Printable math worksheet for practicing one-step equations with fractions.

Let’s solve each equation one by one. These are all one-step equations with fractions, so we’ll isolate the variable by doing the opposite operation — usually multiplying both sides by the reciprocal of the fraction attached to the variable.

---

1) $\frac{3}{4}a = \frac{1}{4}$

Multiply both sides by the reciprocal of $\frac{3}{4}$, which is $\frac{4}{3}$:

$a = \frac{1}{4} \cdot \frac{4}{3} = \frac{4}{12} = \frac{1}{3}$

✔ $a = \frac{1}{3}$

---

2) $\frac{7}{2} = -\frac{c}{8/7}$ → Wait, this looks like it might be written as:
Actually, looking at the image, it says:
$\frac{7}{2} = -\frac{c}{(8/7)}$ — but that would mean dividing by a fraction. Let me re-read.

Wait — in the image, problem 2 is:
$\frac{7}{2} = -\frac{c}{(8/7)}$? No — actually, looking again, it's likely meant to be:
$\frac{7}{2} = -\left(\frac{8}{7}\right)c$ — because the parentheses around (8/7) suggest it’s multiplied by c.

But let’s check the original image description — user wrote:
“2) $\frac{7}{2} = -\frac{c}{(8/7)}$” — no, wait, in the text you provided, it says:

> 2) $\frac{7}{2} = -\frac{c}{(8/7)}$

That doesn’t make sense dimensionally. Actually, looking back at your initial input, you have:

In the image transcription, for #2:
“2) $\frac{7}{2} = -\frac{c}{(8/7)}$” — but that would be unusual.

Wait — I think there was a formatting issue. In many worksheets, when they write “-c over (8/7)”, they may mean “negative c times 8/7”. But let’s look at the actual structure.

Actually, reviewing your original message:

You wrote:
> 2) $\frac{7}{2} = -\frac{c}{(8/7)}$

But that would mean:
$\frac{7}{2} = -c \div \frac{8}{7} = -c \cdot \frac{7}{8}$

So:
$\frac{7}{2} = -\frac{7}{8}c$

Now multiply both sides by reciprocal of $-\frac{7}{8}$, which is $-\frac{8}{7}$:

$c = \frac{7}{2} \cdot (-\frac{8}{7}) = -\frac{56}{14} = -4$

✔ $c = -4$

But wait — let me double-check. If the equation is $\frac{7}{2} = -\frac{c}{(8/7)}$, then yes, dividing by (8/7) is same as multiplying by 7/8, so:

Right side: $-c \cdot \frac{7}{8}$

So:
$\frac{7}{2} = -\frac{7}{8}c$

Divide both sides by $-\frac{7}{8}$ → multiply by $-\frac{8}{7}$:

$c = \frac{7}{2} \times (-\frac{8}{7}) = -\frac{56}{14} = -4$

Yes.

---

3) $\frac{6}{5} = -\frac{h}{(3/8)}$

Again, this means:
$\frac{6}{5} = -h \div \frac{3}{8} = -h \cdot \frac{8}{3}$

So:
$\frac{6}{5} = -\frac{8}{3}h$

Multiply both sides by reciprocal of $-\frac{8}{3}$ → $-\frac{3}{8}$:

$h = \frac{6}{5} \cdot (-\frac{3}{8}) = -\frac{18}{40} = -\frac{9}{20}$

✔ $h = -\frac{9}{20}$

---

4) $-\frac{2}{9} = -\frac{3}{2}m$

Multiply both sides by reciprocal of $-\frac{3}{2}$ → $-\frac{2}{3}$:

$m = -\frac{2}{9} \cdot (-\frac{2}{3}) = \frac{4}{27}$

✔ $m = \frac{4}{27}$

---

5) $\frac{7}{6} = -\frac{7}{3}p$

Multiply both sides by reciprocal of $-\frac{7}{3}$ → $-\frac{3}{7}$:

$p = \frac{7}{6} \cdot (-\frac{3}{7}) = -\frac{21}{42} = -\frac{1}{2}$

✔ $p = -\frac{1}{2}$

---

6) $\frac{x}{(1/7)} = -\frac{4}{7}$

This means: $x \div \frac{1}{7} = x \cdot 7 = -\frac{4}{7}$

So:
$7x = -\frac{4}{7}$

Divide both sides by 7 → multiply by $\frac{1}{7}$:

$x = -\frac{4}{7} \cdot \frac{1}{7} = -\frac{4}{49}$

✔ $x = -\frac{4}{49}$

---

7) $\frac{n}{(-4/9)} = \frac{10}{9}$

This means: $n \div (-\frac{4}{9}) = n \cdot (-\frac{9}{4}) = \frac{10}{9}$

So:
$-\frac{9}{4}n = \frac{10}{9}$

Multiply both sides by reciprocal of $-\frac{9}{4}$ → $-\frac{4}{9}$:

$n = \frac{10}{9} \cdot (-\frac{4}{9}) = -\frac{40}{81}$

✔ $n = -\frac{40}{81}$

---

8) $\frac{5}{3}g = -\frac{8}{3}$

Multiply both sides by reciprocal of $\frac{5}{3}$ → $\frac{3}{5}$:

$g = -\frac{8}{3} \cdot \frac{3}{5} = -\frac{24}{15} = -\frac{8}{5}$

✔ $g = -\frac{8}{5}$

---

9) $\frac{7}{4} = \frac{1}{8}s$

Multiply both sides by reciprocal of $\frac{1}{8}$ → 8:

$s = \frac{7}{4} \cdot 8 = \frac{56}{4} = 14$

✔ $s = 14$

---

10) $-\frac{9}{5} = -\frac{t}{(-2/3)}$

First, simplify right side:
$-\frac{t}{(-2/3)} = -t \div (-\frac{2}{3}) = -t \cdot (-\frac{3}{2}) = t \cdot \frac{3}{2}$

So equation becomes:
$-\frac{9}{5} = \frac{3}{2}t$

Multiply both sides by reciprocal of $\frac{3}{2}$ → $\frac{2}{3}$:

$t = -\frac{9}{5} \cdot \frac{2}{3} = -\frac{18}{15} = -\frac{6}{5}$

✔ $t = -\frac{6}{5}$

---

Final Answer:
1) $a = \frac{1}{3}$
2) $c = -4$
3) $h = -\frac{9}{20}$
4) $m = \frac{4}{27}$
5) $p = -\frac{1}{2}$
6) $x = -\frac{4}{49}$
7) $n = -\frac{40}{81}$
8) $g = -\frac{8}{5}$
9) $s = 14$
10) $t = -\frac{6}{5}$