) V₂(SO₄)₃
- SO₄²⁻ is sulfate; three of them = 6– → two V ions = +6 → each V is +3
→ Vanadium(III) sulfate

4) NH₄F
- NH₄⁺ is ammonium, F⁻ is fluoride
→ Ammonium fluoride

5) CaCO₃
- Ca²⁺ is calcium, CO₃²⁻ is carbonate
→ Calcium carbonate

6) NiPO₄
- PO₄³⁻ is phosphate; Ni must be +3 to balance
→ Nickel(III) phosphate

7) Li₂SO₃
- Li⁺ is lithium, SO₃²⁻ is sulfite
→ Lithium sulfite

8) Zn₃P₂
- Zn is zinc (+2), P is phosphide (3–).
Total negative charge: 2 × (3–) = 6–
Total positive charge: 3 × (+2) = +6 → balanced
→ Zinc phosphide

9) Sr(C₂H₃O₂)₂
- Sr²⁺ is strontium, C₂H₃O₂⁻ is acetate
→ Strontium acetate

10) Cu₂O
- O²⁻ is oxide; two Cu atoms balance one O²⁻ → each Cu is +1
→ Copper(I) oxide

11) Ag₃PO₄
- Ag⁺ is silver (usually +1), PO₄³⁻ is phosphate
→ Silver phosphate

12) YClO₃
- Y is yttrium (usually +3), ClO₃⁻ is chlorate
→ Yttrium chlorate

13) SnS₂
- S²⁻ is sulfide; two S = 4– → Sn must be +4
→ Tin(IV) sulfide

14) Ti(CN)₄
- CN⁻ is cyanide; four of them = 4– → Ti is +4
→ Titanium(IV) cyanide

15) KMnO₄
- K⁺ is potassium, MnO₄⁻ is permanganate
→ Potassium permanganate

16) Pb₃N₂
- N³⁻ is nitride; two N = 6– → three Pb = +6 → each Pb is +2
→ Lead(II) nitride

17) CoCO₃
- Co is cobalt; CO₃²⁻ is carbonate → Co must be +2
→ Cobalt(II) carbonate

18) CdSO₃
- Cd²⁺ is cadmium, SO₃²⁻ is sulfite
→ Cadmium sulfite

19) Cu(NO₂)₂
- NO₂⁻ is nitrite; two of them = 2– → Cu is +2
→ Copper(II) nitrite

20) Fe(HCO₃)₂
- HCO₃⁻ is bicarbonate; two of them = 2– → Fe is +2
→ Iron(II) bicarbonate

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Part 2: Write the formulas for the following compounds

11) chromium(VI) phosphate
- Cr⁶⁺ and PO₄³⁻
- Balance charges: Cr⁶⁺ and two PO₄³⁻ (total 6–) → Cr(PO₄)₂
→ Cr(PO₄)₂

12) vanadium(IV) carbonate
- V⁴⁺ and CO₃²⁻
- Need two V⁴⁺ (8+) and three CO₃²⁻ (6–)? Wait:
Charge balance: V⁴⁺ and CO₃²⁻ → need 2 V⁴⁺ = +8, 3 CO₃²⁻ = –6 → not balanced
Better: 2 V⁴⁺ = +8, 4 CO₃²⁻ = –8 → V₂(CO₃)₄ → simplify? No, just write as is
Actually: V⁴⁺ and CO₃²⁻ → lowest common multiple: 2×(+4)=+8, 4×(-2)= -8 → V₂(CO₃)₄
But we can write as V₂(CO₃)₄ or simplify to V(CO₃)₂? No — that would be V²⁺
So correct: V₂(CO₃)₄ → but usually written with smallest whole numbers: V₂(CO₃)₄ is acceptable, but often simplified to V(CO₃)₂ only if charge matches.
Let’s check: V⁴⁺ and CO₃²⁻ → formula: V(CO₃)₂ → V⁴⁺ and two CO₃²⁻ = 4– → yes!
→ V(CO₃)₂

13) tin(II) nitrite
- Sn²⁺ and NO₂⁻ → Sn(NO₂)₂
→ Sn(NO₂)₂

14) cobalt(III) oxide
- Co³⁺ and O²⁻ → need 2 Co³⁺ = +6, 3 O²⁻ = –6 → Co₂O₃
→ Co₂O₃

15) titanium(II) acetate
- Ti²⁺ and C₂H₃O₂⁻ → Ti(C₂H₃O₂)₂
→ Ti(C₂H₃O₂)₂

16) vanadium(V) sulfide
- V⁵⁺ and S²⁻ → need 2 V⁵⁺ = +10, 5 S²⁻ = –10 → V₂S₅
→ V₂S₅

17) chromium(III) hydroxide
- Cr³⁺ and OH⁻ → Cr(OH)₃
→ Cr(OH)₃

18) lithium iodide
- Li⁺ and I⁻ → LiI
→ LiI

19) lead(II) nitride
- Pb²⁺ and N³⁻ → need 3 Pb²⁺ = +6, 2 N³⁻ = –6 → Pb₃N₂
→ Pb₃N₂

20) silver bromide
- Ag⁺ and Br⁻ → AgBr
→ AgBr

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✔ Final Answers:

#### Name the following ionic compounds:

Left Column:
1) Ammonium chloride
2) Iron(III) nitrate
3) Titanium(III) bromide
4) Copper(I) phosphide
5) Tin(IV) selenide
6) Gallium arsenide
7) Lead(IV) sulfate
8) Beryllium bicarbonate
9) Manganese(III) sulfite
10) Aluminum cyanide

Right Column:
1) Sodium bromide
2) Scandium(III) hydroxide
3) Vanadium(III) sulfate
4) Ammonium fluoride
5) Calcium carbonate
6) Nickel(III) phosphate
7) Lithium sulfite
8) Zinc phosphide
9) Strontium acetate
10) Copper(I) oxide
11) Silver phosphate
12) Yttrium chlorate
13) Tin(IV) sulfide
14) Titanium(IV) cyanide
15) Potassium permanganate
16) Lead(II) nitride
17) Cobalt(II) carbonate
18) Cadmium sulfite
19) Copper(II) nitrite
20) Iron(II) bicarbonate

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#### Write the formulas:

11) Cr(PO₄)₂
12) V(CO₃)₂
13) Sn(NO₂)₂
14) Co₂O₃
15) Ti(C₂H₃O₂)₂
16) V₂S₅
17) Cr(OH)₃
18) LiI
19) Pb₃N₂
20) AgBr

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✔ All problems solved!

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