Order Of Operations Word Problems - Fill and Sign Printable ... - Free Printable

Problem Analysis:

The task involves solving word problems related to the order of operations and basic arithmetic. Each problem requires writing an expression and solving it step-by-step. Let's solve each problem systematically.

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Problem 1:

Adam has $450. He spends $210 on food. Later he divides all the money into four parts, out of which three parts were distributed among his children, and one part was kept for himself. Then he found $50 on the road. Write the final expression and find the money he has left.

#### Step-by-Step Solution:
1. Initial amount: Adam starts with $450.
2. Spending on food: He spends $210 on food.
\[
450 - 210 = 240
\]
After spending, Adam has $240 left.
3. Dividing the remaining money into four parts:
- Total remaining money = $240.
- Each part = \( \frac{240}{4} = 60 \).
- Adam keeps one part for himself: $60.
- The other three parts are distributed to his children: \( 3 \times 60 = 180 \).
- Money left after distribution = $60 (kept by Adam).
4. Finding $50 on the road:
- Adam finds an additional $50.
- Total money now = \( 60 + 50 = 110 \).

#### Final Expression:
\[
(450 - 210) \div 4 \times 1 + 50
\]

#### Final Answer:
\[
\boxed{110}
\]

---

Problem 2:

You pay $1.00 to buy a package of paper napkins costing $0.44. How much change will you get back? Give the expression also.

#### Step-by-Step Solution:
1. Cost of the napkins: $0.44.
2. Amount paid: $1.00.
3. Change received:
\[
1.00 - 0.44 = 0.56
\]

#### Final Expression:
\[
1.00 - 0.44
\]

#### Final Answer:
\[
\boxed{0.56}
\]

---

Problem 3:

Sam has $1,000 to be distributed among two groups equally. Later, the first part is divided among five children, and the second part is divided among two brothers. Give the expression that represents how the money distribution between two groups was dispersed.

#### Step-by-Step Solution:
1. Total amount: $1,000.
2. Distribution into two equal parts:
- Each part = \( \frac{1000}{2} = 500 \).
- First group (five children): $500.
- Second group (two brothers): $500.
3. Further division:
- For the first group (five children):
\[
\text{Each child gets} = \frac{500}{5} = 100
\]
- For the second group (two brothers):
\[
\text{Each brother gets} = \frac{500}{2} = 250
\]

#### Final Expression:
\[
\left( \frac{1000}{2} \right) \div 5 \quad \text{(for children)}, \quad \left( \frac{1000}{2} \right) \div 2 \quad \text{(for brothers)}
\]

#### Final Answer:
\[
\boxed{\left( \frac{1000}{2} \right) \div 5 \quad \text{and} \quad \left( \frac{1000}{2} \right) \div 2}
\]

---

Problem 4:

Andy had $1,500 and he invested in stock. In one day, his money was doubled. The next day he got a profit of $185 and later lost $238. Write an expression for this and determine his present amount.

#### Step-by-Step Solution:
1. Initial amount: $1,500.
2. Money doubled:
\[
1500 \times 2 = 3000
\]
3. Profit of $185:
\[
3000 + 185 = 3185
\]
4. Loss of $238:
\[
3185 - 238 = 2947
\]

#### Final Expression:
\[
(1500 \times 2) + 185 - 238
\]

#### Final Answer:
\[
\boxed{2947}
\]

---

Problem 5:

Linda bought 3 notebooks for $1.30 each, a box of pencils for $1.50, and a box of pens for $1.70.

#### Step-by-Step Solution:
1. Cost of notebooks:
- Price per notebook = $1.30.
- Number of notebooks = 3.
- Total cost for notebooks = \( 3 \times 1.30 = 3.90 \).
2. Cost of pencils:
- Price per box = $1.50.
- Total cost for pencils = $1.50.
3. Cost of pens:
- Price per box = $1.70.
- Total cost for pens = $1.70.
4. Total cost:
\[
3.90 + 1.50 + 1.70 = 7.10
\]

#### Final Expression:
\[
(3 \times 1.30) + 1.50 + 1.70
\]

#### Final Answer:
\[
\boxed{7.10}
\]

---

Problem 6:

Mel had $35 and went shopping. He bought a pair of trousers for $30 from his bank account. He bought a pair of trainers for $90.00, 2 shirts for $16.00 each, and 2 pairs of socks for $24.00 each. Give the final expression and determine how much money Mel had at the end of the shopping day.

#### Step-by-Step Solution:
1. Initial amount: $35.
2. Cost of trousers: $30.
- Remaining after buying trousers:
\[
35 - 30 = 5
\]
3. Cost of trainers: $90.
- Remaining after buying trainers:
\[
5 - 90 = -85
\]
- Mel owes $85 because he spent more than he had.
4. Cost of shirts:
- Price per shirt = $16.
- Number of shirts = 2.
- Total cost for shirts = \( 2 \times 16 = 32 \).
- Remaining after buying shirts:
\[
-85 - 32 = -117
\]
5. Cost of socks:
- Price per pair of socks = $24.
- Number of pairs = 2.
- Total cost for socks = \( 2 \times 24 = 48 \).
- Remaining after buying socks:
\[
-117 - 48 = -165
\]

#### Final Expression:
\[
35 - 30 - 90 - (2 \times 16) - (2 \times 24)
\]

#### Final Answer:
\[
\boxed{-165}
\]

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Final Answers:

1. \(\boxed{110}\)
2. \(\boxed{0.56}\)
3. \(\boxed{\left( \frac{1000}{2} \right) \div 5 \quad \text{and} \quad \left( \frac{1000}{2} \right) \div 2}\)
4. \(\boxed{2947}\)
5. \(\boxed{7.10}\)
6. \(\boxed{-165}\)