5th-grade partial quotients division worksheets with multiple-choice and open-ended problems.

- For problem 1 (Set A2L2): The partial quotients are 10, 2, and 1. Adding them gives 13. The final remainder is 76 - 72 = 4? Wait, let's re-examine the subtraction steps shown: 916 - 600 = 316; 316 - 120 = 196; 196 - 120 = 76. Since 76 is less than 60, we stop. The total quotient is 10 + 2 + 2 = 14, and the remainder is 76. But 76 is greater than 60, so we can take one more 60 out: 76 - 60 = 16. So the quotient becomes 15 and the remainder is 16. Therefore, the answer is 15 R16.
- For problem 3 (Set A2L2): Divide 895 by 80. First, 80 x 10 = 800. Subtract: 895 - 800 = 95. Then, 80 x 1 = 80. Subtract: 95 - 80 = 15. Total quotient: 10 + 1 = 11. Remainder: 15. So, 11 R15.
- For problem 1 (Set B1L1): The partial quotients are 500, 0, and 0. Adding them gives 500. The final remainder is 0. So, the answer is 500.
- For problem 2 (Set B1L1): Divide 7582 by 34. Use partial quotients: 34 x 200 = 6800. Subtract: 7582 - 6800 = 782. 34 x 20 = 680. Subtract: 782 - 680 = 102. 34 x 3 = 102. Subtract: 102 - 102 = 0. Total quotient: 200 + 20 + 3 = 223. No remainder.
- For problem 3 (Set B1L1): Divide 3575 by 25. 25 x 100 = 2500. Subtract: 3575 - 2500 = 1075. 25 x 40 = 1000. Subtract: 1075 - 1000 = 75. 25 x 3 = 75. Subtract: 75 - 75 = 0. Total quotient: 100 + 40 + 3 = 143. No remainder.
- For problem 4 (Set B1L1): Divide 6579 by 43. 43 x 100 = 4300. Subtract: 6579 - 4300 = 2279. 43 x 50 = 2150. Subtract: 2279 - 2150 = 129. 43 x 3 = 129. Subtract: 129 - 129 = 0. Total quotient: 100 + 50 + 3 = 153. No remainder.