Grade 4 Maths Resources (4.4 Word Problems Percentages Printable ... - Free Printable

Let's solve each problem step by step.

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Problem 1:

Harris has a bag of 100 balls. 59% of the balls are red. The remaining balls are blue. What is the number of blue balls that Harris has?

#### Solution:
1. Total number of balls: 100
2. Percentage of red balls: 59%
3. Number of red balls:
\[
\text{Number of red balls} = 59\% \times 100 = \frac{59}{100} \times 100 = 59
\]
4. Number of blue balls:
Since the total number of balls is 100, and the rest are blue:
\[
\text{Number of blue balls} = 100 - 59 = 41
\]

#### Final Answer:
\[
\boxed{41}
\]

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Problem 2:

A shopkeeper bought 120 boxes of juice. He sold 30% of the boxes over the weekend. How many boxes of juice did he sell over the weekend?

#### Solution:
1. Total number of boxes: 120
2. Percentage sold: 30%
3. Number of boxes sold:
\[
\text{Number of boxes sold} = 30\% \times 120 = \frac{30}{100} \times 120 = 0.3 \times 120 = 36
\]

#### Final Answer:
\[
\boxed{36}
\]

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Problem 3:

There are 50 students in my class. Only 24 students in the class are taking a math exam.
a) What percentage of students is taking the math exam?
b) What percentage of students is not taking the exam?

#### Solution:
1. Total number of students: 50
2. Number of students taking the exam: 24

##### Part (a): Percentage of students taking the exam
\[
\text{Percentage taking the exam} = \left( \frac{\text{Number of students taking the exam}}{\text{Total number of students}} \right) \times 100
\]
\[
\text{Percentage taking the exam} = \left( \frac{24}{50} \right) \times 100 = 0.48 \times 100 = 48\%
\]

##### Part (b): Percentage of students not taking the exam
- Number of students not taking the exam:
\[
\text{Number of students not taking the exam} = 50 - 24 = 26
\]
- Percentage of students not taking the exam:
\[
\text{Percentage not taking the exam} = \left( \frac{\text{Number of students not taking the exam}}{\text{Total number of students}} \right) \times 100
\]
\[
\text{Percentage not taking the exam} = \left( \frac{26}{50} \right) \times 100 = 0.52 \times 100 = 52\%
\]

#### Final Answers:
a) \(\boxed{48\%}\)
b) \(\boxed{52\%}\)

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Problem 4:

Ahmed had 36 marbles. He lost 18 marbles yesterday while playing. What percentage of marbles is still left with him?

#### Solution:
1. Initial number of marbles: 36
2. Number of marbles lost: 18
3. Number of marbles left:
\[
\text{Number of marbles left} = 36 - 18 = 18
\]
4. Percentage of marbles left:
\[
\text{Percentage left} = \left( \frac{\text{Number of marbles left}}{\text{Initial number of marbles}} \right) \times 100
\]
\[
\text{Percentage left} = \left( \frac{18}{36} \right) \times 100 = 0.5 \times 100 = 50\%
\]

#### Final Answer:
\[
\boxed{50\%}
\]

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Problem 5:

The football team of our school played 25 matches and won 16 games. What is their winning percentage?

#### Solution:
1. Total number of matches played: 25
2. Number of matches won: 16
3. Winning percentage:
\[
\text{Winning percentage} = \left( \frac{\text{Number of matches won}}{\text{Total number of matches played}} \right) \times 100
\]
\[
\text{Winning percentage} = \left( \frac{16}{25} \right) \times 100 = 0.64 \times 100 = 64\%
\]

#### Final Answer:
\[
\boxed{64\%}
\]

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Final Summary of Answers:

1. \(\boxed{41}\)
2. \(\boxed{36}\)
3. a) \(\boxed{48\%}\), b) \(\boxed{52\%}\)
4. \(\boxed{50\%}\)
5. \(\boxed{64\%}\)