Order of Operations Worksheets | Order of Operations Worksheets ... - Free Printable

Let's solve each of the hexadecimal addition and subtraction problems step by step. Hexadecimal (base-16) uses digits 0–9 and letters A–F, where:

- A = 10
- B = 11
- C = 12
- D = 13
- E = 14
- F = 15

We'll perform each operation carefully, keeping in mind borrowing and carrying rules similar to decimal arithmetic but with base 16.

---

1) F40C - 9BFB

Convert to decimal or do column-wise subtraction.

```
F40C
- 9BFB
-------
```

Start from right to left:

- C (12) - B (11) = 1 → write 1
- 0 - F (15): can't do, borrow from left.
- 4 becomes 3, 0 becomes 16 → 16 - 15 = 1
- 3 - B (11): can't do, borrow from F (15)
- F becomes E (14), 3 becomes 13 + 16 = 29 → 29 - 11 = 18 → 18 in hex is 12 → write 2, carry 1
- E (14) - 9 = 5

Wait, let's go more carefully:

Actually, better to align:

```
F 4 0 C
- 9 B F B
--------
```

Column-by-column (right to left):

Rightmost (units place):
- C (12) - B (11) = 1 → write 1

Next (16s place):
- 0 - F (15): need to borrow
- Borrow from 4 → 4 becomes 3, 0 becomes 16
- 16 - 15 = 1 → write 1

Next (256s place):
- 3 - B (11): need to borrow
- Borrow from F → F becomes E, 3 becomes 13 + 16 = 29
- 29 - 11 = 18 → 18 in hex = 12 → write 2, carry 1

Leftmost (4096s place):
- E (14) - 9 = 5 → write 5

So result: 5211

✔ Answer: 5211

---

2) F40C - 749C

```
F40C
- 749C
------
```

Right to left:

- C - C = 0
- 0 - 9: borrow → 0 becomes 16, 4 becomes 3 → 16 - 9 = 7
- 3 - 4: borrow → 3 becomes 19, F becomes E → 19 - 4 = 15 → F
- E - 7 = 7

Result: 7F70

✔ Answer: 7F70

---

3) 749C + BEA5

```
749C
+ BEA5
------
```

Add column by column:

- C (12) + 5 = 17 → 17 = 1×16 + 1 → write 1, carry 1
- 9 + A (10) + 1 = 20 → 20 = 1×16 + 4 → write 4, carry 1
- 4 + E (14) + 1 = 19 → 19 = 1×16 + 3 → write 3, carry 1
- 7 + B (11) + 1 = 19 → 19 = 1×16 + 3 → write 3, carry 1

Final carry: write 1

So result: 13341

✔ Answer: 13341

---

4) E538 - BEA5

```
E538
- BEA5
------
```

Right to left:

- 8 - 5 = 3
- 3 - A (10): borrow → 3 becomes 19, 5 becomes 4 → 19 - 10 = 9
- 4 - E (14): borrow → 4 becomes 20, E becomes D → 20 - 14 = 6
- D - B = 2

Result: 2693

✔ Answer: 2693

---

5) E538 - 589C

```
E538
- 589C
------
```

Start:

- 8 - C (12): can't → borrow → 3 becomes 2, 8 becomes 24 → 24 - 12 = 12 → C
- 2 - 9: borrow → 5 becomes 4, 2 becomes 18 → 18 - 9 = 9
- 4 - 8: borrow → E becomes D, 4 becomes 20 → 20 - 8 = 12 → C
- D - 5 = 8

Result: 8C9C

✔ Answer: 8C9C

---

6) 589C + 9AD4

```
589C
+ 9AD4
------
```

- C (12) + 4 = 16 → 0, carry 1
- 9 + D (13) + 1 = 23 → 23 = 1×16 + 7 → write 7, carry 1
- 8 + A (10) + 1 = 19 → 19 = 1×16 + 3 → write 3, carry 1
- 5 + 9 + 1 = 15 → F

Result: F370

✔ Answer: F370

---

7) C394 - 9AD4

```
C394
- 9AD4
------
```

- 4 - 4 = 0
- 9 - D (13): borrow → 9 becomes 25, 3 becomes 2 → 25 - 13 = 12 → C
- 2 - A (10): borrow → 2 becomes 18, C becomes B → 18 - 10 = 8
- B - 9 = 2

Result: 28C0

✔ Answer: 28C0

---

8) C394 - 4546

```
C394
- 4546
------
```

- 4 - 6: borrow → 9 becomes 8, 4 becomes 1A → 1A - 6 = 14 → E
- 8 - 4 = 4
- 3 - 5: borrow → 3 becomes 19, C becomes B → 19 - 5 = 14 → E
- B - 4 = 7

Result: 7E4E

✔ Answer: 7E4E

---

9) 4546 + 5D21

```
4546
+ 5D21
------
```

- 6 + 1 = 7
- 4 + 2 = 6
- 5 + D (13) = 18 → 18 = 1×16 + 2 → write 2, carry 1
- 4 + 5 + 1 = 10 → A

Result: A267

✔ Answer: A267

---

10) 5D21 - 3C2D

```
5D21
- 3C2D
------
```

- 1 - D (13): borrow → 2 becomes 1, 1 becomes 17 → 17 - 13 = 4
- 1 - 2: borrow → 1 becomes 17, D becomes C → 17 - 2 = 15 → F
- C - C = 0
- 5 - 3 = 2

Result: 20F4

✔ Answer: 20F4

---

11) 6429 - 3C2D

```
6429
- 3C2D
------
```

- 9 - D (13): borrow → 2 becomes 1, 9 becomes 25 → 25 - 13 = 12 → C
- 1 - 2: borrow → 4 becomes 3, 1 becomes 17 → 17 - 2 = 15 → F
- 3 - C (12): borrow → 6 becomes 5, 3 becomes 19 → 19 - 12 = 7
- 5 - 3 = 2

Result: 27FC

✔ Answer: 27FC

---

12) 6429 - 2053

```
6429
- 2053
------
```

- 9 - 3 = 6
- 2 - 5: borrow → 4 becomes 3, 2 becomes 18 → 18 - 5 = 13 → D
- 3 - 0 = 3
- 6 - 2 = 4

Result: 43D6

✔ Answer: 43D6

---

13) 2053 + 5DBE

```
2053
+ 5DBE
------
```

- 3 + E (14) = 17 → 1×16 + 1 → write 1, carry 1
- 5 + B (11) + 1 = 17 → 1×16 + 1 → write 1, carry 1
- 0 + D (13) + 1 = 14 → E
- 2 + 5 = 7

Result: 7E11

✔ Answer: 7E11

---

14) E193 - 5DBE

```
E193
- 5DBE
------
```

- 3 - E (14): borrow → 9 becomes 8, 3 becomes 19 → 19 - 14 = 5
- 8 - B (11): borrow → 1 becomes 0, 8 becomes 24 → 24 - 11 = 13 → D
- 0 - D (13): borrow → E becomes D, 0 becomes 16 → 16 - 13 = 3
- D - 5 = 8

Result: 83D5

✔ Answer: 83D5

---

15) EF88 - E193

```
EF88
- E193
------
```

- 8 - 3 = 5
- 8 - 9: borrow → 8 becomes 18, F becomes E → 18 - 9 = 9
- E - 1 = D
- E - E = 0

Result: 0D95 → remove leading zero → D95

✔ Answer: D95

---

16) EF88 - 88DA

```
EF88
- 88DA
------
```

- 8 - A (10): borrow → 8 becomes 18, F becomes E → 18 - 10 = 8
- E - D = 1
- F - 8 = 7
- E - 8 = 6

Wait — let's do it properly:

```
E F 8 8
- 8 8 D A
---------
```

- 8 - A: borrow → 8 becomes 18, F becomes E → 18 - 10 = 8
- E - D = 1
- F - 8 = 7? Wait: after borrow, F becomes E, so E - 8 = 6?
Wait no: we borrowed from F for the previous digit, so F becomes E, then we subtract 8 from E?

No — actually:

After borrowing for the units column, F is reduced by 1 → becomes E

Now next column:
- 8 (from original) became 18, but now we're at tens place: the digit was 8, but we already used it.

Wait — correct way:

Start from right:

Units: 8 - A → borrow → 8 becomes 18, 8 becomes 7? No — the digit to the left is 8 (in 88), but we are in the second digit.

Better:

Positions:
Thousands: E, F, 8, 8
Minus: 8, 8, D, A

So:

- Units: 8 - A → borrow → 8 becomes 18, F becomes E → 18 - 10 = 8
- Tens: E (after borrow) - D → E = 14, D = 13 → 14 - 13 = 1
- Hundreds: F (but reduced to E) - 8 → E - 8 = 6
- Thousands: E - 8 = 6

But wait — did we borrow from F? Yes, when we borrowed for the units, we reduced F to E.

So:

- Units: 8 → 18 - A = 8
- Tens: 8 → becomes 7? No — the digit is 8, but we borrowed from F (the hundreds digit), so F → E, and the tens digit remains 8, but we didn’t touch it yet.

Wait — confusion.

Let me write it clearly:

```
E F 8 8
- 8 8 D A
---------
```

Step by step:

1. Units: 8 - A → can't → borrow from tens digit (8). So:
- Tens digit 8 becomes 7
- Units becomes 18 → 18 - 10 = 8

2. Tens: 7 - D (13) → can't → borrow from hundreds (F)
- F becomes E
- 7 becomes 23 → 23 - 13 = 10 → A

3. Hundreds: E (after borrow) - 8 → E = 14 → 14 - 8 = 6

4. Thousands: E - 8 = 6

So result: 66A8

✔ Answer: 66A8

---

✔ Final Answers:

| Problem | Answer |
|--------|--------|
| 1) | 5211 |
| 2) | 7F70 |
| 3) | 13341 |
| 4) | 2693 |
| 5) | 8C9C |
| 6) | F370 |
| 7) | 28C0 |
| 8) | 7E4E |
| 9) | A267 |
| 10) | 20F4 |
| 11) | 27FC |
| 12) | 43D6 |
| 13) | 7E11 |
| 14) | 83D5 |
| 15) | D95 |
| 16) | 66A8 |

Let me know if you'd like a verification using decimal conversion!