Word Problems Worksheets | Dynamically Created Word Problems - Free Printable

Here are the solutions to all 10 word problems, with step-by-step explanations:

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Problem 1:
> 15 of the students in an English class passed an English test. If these students are 75% of all the students in the class, how many students are in this English class? Round your answer to the nearest whole number if necessary.

Solution:
Let total students = \( x \)

We know:
\( 75\% \) of \( x = 15 \)
→ \( 0.75x = 15 \)

Divide both sides by 0.75:
→ \( x = \frac{15}{0.75} = 20 \)

✔ Answer: 20 students

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Problem 2:
> For one Chemistry test, John had to answer 40 questions. Of these 40 questions, John answered 38 of them correctly. What percent did John get on his Chemistry test? Round your answer to the nearest whole number if necessary.

Solution:
Percent correct = \( \frac{\text{correct}}{\text{total}} \times 100 \)

→ \( \frac{38}{40} \times 100 = 0.95 \times 100 = 95\% \)

✔ Answer: 95%

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Problem 3:
> One baseball team played 18 games throughout their entire season. If this baseball team won 50% of those games, then how many games did they win? Round your answer to the nearest whole number if necessary.

Solution:
50% of 18 = \( 0.50 \times 18 = 9 \)

✔ Answer: 9 games

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Problem 4:
> In one particular suburb, there are 30 families that own a boxer. If there are a total of 50 families that own a dog in general, then what percentage of dog owners have a boxer? Round your answer to the nearest whole number if necessary.

Solution:
Percentage = \( \frac{\text{boxer owners}}{\text{total dog owners}} \times 100 \)

→ \( \frac{30}{50} \times 100 = 0.6 \times 100 = 60\% \)

✔ Answer: 60%

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Problem 5:
> At a local department store, slacks have been reduced to $36. This price is at 90% of the original price for slacks. Given this, what was the original price of the slacks? Round your answer to the nearest whole number if necessary.

Solution:
Let original price = \( x \)

We know:
\( 90\% \) of \( x = 36 \)
→ \( 0.90x = 36 \)

Divide both sides by 0.90:
→ \( x = \frac{36}{0.90} = 40 \)

✔ Answer: $40

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Problem 6:
> Peter receives a $30000 salary for working as an administrator. If Peter spends 20% of his salary on expenses each year, then how much money does Peter have to spend on expenses? Round your answer to the nearest whole number if necessary.

Solution:
20% of $30,000 = \( 0.20 \times 30000 = 6000 \)

✔ Answer: $6,000

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Problem 7:
> Joan decided to look at new and used trucks. Joan found a used truck for $12000. A new truck is $24000, so what percent of the price of a new truck does Joan pay for a used truck? Round your answer to the nearest whole number if necessary.

Solution:
Percent = \( \frac{\text{used price}}{\text{new price}} \times 100 \)

→ \( \frac{12000}{24000} \times 100 = 0.5 \times 100 = 50\% \)

✔ Answer: 50%

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Problem 8:
> John went to his local zoo that featured 3 reptile exhibits. If the zoo features 15 exhibits in total, then what percent of the zoo’s exhibits feature reptiles? Round your answer to the nearest whole number if necessary.

Solution:
Percent = \( \frac{3}{15} \times 100 = 0.2 \times 100 = 20\% \)

✔ Answer: 20%

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Problem 9:
> While mining, Keith found a large metal bar that weighed 16 grams. Keith was also able to determine that the bar contained 25% copper. How many grams of copper are in the metal bar? Round your answer to the nearest whole number if necessary.

Solution:
25% of 16 grams = \( 0.25 \times 16 = 4 \) grams

✔ Answer: 4 grams

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Problem 10:
> At a construction job for a gallery, 18 painters were tasked with painting the interior. These painters made up 75% of the painting crew, so how many painters in all worked on this job? Round your answer to the nearest whole number if necessary.

Solution:
Let total painters = \( x \)

We know:
75% of \( x = 18 \)
→ \( 0.75x = 18 \)

Divide both sides by 0.75:
→ \( x = \frac{18}{0.75} = 24 \)

✔ Answer: 24 painters

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✔ Final Answers Summary:

1. 20
2. 95%
3. 9
4. 60%
5. $40
6. $6,000
7. 50%
8. 20%
9. 4 grams
10. 24

All answers are rounded appropriately and verified. Let me know if you’d like to see any problem explained further!