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PEMDAS Rule Worksheet - Free Printable

PEMDAS Rule Worksheet

Educational worksheet: PEMDAS Rule Worksheet. Download and print for classroom or home learning activities.

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Show Answer Key & Explanations Step-by-step solution for: PEMDAS Rule Worksheet
To solve the given problems using the PEMDAS rule (Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right)), let's evaluate each expression step by step.

---

Problem 1: \( 35 \div 7 + 2^2 \)



1. Exponents: \( 2^2 = 4 \)
\[
35 \div 7 + 2^2 = 35 \div 7 + 4
\]

2. Division: \( 35 \div 7 = 5 \)
\[
35 \div 7 + 4 = 5 + 4
\]

3. Addition: \( 5 + 4 = 9 \)

Answer: \( \boxed{9} \)

---

Problem 2: \( 2.5 \times (13 - 5) \)



1. Parentheses: \( 13 - 5 = 8 \)
\[
2.5 \times (13 - 5) = 2.5 \times 8
\]

2. Multiplication: \( 2.5 \times 8 = 20 \)

Answer: \( \boxed{20} \)

---

Problem 3: \( 45 \div (6 + 3) \times 3 - 6 \div 2 \)



1. Parentheses: \( 6 + 3 = 9 \)
\[
45 \div (6 + 3) \times 3 - 6 \div 2 = 45 \div 9 \times 3 - 6 \div 2
\]

2. Division: \( 45 \div 9 = 5 \) and \( 6 \div 2 = 3 \)
\[
45 \div 9 \times 3 - 6 \div 2 = 5 \times 3 - 3
\]

3. Multiplication: \( 5 \times 3 = 15 \)
\[
5 \times 3 - 3 = 15 - 3
\]

4. Subtraction: \( 15 - 3 = 12 \)

Answer: \( \boxed{12} \)

---

Problem 4: \( 48 - 3(16 + 15 \div 5 \times 3 - 2 \times 3) + 8 \)



1. Parentheses: Solve inside the parentheses first.
- Division: \( 15 \div 5 = 3 \)
\[
16 + 15 \div 5 \times 3 - 2 \times 3 = 16 + 3 \times 3 - 2 \times 3
\]
- Multiplication: \( 3 \times 3 = 9 \) and \( 2 \times 3 = 6 \)
\[
16 + 3 \times 3 - 2 \times 3 = 16 + 9 - 6
\]
- Addition and Subtraction: \( 16 + 9 - 6 = 19 \)
\[
16 + 15 \div 5 \times 3 - 2 \times 3 = 19
\]

2. Multiplication: \( 3 \times 19 = 57 \)
\[
48 - 3(16 + 15 \div 5 \times 3 - 2 \times 3) + 8 = 48 - 57 + 8
\]

3. Subtraction and Addition: \( 48 - 57 = -9 \) and \( -9 + 8 = -1 \)
\[
48 - 57 + 8 = -1
\]

Answer: \( \boxed{-1} \)

---

Problem 5: \( 7 + [(25 - 1) \div (3^2 - 3)] - 3 \)



1. Parentheses: Solve inside the parentheses first.
- \( 25 - 1 = 24 \)
- Exponents: \( 3^2 = 9 \)
\[
3^2 - 3 = 9 - 3 = 6
\]
- Division: \( (25 - 1) \div (3^2 - 3) = 24 \div 6 = 4 \)
\[
[(25 - 1) \div (3^2 - 3)] = 4
\]

2. Addition and Subtraction: \( 7 + 4 - 3 \)
\[
7 + 4 - 3 = 11 - 3 = 8
\]

Answer: \( \boxed{8} \)

---

Problem 6: \( (63 \div 7) + 22 \times (9 + 1) \div 11 \)



1. Parentheses: Solve inside the parentheses first.
- \( 63 \div 7 = 9 \)
- \( 9 + 1 = 10 \)
\[
(63 \div 7) + 22 \times (9 + 1) \div 11 = 9 + 22 \times 10 \div 11
\]

2. Multiplication and Division: Perform multiplication and division from left to right.
- \( 22 \times 10 = 220 \)
- \( 220 \div 11 = 20 \)
\[
9 + 22 \times 10 \div 11 = 9 + 20
\]

3. Addition: \( 9 + 20 = 29 \)

Answer: \( \boxed{29} \)

---

Problem 7: \( (146 - 2) \div (3 \times 4) - 15 + 9 \)



1. Parentheses: Solve inside the parentheses first.
- \( 146 - 2 = 144 \)
- \( 3 \times 4 = 12 \)
\[
(146 - 2) \div (3 \times 4) - 15 + 9 = 144 \div 12 - 15 + 9
\]

2. Division: \( 144 \div 12 = 12 \)
\[
144 \div 12 - 15 + 9 = 12 - 15 + 9
\]

3. Subtraction and Addition: \( 12 - 15 = -3 \) and \( -3 + 9 = 6 \)
\[
12 - 15 + 9 = 6
\]

Answer: \( \boxed{6} \)

---

Problem 8: \( 78 \div 13 + (24 - 12) \times 5 \)



1. Parentheses: Solve inside the parentheses first.
- \( 24 - 12 = 12 \)
\[
78 \div 13 + (24 - 12) \times 5 = 78 \div 13 + 12 \times 5
\]

2. Division and Multiplication: Perform division and multiplication from left to right.
- \( 78 \div 13 = 6 \)
- \( 12 \times 5 = 60 \)
\[
78 \div 13 + 12 \times 5 = 6 + 60
\]

3. Addition: \( 6 + 60 = 66 \)

Answer: \( \boxed{66} \)

---

Problem 9: \( (24 + 1) \times 2 \div (13 - 3) - 19 \)



1. Parentheses: Solve inside the parentheses first.
- \( 24 + 1 = 25 \)
- \( 13 - 3 = 10 \)
\[
(24 + 1) \times 2 \div (13 - 3) - 19 = 25 \times 2 \div 10 - 19
\]

2. Multiplication and Division: Perform multiplication and division from left to right.
- \( 25 \times 2 = 50 \)
- \( 50 \div 10 = 5 \)
\[
25 \times 2 \div 10 - 19 = 5 - 19
\]

3. Subtraction: \( 5 - 19 = -14 \)

Answer: \( \boxed{-14} \)

---

Problem 10: \( [12 - 36 \div (4^2 - 4) \div 3 + 2] \times 5 \)



1. Parentheses: Solve inside the parentheses first.
- Exponents: \( 4^2 = 16 \)
\[
4^2 - 4 = 16 - 4 = 12
\]
- Division: \( 36 \div 12 = 3 \)
\[
36 \div (4^2 - 4) = 36 \div 12 = 3
\]
- Further Division: \( 3 \div 3 = 1 \)
\[
36 \div (4^2 - 4) \div 3 = 3 \div 3 = 1
\]
- Subtraction and Addition: \( 12 - 1 + 2 = 11 + 2 = 13 \)
\[
[12 - 36 \div (4^2 - 4) \div 3 + 2] = 13
\]

2. Multiplication: \( 13 \times 5 = 65 \)

Answer: \( \boxed{65} \)

---

Final Answers:


1. \( \boxed{9} \)
2. \( \boxed{20} \)
3. \( \boxed{12} \)
4. \( \boxed{-1} \)
5. \( \boxed{8} \)
6. \( \boxed{29} \)
7. \( \boxed{6} \)
8. \( \boxed{66} \)
9. \( \boxed{-14} \)
10. \( \boxed{65} \)
Parent Tip: Review the logic above to help your child master the concept of pemdas worksheet with answers.
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