Let’s solve each equation one by one. We’ll isolate the variable (get it alone on one side) using inverse operations — that means if something is added, we subtract; if multiplied, we divide, and so on.
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1)
Equation:
> \( d - \frac{5}{2} = 11 \)
To get \( d \) alone, add \( \frac{5}{2} \) to both sides:
\( d = 11 + \frac{5}{2} \)
Convert 11 to a fraction with denominator 2:
\( 11 = \frac{22}{2} \)
So:
\( d = \frac{22}{2} + \frac{5}{2} = \frac{27}{2} \)
✔ Final answer for #1: \( \boxed{\frac{27}{2}} \)
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2)
Equation:
> \( \frac{1}{5}r = -\frac{8}{5} \)
Multiply both sides by 5 to cancel the denominator:
\( r = -\frac{8}{5} \times 5 = -8 \)
✔ Final answer for #2: \( \boxed{-8} \)
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3)
Equation:
> \( \frac{1}{3} + p = -\frac{8}{9} \)
Subtract \( \frac{1}{3} \) from both sides:
\( p = -\frac{8}{9} - \frac{1}{3} \)
Convert \( \frac{1}{3} \) to ninths: \( \frac{1}{3} = \frac{3}{9} \)
So:
\( p = -\frac{8}{9} - \frac{3}{9} = -\frac{11}{9} \)
✔ Final answer for #3: \( \boxed{-\frac{11}{9}} \)
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4)
Equation:
> \( \frac{4}{5} = \frac{c}{\left(\frac{6}{7}\right)} \)
This means: \( \frac{4}{5} = c \div \frac{6}{7} \), which is same as \( \frac{4}{5} = c \times \frac{7}{6} \)
So to solve for \( c \), multiply both sides by reciprocal of \( \frac{7}{6} \), which is \( \frac{6}{7} \):
Wait — actually, let's rewrite clearly:
If \( \frac{4}{5} = \frac{c}{\frac{6}{7}} \), then multiplying both sides by \( \frac{6}{7} \) gives:
\( c = \frac{4}{5} \times \frac{6}{7} = \frac{24}{35} \)
✔ Final answer for #4: \( \boxed{\frac{24}{35}} \)
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5)
Equation:
> \( -12 = -\frac{3}{7}t \)
Divide both sides by \( -\frac{3}{7} \), or multiply by its reciprocal \( -\frac{7}{3} \):
\( t = -12 \times \left(-\frac{7}{3}\right) = \frac{84}{3} = 28 \)
✔ Final answer for #5: \( \boxed{28} \)
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6)
Equation:
> \( \frac{5}{3} = q - \frac{2}{3} \)
Add \( \frac{2}{3} \) to both sides:
\( q = \frac{5}{3} + \frac{2}{3} = \frac{7}{3} \)
✔ Final answer for #6: \( \boxed{\frac{7}{3}} \)
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7)
Equation:
> \( \frac{s}{\left(-\frac{11}{9}\right)} = 9 \)
This means: \( s \div \left(-\frac{11}{9}\right) = 9 \), so multiply both sides by \( -\frac{11}{9} \):
\( s = 9 \times \left(-\frac{11}{9}\right) = -11 \)
✔ Final answer for #7: \( \boxed{-11} \)
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8)
Equation:
> \( a + \frac{3}{4} = \frac{1}{2} \)
Subtract \( \frac{3}{4} \) from both sides:
\( a = \frac{1}{2} - \frac{3}{4} \)
Convert \( \frac{1}{2} \) to fourths: \( \frac{1}{2} = \frac{2}{4} \)
So:
\( a = \frac{2}{4} - \frac{3}{4} = -\frac{1}{4} \)
✔ Final answer for #8: \( \boxed{-\frac{1}{4}} \)
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Final Answer:
1) \( \frac{27}{2} \)
2) \( -8 \)
3) \( -\frac{11}{9} \)
4) \( \frac{24}{35} \)
5) \( 28 \)
6) \( \frac{7}{3} \)
7) \( -11 \)
8) \( -\frac{1}{4} \)
Parent Tip: Review the logic above to help your child master the concept of one step equations fractions worksheet.