08 - Newtons Laws Practice Worksheet | PDF | Acceleration | Force - Free Printable

Part I: Fill in the blanks to state Newton's three laws of motion

#### Newton's 1st Law
- All objects will remain at rest, or will continue to move at a constant velocity in the same direction unless acted upon by an unbalanced force. This property is called inertia.

#### Newton's 2nd Law
- Unbalanced forces cause an object to accelerate. This can be stated mathematically by the formula:
\[
F = m \cdot a
\]
where \( F \) is force, \( m \) is mass, and \( a \) is acceleration.

#### Newton's 3rd Law
- Every action produces an equal and opposite reaction. When one object exerts a force on another object, the second object pushes back with the same amount of force.

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Part II: Use Newton's 2nd Law of motion to solve each problem

We will use the formula \( F = m \cdot a \) to solve these problems. Rearranging the formula as needed:
- \( F = m \cdot a \)
- \( m = \frac{F}{a} \)
- \( a = \frac{F}{m} \)

#### Problem 1:
How much force is needed to accelerate a 66 kg skier at 2 m/s²?

- Given:
- Mass (\( m \)) = 66 kg
- Acceleration (\( a \)) = 2 m/s²
- Formula: \( F = m \cdot a \)
- Calculation:
\[
F = 66 \, \text{kg} \cdot 2 \, \text{m/s}^2 = 132 \, \text{N}
\]

#### Problem 2:
What is the force on a 1,000 kg elevator that is falling freely at 9.8 m/s²?

- Given:
- Mass (\( m \)) = 1,000 kg
- Acceleration (\( a \)) = 9.8 m/s² (due to gravity)
- Formula: \( F = m \cdot a \)
- Calculation:
\[
F = 1,000 \, \text{kg} \cdot 9.8 \, \text{m/s}^2 = 9,800 \, \text{N}
\]

#### Problem 3:
What is the acceleration of a 50 kg object pushed with a force of 500 newtons?

- Given:
- Force (\( F \)) = 500 N
- Mass (\( m \)) = 50 kg
- Formula: \( a = \frac{F}{m} \)
- Calculation:
\[
a = \frac{500 \, \text{N}}{50 \, \text{kg}} = 10 \, \text{m/s}^2
\]

#### Problem 4:
The mass of a large car is 1,000 kg. How much force would be required to accelerate the car at a rate of 3 m/s²?

- Given:
- Mass (\( m \)) = 1,000 kg
- Acceleration (\( a \)) = 3 m/s²
- Formula: \( F = m \cdot a \)
- Calculation:
\[
F = 1,000 \, \text{kg} \cdot 3 \, \text{m/s}^2 = 3,000 \, \text{N}
\]

#### Problem 5:
A 50 kg skater pushed by a friend accelerates at 5 m/s². How much force did the friend apply?

- Given:
- Mass (\( m \)) = 50 kg
- Acceleration (\( a \)) = 5 m/s²
- Formula: \( F = m \cdot a \)
- Calculation:
\[
F = 50 \, \text{kg} \cdot 5 \, \text{m/s}^2 = 250 \, \text{N}
\]

#### Problem 6:
A force of 250 N is applied to an object that accelerates at a rate of 5 m/s². What is the mass of the object?

- Given:
- Force (\( F \)) = 250 N
- Acceleration (\( a \)) = 5 m/s²
- Formula: \( m = \frac{F}{a} \)
- Calculation:
\[
m = \frac{250 \, \text{N}}{5 \, \text{m/s}^2} = 50 \, \text{kg}
\]

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Final Answers:

1. \( \boxed{132 \, \text{N}} \)
2. \( \boxed{9,800 \, \text{N}} \)
3. \( \boxed{10 \, \text{m/s}^2} \)
4. \( \boxed{3,000 \, \text{N}} \)
5. \( \boxed{250 \, \text{N}} \)
6. \( \boxed{50 \, \text{kg}} \)