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Order of Operations Practice Worksheet with six math problems.

A math worksheet titled "ORDER OF OPERATIONS PRACTICE" with six problems involving parentheses, brackets, and mixed operations.

A math worksheet titled "ORDER OF OPERATIONS PRACTICE" with six problems involving parentheses, brackets, and mixed operations.

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Show Answer Key & Explanations Step-by-step solution for: Order of Operations Practice Worksheet | Math = Love
Let's solve each expression step by step using the order of operations (PEMDAS: Parentheses, Exponents, Multiplication and Division from left to right, Addition and Subtraction from left to right).

---

Problem 1:


$$
3 + [(9 \div 3) \cdot 2] + [(2 \cdot 6) \div 3]
$$

Step-by-step:

- First, simplify inside the brackets:
- $9 \div 3 = 3$
- $3 \cdot 2 = 6$
- $2 \cdot 6 = 12$
- $12 \div 3 = 4$

Now substitute:
$$
3 + 6 + 4 = 13
$$

Answer: 13

---

Problem 2:


$$
[(3 + 9) \div (3 \cdot 2)] + [(2 \cdot 6) \div 3]
$$

Step-by-step:

- Simplify inside parentheses:
- $3 + 9 = 12$
- $3 \cdot 2 = 6$
- So, $12 \div 6 = 2$
- $2 \cdot 6 = 12$, then $12 \div 3 = 4$

Now add:
$$
2 + 4 = 6
$$

Answer: 6

---

Problem 3:


$$
(3 + 9) \div [(3 \cdot 2 + 2 \cdot 6) \div 3]
$$

Step-by-step:

- Numerator: $3 + 9 = 12$
- Denominator: Inside the brackets:
- $3 \cdot 2 = 6$
- $2 \cdot 6 = 12$
- $6 + 12 = 18$
- $18 \div 3 = 6$

Now divide:
$$
12 \div 6 = 2
$$

Answer: 2

---

Problem 4:


$$
(3 + 9 \div 3 \cdot 2) + (2 \cdot 6 \div 3)
$$

Step-by-step:

We must follow PEMDAS — do division and multiplication left to right.

#### First part: $3 + 9 \div 3 \cdot 2$
- $9 \div 3 = 3$
- $3 \cdot 2 = 6$
- $3 + 6 = 9$

#### Second part: $2 \cdot 6 \div 3$
- $2 \cdot 6 = 12$
- $12 \div 3 = 4$

Now add:
$$
9 + 4 = 13
$$

Answer: 13

---

Problem 5:


$$
[(3 + 9) \div 3 \cdot 2 + 2] \cdot (6 \div 3)
$$

Step-by-step:

Start with innermost parentheses:

- $3 + 9 = 12$
- Now: $12 \div 3 = 4$
- $4 \cdot 2 = 8$
- $8 + 2 = 10$ → this is the value inside the first bracket

Now second part: $6 \div 3 = 2$

Now multiply:
$$
10 \cdot 2 = 20
$$

Answer: 20

---

Problem 6:


$$
[(3 + 9 \div 3) \cdot 2] + (2 \cdot 6 \div 3)
$$

Step-by-step:

Inside the first bracket:
- $9 \div 3 = 3$
- $3 + 3 = 6$
- $6 \cdot 2 = 12$

Second part:
- $2 \cdot 6 = 12$
- $12 \div 3 = 4$

Now add:
$$
12 + 4 = 16
$$

Answer: 16

---

Final Answers:



| Expression | Answer |
|----------|--------|
| $3 + [(9 \div 3) \cdot 2] + [(2 \cdot 6) \div 3]$ | 13 |
| $[(3 + 9) \div (3 \cdot 2)] + [(2 \cdot 6) \div 3]$ | 6 |
| $(3 + 9) \div [(3 \cdot 2 + 2 \cdot 6) \div 3]$ | 2 |
| $(3 + 9 \div 3 \cdot 2) + (2 \cdot 6 \div 3)$ | 13 |
| $[(3 + 9) \div 3 \cdot 2 + 2] \cdot (6 \div 3)$ | 20 |
| $[(3 + 9 \div 3) \cdot 2] + (2 \cdot 6 \div 3)$ | 16 |

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