Newtons 2nd Law Practice Problems by Mrs K Science | TPT - Free Printable

Let's solve each of these Newton's Second Law problems step by step. The formula we'll use is:

$$
F = ma \quad \text{(Force = mass × acceleration)}
$$

We’ll rearrange this formula as needed:
- $ a = \frac{F}{m} $
- $ m = \frac{F}{a} $

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Problem 1:

Which force is required to accelerate a car of 2,000 kg at a rate of 2.00 m/s²?

Given:
- $ m = 2000 \, \text{kg} $
- $ a = 2.00 \, \text{m/s}^2 $

Use:
$$
F = ma = 2000 \times 2.00 = 4000 \, \text{N}
$$

✔ Answer: $ F = 4000 \, \text{N} $

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Problem 2:

A 65 kg bowling ball would require what force to accelerate down an alleyway at a rate of 3 m/s²?

Given:
- $ m = 65 \, \text{kg} $
- $ a = 3 \, \text{m/s}^2 $

$$
F = ma = 65 \times 3 = 195 \, \text{N}
$$

✔ Answer: $ F = 195 \, \text{N} $

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Problem 3:

Tolly has a car that accelerates at 3 m/s². His car has a mass of 1000 kg. How much force does the car produce?

Given:
- $ m = 1000 \, \text{kg} $
- $ a = 3 \, \text{m/s}^2 $

$$
F = ma = 1000 \times 3 = 3000 \, \text{N}
$$

✔ Answer: $ F = 3000 \, \text{N} $

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Problem 4:

What is the mass of a bike which produces a force of 147 N?

Wait — this problem is missing information. We need either acceleration or force and acceleration to find mass.

But looking closely: It says “produces a force of 147 N” — but force depends on both mass and acceleration. Without knowing acceleration, we cannot find mass.

However, if we assume the force is due to gravity, then it might be referring to weight, where:

$$
F = mg \Rightarrow m = \frac{F}{g}
$$

Assuming $ g = 9.8 \, \text{m/s}^2 $:

$$
m = \frac{147}{9.8} = 15 \, \text{kg}
$$

This makes sense — 147 N is likely the weight (gravitational force) of the bike.

✔ Answer: $ m = 15 \, \text{kg} $

*(Note: This assumes the "force" is gravitational weight. If not, the problem is incomplete.)*

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Problem 5:

What is the mass of a truck which produces a force of 14,000 N while accelerating at a rate of 5 m/s²?

Given:
- $ F = 14,000 \, \text{N} $
- $ a = 5 \, \text{m/s}^2 $

Use:
$$
m = \frac{F}{a} = \frac{14,000}{5} = 2800 \, \text{kg}
$$

✔ Answer: $ m = 2800 \, \text{kg} $

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✔ Final Answers:

1. $ F = 4000 \, \text{N} $
2. $ F = 195 \, \text{N} $
3. $ F = 3000 \, \text{N} $
4. $ m = 15 \, \text{kg} $ *(assuming force is weight, i.e., due to gravity)*
5. $ m = 2800 \, \text{kg} $

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