Let’s solve each pattern one by one. We’ll count the number of
Squares (S) and
Circles (C) in each step, then find a rule (formula) that tells us how many S and C there are for any step number — we’ll call the step number “n”.
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Pattern 1:
Look at the shapes:
- Step 1: 1 square, 4 circles → S=1, C=4
- Step 2: 2 squares, 6 circles → S=2, C=6
- Step 3: 3 squares, 8 circles → S=3, C=8
We can see:
- Squares = n (just the step number)
- Circles = 2n + 2? Let’s check:
- n=1 → 2(1)+2 = 4 ✔️
- n=2 → 2(2)+2 = 6 ✔️
- n=3 → 2(3)+2 = 8 ✔️
✔ Formula:
S = n
C = 2n + 2
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Pattern 2:
Shapes:
- Step 1: 1 square, 3 circles → S=1, C=3
- Step 2: 2 squares, 5 circles → S=2, C=5
- Step 3: 3 squares, 7 circles → S=3, C=7
Squares = n
Circles: 3, 5, 7 → increases by 2 each time → starts at 3 when n=1 → so C = 2n + 1
Check:
- n=1 → 2(1)+1 = 3 ✔️
- n=2 → 2(2)+1 = 5 ✔️
- n=3 → 2(3)+1 = 7 ✔️
✔ Formula:
S = n
C = 2n + 1
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Pattern 3:
Shapes:
- Step 1: 1 square, 6 circles → S=1, C=6
- Step 2: 2 squares, 8 circles → S=2, C=8
- Step 3: 3 squares, 10 circles → S=3, C=10
Squares = n
Circles: 6, 8, 10 → increases by 2 → starts at 6 → C = 2n + 4
Check:
- n=1 → 2(1)+4 = 6 ✔️
- n=2 → 2(2)+4 = 8 ✔️
- n=3 → 2(3)+4 = 10 ✔️
✔ Formula:
S = n
C = 2n + 4
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Pattern 4:
Shapes:
- Step 1: 4 squares, 4 circles → S=4, C=4
- Step 2: 8 squares, 6 circles → S=8, C=6
- Step 3: 12 squares, 8 circles → S=12, C=8
Squares: 4, 8, 12 → multiples of 4 → S = 4n
Circles: 4, 6, 8 → increases by 2 → starts at 4 → C = 2n + 2
Check:
- n=1 → S=4(1)=4, C=2(1)+2=4 ✔️
- n=2 → S=8, C=6 ✔️
- n=3 → S=12, C=8 ✔️
✔ Formula:
S = 4n
C = 2n + 2
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Final Answer:
Pattern 1:
S = n
C = 2n + 2
Pattern 2:
S = n
C = 2n + 1
Pattern 3:
S = n
C = 2n + 4
Pattern 4:
S = 4n
C = 2n + 2
Parent Tip: Review the logic above to help your child master the concept of pattern rule worksheet grade 7.