Percent of Change Worksheet for Teachers | Perfect for grades 3rd ... - Free Printable

To solve the problems involving percent change, we use the following formulas:

1. Percent Increase:
\[
\text{Percent Increase} = \left( \frac{\text{New Value} - \text{Original Value}}{\text{Original Value}} \right) \times 100
\]

2. Percent Decrease:
\[
\text{Percent Decrease} = \left( \frac{\text{Original Value} - \text{New Value}}{\text{Original Value}} \right) \times 100
\]

Let's solve each problem step by step.

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Problem 1: Price of a pair of shoes

The price of a pair of shoes increased from $50 to $65. What is the percent increase?

- Original Value = $50
- New Value = $65

Using the Percent Increase formula:
\[
\text{Percent Increase} = \left( \frac{65 - 50}{50} \right) \times 100 = \left( \frac{15}{50} \right) \times 100 = 0.3 \times 100 = 30\%
\]

Answer: \( \boxed{30\%} \)

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Problem 2: Car's value

A car's value increased from $15,000 to $18,000. What is the percent increase?

- Original Value = $15,000
- New Value = $18,000

Using the Percent Increase formula:
\[
\text{Percent Increase} = \left( \frac{18,000 - 15,000}{15,000} \right) \times 100 = \left( \frac{3,000}{15,000} \right) \times 100 = 0.2 \times 100 = 20\%
\]

Answer: \( \boxed{20\%} \)

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Problem 3: Temperature decrease

The temperature in a city decreased from 80 degrees Fahrenheit to 68 degrees Fahrenheit. What is the percent decrease?

- Original Value = 80°F
- New Value = 68°F

Using the Percent Decrease formula:
\[
\text{Percent Decrease} = \left( \frac{80 - 68}{80} \right) \times 100 = \left( \frac{12}{80} \right) \times 100 = 0.15 \times 100 = 15\%
\]

Answer: \( \boxed{15\%} \)

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Problem 4: Number of students

The number of students in a school decreased from 500 to 450. What is the percent decrease?

- Original Value = 500
- New Value = 450

Using the Percent Decrease formula:
\[
\text{Percent Decrease} = \left( \frac{500 - 450}{500} \right) \times 100 = \left( \frac{50}{500} \right) \times 100 = 0.1 \times 100 = 10\%
\]

Answer: \( \boxed{10\%} \)

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Problem 5: Population increase

The population of a city increased from 500,000 to 600,000. What is the percent increase?

- Original Value = 500,000
- New Value = 600,000

Using the Percent Increase formula:
\[
\text{Percent Increase} = \left( \frac{600,000 - 500,000}{500,000} \right) \times 100 = \left( \frac{100,000}{500,000} \right) \times 100 = 0.2 \times 100 = 20\%
\]

Answer: \( \boxed{20\%} \)

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Problem 6: Price of a shirt

The price of a shirt decreased from $30 to $25. What is the percent decrease?

- Original Value = $30
- New Value = $25

Using the Percent Decrease formula:
\[
\text{Percent Decrease} = \left( \frac{30 - 25}{30} \right) \times 100 = \left( \frac{5}{30} \right) \times 100 = \frac{500}{30} \approx 16.67\%
\]

Answer: \( \boxed{16.67\%} \)

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Final Answers

1. \( \boxed{30\%} \)
2. \( \boxed{20\%} \)
3. \( \boxed{15\%} \)
4. \( \boxed{10\%} \)
5. \( \boxed{20\%} \)
6. \( \boxed{16.67\%} \)