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Math worksheet for practicing the order of operations with multiple expressions.

Order of Operations Practice worksheet with six math problems involving parentheses, brackets, and various arithmetic operations.

Order of Operations Practice worksheet with six math problems involving parentheses, brackets, and various arithmetic operations.

WEBP 981×582 9.6 KB Free · Personal Use
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Show Answer Key & Explanations Step-by-step solution for: Order of Operations Practice Worksheet | Math = Love
Let's solve each expression step by step using the order of operations (PEMDAS: Parentheses, Exponents, Multiplication and Division from left to right, Addition and Subtraction from left to right).

---

Problem 1:


$$
3 + [(9 \div 3) \cdot 2] + [(2 \cdot 6) \div 3]
$$

Step-by-step:

- First, simplify inside the brackets:
- $9 \div 3 = 3$
- $3 \cdot 2 = 6$
- $2 \cdot 6 = 12$
- $12 \div 3 = 4$

Now substitute:
$$
3 + 6 + 4 = 13
$$

Answer: 13

---

Problem 2:


$$
[(3 + 9) \div (3 \cdot 2)] + [(2 \cdot 6) \div 3]
$$

Step-by-step:

- Simplify inside parentheses:
- $3 + 9 = 12$
- $3 \cdot 2 = 6$
- So, $12 \div 6 = 2$
- $2 \cdot 6 = 12$, then $12 \div 3 = 4$

Now add:
$$
2 + 4 = 6
$$

Answer: 6

---

Problem 3:


$$
(3 + 9) \div [(3 \cdot 2 + 2 \cdot 6) \div 3]
$$

Step-by-step:

- Numerator: $3 + 9 = 12$
- Denominator: Inside the brackets:
- $3 \cdot 2 = 6$
- $2 \cdot 6 = 12$
- $6 + 12 = 18$
- $18 \div 3 = 6$

Now divide:
$$
12 \div 6 = 2
$$

Answer: 2

---

Problem 4:


$$
(3 + 9 \div 3 \cdot 2) + (2 \cdot 6 \div 3)
$$

Step-by-step:

We must follow order of operations inside each set of parentheses.

First part: $3 + 9 \div 3 \cdot 2$

- Division and multiplication from left to right:
- $9 \div 3 = 3$
- $3 \cdot 2 = 6$
- Then $3 + 6 = 9$

Second part: $2 \cdot 6 \div 3$

- $2 \cdot 6 = 12$
- $12 \div 3 = 4$

Now add:
$$
9 + 4 = 13
$$

Answer: 13

---

Problem 5:


$$
[(3 + 9) \div 3 \cdot 2 + 2] \cdot (6 \div 3)
$$

Step-by-step:

First, simplify inside the first big bracket:

- $3 + 9 = 12$
- $12 \div 3 = 4$
- $4 \cdot 2 = 8$
- $8 + 2 = 10$

Now second part: $6 \div 3 = 2$

Now multiply:
$$
10 \cdot 2 = 20
$$

Answer: 20

---

Problem 6:


$$
[(3 + 9 \div 3) \cdot 2] + (2 \cdot 6 \div 3)
$$

Step-by-step:

First bracket: $(3 + 9 \div 3) \cdot 2$

- $9 \div 3 = 3$
- $3 + 3 = 6$
- $6 \cdot 2 = 12$

Second part: $2 \cdot 6 \div 3$

- $2 \cdot 6 = 12$
- $12 \div 3 = 4$

Now add:
$$
12 + 4 = 16
$$

Answer: 16

---

Final Answers:



| Expression | Answer |
|----------|--------|
| $3 + [(9 \div 3) \cdot 2] + [(2 \cdot 6) \div 3]$ | 13 |
| $[(3 + 9) \div (3 \cdot 2)] + [(2 \cdot 6) \div 3]$ | 6 |
| $(3 + 9) \div [(3 \cdot 2 + 2 \cdot 6) \div 3]$ | 2 |
| $(3 + 9 \div 3 \cdot 2) + (2 \cdot 6 \div 3)$ | 13 |
| $[(3 + 9) \div 3 \cdot 2 + 2] \cdot (6 \div 3)$ | 20 |
| $[(3 + 9 \div 3) \cdot 2] + (2 \cdot 6 \div 3)$ | 16 |

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Parent Tip: Review the logic above to help your child master the concept of pemdas worksheet pdf.
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